我已经用@Test注释编写了一些JUnit测试。如果我的测试方法抛出一个检查过的异常,并且如果我想断言该消息与异常一起,是否有一种方法可以使用JUnit @Test注释来做到这一点?AFAIK, JUnit 4.7不提供这个功能,但是将来的版本会提供吗?我知道在。net中你可以断言消息和异常类。在Java世界中寻找类似的特性。

这就是我想要的:

@Test (expected = RuntimeException.class, message = "Employee ID is null")
public void shouldThrowRuntimeExceptionWhenEmployeeIDisNull() {}

当前回答

雷斯托姆给出了一个很好的答案。我也不太喜欢《规则》。我做了类似的事情,除了创建下面的实用工具类来提高可读性和可用性,这首先是注释的一大优点。

添加这个实用程序类:

import org.junit.Assert;

public abstract class ExpectedRuntimeExceptionAsserter {

    private String expectedExceptionMessage;

    public ExpectedRuntimeExceptionAsserter(String expectedExceptionMessage) {
        this.expectedExceptionMessage = expectedExceptionMessage;
    }

    public final void run(){
        try{
            expectException();
            Assert.fail(String.format("Expected a RuntimeException '%s'", expectedExceptionMessage));
        } catch (RuntimeException e){
            Assert.assertEquals("RuntimeException caught, but unexpected message", expectedExceptionMessage, e.getMessage());
        }
    }

    protected abstract void expectException();

}

然后,对于我的单元测试,我所需要的是这段代码:

@Test
public void verifyAnonymousUserCantAccessPrivilegedResourceTest(){
    new ExpectedRuntimeExceptionAsserter("anonymous user can't access privileged resource"){
        @Override
        protected void expectException() {
            throw new RuntimeException("anonymous user can't access privileged resource");
        }
    }.run(); //passes test; expected exception is caught, and this @Test returns normally as "Passed"
}

其他回答

在JUnit 4.13你可以做:

import static org.junit.Assert.assertEquals;
import static org.junit.Assert.assertThrows;

...

@Test
void exceptionTesting() {
  IllegalArgumentException exception = assertThrows(
    IllegalArgumentException.class, 
    () -> { throw new IllegalArgumentException("a message"); }
  );

  assertEquals("a message", exception.getMessage());
}

这也适用于JUnit 5,但有不同的导入:

import static org.junit.jupiter.api.Assertions.assertEquals;
import static org.junit.jupiter.api.Assertions.assertThrows;

...

我喜欢@Rule的答案。但是,如果出于某种原因您不想使用规则。还有第三种选择。

@Test (expected = RuntimeException.class)
public void myTestMethod()
{
   try
   {
      //Run exception throwing operation here
   }
   catch(RuntimeException re)
   {
      String message = "Employee ID is null";
      assertEquals(message, re.getMessage());
      throw re;
    }
    fail("Employee Id Null exception did not throw!");
  }

导入catch-exception库,并使用它。它比ExpectedException规则或try-catch规则干净得多。

他们文档中的例子:

import static com.googlecode.catchexception.CatchException.*;
import static com.googlecode.catchexception.apis.CatchExceptionHamcrestMatchers.*;

// given: an empty list
List myList = new ArrayList();

// when: we try to get the first element of the list
catchException(myList).get(1);

// then: we expect an IndexOutOfBoundsException with message "Index: 1, Size: 0"
assertThat(caughtException(),
  allOf(
    instanceOf(IndexOutOfBoundsException.class),
    hasMessage("Index: 1, Size: 0"),
    hasNoCause()
  )
);

如果使用@Rule,则异常集将应用于test类中的所有测试方法。

你可以使用@Rule注释和ExpectedException,就像这样:

@Rule
public ExpectedException expectedEx = ExpectedException.none();

@Test
public void shouldThrowRuntimeExceptionWhenEmployeeIDisNull() throws Exception {
    expectedEx.expect(RuntimeException.class);
    expectedEx.expectMessage("Employee ID is null");

    // do something that should throw the exception...
    System.out.println("=======Starting Exception process=======");
    throw new NullPointerException("Employee ID is null");
}

注意,ExpectedException文档中的例子(目前)是错误的——没有公共构造函数,所以你必须使用ExpectedException.none()。