我想做的事情是:

foo = {
    'foo': 1,
    'zip': 2,
    'zam': 3,
    'bar': 4
}

if ("foo", "bar") in foo:
    #do stuff

我如何检查是否foo和酒吧都在dict foo?


当前回答

你可以这样做:

>>> if all(k in foo for k in ("foo","bar")):
...     print "They're there!"
...
They're there!

其他回答

if {"foo", "bar"} <= myDict.keys(): ...

如果你还在使用python2,你可以这样做

if {"foo", "bar"} <= myDict.viewkeys(): ...

如果你仍然使用非常老的Python <= 2.6,你可以在字典上调用set,但它会遍历整个字典来构建集合,这是很慢的:

if set(("foo", "bar")) <= set(myDict): ...
>>> if 'foo' in foo and 'bar' in foo:
...     print 'yes'
... 
yes

Jason,()在Python中不是必需的。

那么使用呢?

 if reduce( (lambda x, y: x and foo.has_key(y) ), [ True, "foo", "bar"] ): # do stuff

使用集:

if set(("foo", "bar")).issubset(foo):
    #do stuff

另外:

if set(("foo", "bar")) <= set(foo):
    #do stuff

你可以这样做:

>>> if all(k in foo for k in ("foo","bar")):
...     print "They're there!"
...
They're there!