我想做的事情是:
foo = {
'foo': 1,
'zip': 2,
'zam': 3,
'bar': 4
}
if ("foo", "bar") in foo:
#do stuff
我如何检查是否foo和酒吧都在dict foo?
我想做的事情是:
foo = {
'foo': 1,
'zip': 2,
'zam': 3,
'bar': 4
}
if ("foo", "bar") in foo:
#do stuff
我如何检查是否foo和酒吧都在dict foo?
当前回答
你可以这样做:
>>> if all(k in foo for k in ("foo","bar")):
... print "They're there!"
...
They're there!
其他回答
使用集:
if set(("foo", "bar")).issubset(foo):
#do stuff
另外:
if set(("foo", "bar")) <= set(foo):
#do stuff
你也可以使用. is子集()
>>> {"key1", "key2"}.issubset({"key1":1, "key2":2, "key3": 3})
True
>>> {"key4", "key2"}.issubset({"key1":1, "key2":2, "key3": 3})
False
>>>
if {"foo", "bar"} <= myDict.keys(): ...
如果你还在使用python2,你可以这样做
if {"foo", "bar"} <= myDict.viewkeys(): ...
如果你仍然使用非常老的Python <= 2.6,你可以在字典上调用set,但它会遍历整个字典来构建集合,这是很慢的:
if set(("foo", "bar")) <= set(myDict): ...
my_dict = {
'name': 'Askavy',
'country': 'India',
'age': 30
}
if set(('name', 'country','age')).issubset(my_dict.keys()):
print("All keys are present in the dictionary")
else:
print("All keys are not present in the dictionary")
并不是说这不是你没有想过的事情,但我发现最简单的事情通常是最好的:
if ("foo" in foo) and ("bar" in foo):
# do stuff