一般来说，你问题的答案是“是的”，但是……

.equals(...) will only compare what it is written to compare, no more, no less. If a class does not override the equals method, then it defaults to the equals(Object o) method of the closest parent class that has overridden this method. If no parent classes have provided an override, then it defaults to the method from the ultimate parent class, Object, and so you're left with the Object#equals(Object o) method. Per the Object API this is the same as ==; that is, it returns true if and only if both variables refer to the same object, if their references are one and the same. Thus you will be testing for object equality and not functional equality. Always remember to override hashCode if you override equals so as not to "break the contract". As per the API, the result returned from the hashCode() method for two objects must be the same if their equals methods show that they are equivalent. The converse is not necessarily true.

对于String类:

equals()方法比较String实例中的“值”(在堆上)，而不考虑两个对象引用是否引用同一个String实例。如果任意两个String类型的对象引用引用同一个String实例，那就太好了!如果两个对象引用引用两个不同的String实例..这没什么区别。它是每个被比较的String实例中的“值”(即:字符数组的内容)。

On the other hand, the "==" operator compares the value of two object references to see whether they refer to the same String instance. If the value of both object references "refer to" the same String instance then the result of the boolean expression would be "true"..duh. If, on the other hand, the value of both object references "refer to" different String instances (even though both String instances have identical "values", that is, the contents of the character arrays of each String instance are the same) the result of the boolean expression would be "false".

就像任何解释一样，让它深入人心。

我希望这能让你清楚一点。

==运算符测试两个变量是否有相同的引用 (又名指向内存地址的指针)。

String foo = new String("abc");
String bar = new String("abc");

if(foo==bar)
// False (The objects are not the same)

bar = foo;

if(foo==bar)
// True (Now the objects are the same)

而equals()方法测试两个变量是否引用对象 具有相同的状态(值)。

String foo = new String("abc");
String bar = new String("abc");

if(foo.equals(bar))
// True (The objects are identical but not same)

欢呼:-)

在计算代码时，很明显(==)是根据内存地址进行比较，而equals(Object o)是比较实例的hashCode()。 这就是为什么如果以后不遇到意外，就不要破坏equals()和hashCode()之间的契约。

    String s1 = new String("Ali");
    String s2 = new String("Veli");
    String s3 = new String("Ali");

    System.out.println(s1.hashCode());
    System.out.println(s2.hashCode());
    System.out.println(s3.hashCode());


    System.out.println("(s1==s2):" + (s1 == s2));
    System.out.println("(s1==s3):" + (s1 == s3));


    System.out.println("s1.equals(s2):" + (s1.equals(s2)));
    System.out.println("s1.equal(s3):" + (s1.equals(s3)));


    /*Output 
    96670     
    3615852
    96670
    (s1==s2):false
    (s1==s3):false
    s1.equals(s2):false
    s1.equal(s3):true
    */

一般来说，你问题的答案是“是的”，但是……

.equals(...) will only compare what it is written to compare, no more, no less. If a class does not override the equals method, then it defaults to the equals(Object o) method of the closest parent class that has overridden this method. If no parent classes have provided an override, then it defaults to the method from the ultimate parent class, Object, and so you're left with the Object#equals(Object o) method. Per the Object API this is the same as ==; that is, it returns true if and only if both variables refer to the same object, if their references are one and the same. Thus you will be testing for object equality and not functional equality. Always remember to override hashCode if you override equals so as not to "break the contract". As per the API, the result returned from the hashCode() method for two objects must be the same if their equals methods show that they are equivalent. The converse is not necessarily true.

Equals()方法主要比较对象的原始内容。

如果我们写作

    String s1 = "Samim";
    String s2 = "Samim";
    String s3 = new String("Samim");
    String s4 = new String("Samim");

    System.out.println(s1.equals(s2));
    System.out.println(s2.equals(s3));
    System.out.println(s3.equals(s4));

输出将是

true 
true 
true

因为equals()方法比较对象的内容。 在first System.out.println()中，s1和s2的内容是相同的，这就是为什么它打印为真。 另外两个System.out.println()为真。

再一次,

    String s1 = "Samim";
    String s2 = "Samim";
    String s3 = new String("Samim");
    String s4 = new String("Samim");
    
    System.out.println(s1 == s2);
    System.out.println(s2 == s3);
    System.out.println(s3 == s4);

输出将是

true
false 
false

因为==运算符主要比较对象的引用，而不是对象的值。 在first System.out.println()中，s1和s2的引用是相同的，这就是为什么它返回true。

在第二个System.out.println()中，创建了s3对象，这就是为什么会创建另一个s3的引用，并且s2和s3的引用会有所不同，因此它返回“false”。

Third System.out.println()，遵循second System.out.println()的规则，这就是为什么它会返回"false"。