我想做的事情是:

foo = {
    'foo': 1,
    'zip': 2,
    'zam': 3,
    'bar': 4
}

if ("foo", "bar") in foo:
    #do stuff

我如何检查是否foo和酒吧都在dict foo?


当前回答

你可以这样做:

>>> if all(k in foo for k in ("foo","bar")):
...     print "They're there!"
...
They're there!

其他回答

使用集:

if set(("foo", "bar")).issubset(foo):
    #do stuff

另外:

if set(("foo", "bar")) <= set(foo):
    #do stuff

你也可以使用. is子集()

>>> {"key1", "key2"}.issubset({"key1":1, "key2":2, "key3": 3})
True
>>> {"key4", "key2"}.issubset({"key1":1, "key2":2, "key3": 3})
False
>>>
if {"foo", "bar"} <= myDict.keys(): ...

如果你还在使用python2,你可以这样做

if {"foo", "bar"} <= myDict.viewkeys(): ...

如果你仍然使用非常老的Python <= 2.6,你可以在字典上调用set,但它会遍历整个字典来构建集合,这是很慢的:

if set(("foo", "bar")) <= set(myDict): ...
my_dict = {
    'name': 'Askavy',
    'country': 'India',
    'age': 30
}

if set(('name', 'country','age')).issubset(my_dict.keys()):
     print("All keys are present in the dictionary") 
else: 
    print("All keys are not present in  the dictionary") 

并不是说这不是你没有想过的事情,但我发现最简单的事情通常是最好的:

if ("foo" in foo) and ("bar" in foo):
    # do stuff