我喜欢这种方法:

this.file <- sys.frame(tail(grep('source',sys.calls()),n=1))$ofile
this.dir <- dirname(this.file)

令人惊讶的是R中没有“$0”类型结构!你可以通过system()调用一个用R编写的bash脚本来实现:

write.table(c("readlink -e $0"), file="scriptpath.sh",col=F, row=F, quote=F)
thisscript <- system("sh scriptpath.sh", intern = TRUE)

然后将scriptpath.sh名称拆分为other。R

splitstr <- rev(strsplit(thisscript, "\\/")[[1]])
otherscript <- paste0(paste(rev(splitstr[2:length(splitstr)]),collapse="/"),"/other.R")

你可以使用commandArgs函数获取Rscript传递给实际R解释器的所有选项，并搜索——file=。如果你的脚本是从路径启动的，或者它是以一个完整的路径启动的，下面的script.name将以'/'开头。否则，它必须是相对于cwd，你可以连接两个路径，以获得完整的路径。

编辑:听起来你只需要上面的script.name，并剥离路径的最后一个组件。我已经删除了不需要的cwd()样本，并清理了主脚本，并张贴了我的其他. r。只需要保存这个脚本和其他脚本。R脚本放到同一个目录下，chmod +x它们，然后运行主脚本。

主要。接待员:

#!/usr/bin/env Rscript
initial.options <- commandArgs(trailingOnly = FALSE)
file.arg.name <- "--file="
script.name <- sub(file.arg.name, "", initial.options[grep(file.arg.name, initial.options)])
script.basename <- dirname(script.name)
other.name <- file.path(script.basename, "other.R")
print(paste("Sourcing",other.name,"from",script.name))
source(other.name)

其他。接待员:

print("hello")

输出:

burner@firefighter:~$ main.R
[1] "Sourcing /home/burner/bin/other.R from /home/burner/bin/main.R"
[1] "hello"
burner@firefighter:~$ bin/main.R
[1] "Sourcing bin/other.R from bin/main.R"
[1] "hello"
burner@firefighter:~$ cd bin
burner@firefighter:~/bin$ main.R
[1] "Sourcing ./other.R from ./main.R"
[1] "hello"

我相信这就是德曼在找的东西。

Steamer25的方法是有效的，但前提是路径中没有空白。在macOS上，至少cmdArgs[match]返回类似/base/some~+~dir~+~带~+~空格/ for /base/some\ dir\带\空格/。

我通过在返回之前用一个简单的空格替换“~+~”来解决这个问题。

thisFile <- function() {
  cmdArgs <- commandArgs(trailingOnly = FALSE)
  needle <- "--file="
  match <- grep(needle, cmdArgs)
  if (length(match) > 0) {
    # Rscript
    path <- cmdArgs[match]
    path <- gsub("\\~\\+\\~", " ", path)
    return(normalizePath(sub(needle, "", path)))
  } else {
    # 'source'd via R console
    return(normalizePath(sys.frames()[[1]]$ofile))
  }
}

显然，你仍然可以像aprstar那样扩展else块。

I would use a variant of @steamer25 's approach. The point is that I prefer to obtain the last sourced script even when my session was started through Rscript. The following snippet, when included on a file, will provided a variable thisScript containing the normalized path of the script. I confess the (ab)use of source'ing, so sometimes I invoke Rscript and the script provided in the --file argument sources another script that sources another one... Someday I will invest in making my messy code turns into a package.

thisScript <- (function() {
  lastScriptSourced <- tail(unlist(lapply(sys.frames(), function(env) env$ofile)), 1)

  if (is.null(lastScriptSourced)) {
    # No script sourced, checking invocation through Rscript
    cmdArgs <- commandArgs(trailingOnly = FALSE)
    needle <- "--file="
    match <- grep(needle, cmdArgs)
    if (length(match) > 0) {
      return(normalizePath(sub(needle, "", cmdArgs[match]), winslash=.Platform$file.sep, mustWork=TRUE))
    }
  } else {
    # 'source'd via R console
    return(normalizePath(lastScriptSourced, winslash=.Platform$file.sep, mustWork=TRUE))
  }
})()

我已经将这个问题的答案打包并扩展为rprojroot中的新函数thisfile()。也适用于编织与针织。