如何使用JUnit来测试某些代码是否抛出异常?

我当然可以这样做:

@Test
public void testFooThrowsIndexOutOfBoundsException() {
  boolean thrown = false;

  try {
    foo.doStuff();
  } catch (IndexOutOfBoundsException e) {
    thrown = true;
  }

  assertTrue(thrown);
}

我记得,对于这类情况,有一个注释或Assert.xyz之类的东西远没有JUnit那么笨拙,更符合JUnit的精神。


当前回答

您也可以这样做:

@Test
public void testFooThrowsIndexOutOfBoundsException() {
    try {
        foo.doStuff();
        assert false;
    } catch (IndexOutOfBoundsException e) {
        assert true;
    }
}

其他回答

JUnit框架具有assertThrows()方法:

ArithmeticException exception = assertThrows(ArithmeticException.class, () ->
    calculator.divide(1, 0));
assertEquals("/ by zero", exception.getMessage());

对于JUnit 5,它位于org.unit.jupiter.api.Assertions类中;对于JUnit 4.13,它位于org.JUnit.Assert类中;对于JUnit4的早期版本:只需将org.JUnit.jupiter:junitjupiterapi上的引用添加到项目中,就可以从JUnit5获得非常好的工作版本。

我会使用assertThatTownBy

@Test
public void testFooThrowsIndexOutOfBoundsException() {
  assertThatThrownBy(() -> doStuff()).isInstanceOf(IndexOutOfBoundsException.class)
}

我建议库assertj核心处理junit测试中的异常

在java 8中,如下所示:

//given

//when
Throwable throwable = catchThrowable(() -> anyService.anyMethod(object));

//then
AnyException anyException = (AnyException) throwable;
assertThat(anyException.getMessage()).isEqualTo("........");
assertThat(exception.getCode()).isEqualTo(".......);

我在这里尝试了许多方法,但它们要么很复杂,要么不太符合我的要求。事实上,可以非常简单地编写一个助手方法:

public class ExceptionAssertions {
    public static void assertException(BlastContainer blastContainer ) {
        boolean caughtException = false;
        try {
            blastContainer.test();
        } catch( Exception e ) {
            caughtException = true;
        }
        if( !caughtException ) {
            throw new AssertionFailedError("exception expected to be thrown, but was not");
        }
    }
    public static interface BlastContainer {
        public void test() throws Exception;
    }
}

这样使用:

assertException(new BlastContainer() {
    @Override
    public void test() throws Exception {
        doSomethingThatShouldExceptHere();
    }
});

零依赖:无需mockito,无需powermock;在期末考试中表现很好。

Junit4与Java8的解决方案是使用此功能:

public Throwable assertThrows(Class<? extends Throwable> expectedException, java.util.concurrent.Callable<?> funky) {
    try {
        funky.call();
    } catch (Throwable e) {
        if (expectedException.isInstance(e)) {
            return e;
        }
        throw new AssertionError(
                String.format("Expected [%s] to be thrown, but was [%s]", expectedException, e));
    }
    throw new AssertionError(
            String.format("Expected [%s] to be thrown, but nothing was thrown.", expectedException));
}

用法如下:

    assertThrows(ValidationException.class,
            () -> finalObject.checkSomething(null));

注意,唯一的限制是在lambda表达式中使用最终对象引用。此解决方案允许使用@test(expected=IndexOutOfBoundsException.class)解决方案继续测试断言,而不是期望在方法级别可以执行。