在JUnit 4或更高版本中，您可以如下测试异常

@Rule
public ExpectedException exceptions = ExpectedException.none();

这提供了许多可以用来改进JUnit测试的特性。如果您看到下面的示例，我将测试异常的3个方面。

引发的异常类型异常消息异常的原因

public class MyTest {

    @Rule
    public ExpectedException exceptions = ExpectedException.none();

    ClassUnderTest classUnderTest;

    @Before
    public void setUp() throws Exception {
        classUnderTest = new ClassUnderTest();
    }

    @Test
    public void testAppleisSweetAndRed() throws Exception {

        exceptions.expect(Exception.class);
        exceptions.expectMessage("this is the exception message");
        exceptions.expectCause(Matchers.<Throwable>equalTo(exceptionCause));

        classUnderTest.methodUnderTest("param1", "param2");
    }

}

除了NamShubWriter所说的，还要确保：

ExpectedException实例是公共的（相关问题）ExpectedException未在@Before方法中实例化。这篇文章清楚地解释了JUnit执行顺序的所有复杂性。

不要这样做：

@Rule    
public ExpectedException expectedException;

@Before
public void setup()
{
    expectedException = ExpectedException.none();
}

最后，这篇博客文章清楚地说明了如何断言抛出了某个异常。

try {
    my method();
    fail( "This method must thrwo" );
} catch (Exception ex) {
    assertThat(ex.getMessage()).isEqual(myErrormsg);
}

Junit4与Java8的解决方案是使用此功能：

public Throwable assertThrows(Class<? extends Throwable> expectedException, java.util.concurrent.Callable<?> funky) {
    try {
        funky.call();
    } catch (Throwable e) {
        if (expectedException.isInstance(e)) {
            return e;
        }
        throw new AssertionError(
                String.format("Expected [%s] to be thrown, but was [%s]", expectedException, e));
    }
    throw new AssertionError(
            String.format("Expected [%s] to be thrown, but nothing was thrown.", expectedException));
}

用法如下：

    assertThrows(ValidationException.class,
            () -> finalObject.checkSomething(null));

注意，唯一的限制是在lambda表达式中使用最终对象引用。此解决方案允许使用@test（expected=IndexOutOfBoundsException.class）解决方案继续测试断言，而不是期望在方法级别可以执行。

小心使用预期的异常，因为它只断言方法抛出了该异常，而不是测试中的特定代码行。

我倾向于将其用于测试参数验证，因为这样的方法通常非常简单，但更复杂的测试可能更好：

try {
    methodThatShouldThrow();
    fail( "My method didn't throw when I expected it to" );
} catch (MyException expectedException) {
}

应用判断。

我使用Java 8 lambdas的解决方案：

public static <T extends Throwable> T assertThrows(Class<T> expected, ThrowingRunnable action) throws Throwable {
    try {
        action.run();
        Assert.fail("Did not throw expected " + expected.getSimpleName());
        return null; // never actually
    } catch (Throwable actual) {
        if (!expected.isAssignableFrom(actual.getClass())) { // runtime '!(actual instanceof expected)'
            System.err.println("Threw " + actual.getClass().getSimpleName() 
                               + ", which is not a subtype of expected " 
                               + expected.getSimpleName());
            throw actual; // throw the unexpected Throwable for maximum transparency
        } else {
            return (T) actual; // return the expected Throwable for further examination
        }
    }
}

您必须定义FunctionalInterface，因为Runnable没有声明所需的抛出。

@FunctionalInterface
public interface ThrowingRunnable {
    void run() throws Throwable;
}

方法如下：

class CustomException extends Exception {
    public final String message;
    public CustomException(final String message) { this.message = message;}
}
CustomException e = assertThrows(CustomException.class, () -> {
    throw new CustomException("Lorem Ipsum");
});
assertEquals("Lorem Ipsum", e.message);