分享我找到的解决方法

首先，使用registerForActivityResult为结果注册这个活动 这将返回一个类型为ActivityResultLauncher<Intent!> 像这样,

private val getResult =
        registerForActivityResult(
            ActivityResultContracts.StartActivityForResult()
        ) {
            if (it.resultCode == Activity.RESULT_OK) {
                val value = it.data?.getStringExtra("input")
            }
        }

现在，无论我们想在哪里启动result活动我们都可以使用getresult。launch(intent)

在芬兰湾的科特林 我改变了我的代码

startActivityForResult(intent, Constants.MY_CODE_REQUEST)

and

override fun onActivityResult(requestCode: Int, resultCode: Int, data: Intent) {
    super.onActivityResult(requestCode, resultCode, data)
    if (resultCode == Activity.RESULT_OK) {
        when (requestCode) {
            Constants.MY_CODE_REQUEST -> {
            ...
}

to

registerForActivityResult(StartActivityForResult()) { result ->
    onActivityResult(Constants.MY_CODE_REQUEST, result)
}.launch(intent)

and

private fun onActivityResult(requestCode: Int, result: ActivityResult) {
    if(result.resultCode == Activity.RESULT_OK) {
        val intent = result.data
        when (requestCode) {
            Constants.MY_CODE_REQUEST -> {
            ...

我希望这对你有用。: D

dor506回答为我工作，因为我在我的大多数项目中使用BaseActivity，所以对我来说更容易在单个文件中更改代码，而不是我所有的活动。我已经写了这个代码的java版本。

BaseActivity代码:

private int requestCode = -1;
private ActivityResultLauncher<Intent> resultHandler = null;

 @Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    mContext = this;

    registerForActivityResult();
}
  private final void registerForActivityResult() {
    if (shouldRegisterForActivityResult()) {
        this.resultHandler = registerForActivityResult(new ActivityResultContracts.StartActivityForResult(),
                new ActivityResultCallback() {

            public void onActivityResult(Object var1) {
                this.onActivityResult((ActivityResult)var1);
            }

            public final void onActivityResult(ActivityResult result) {
                Intrinsics.checkNotNullExpressionValue(result, "result");
                AppActivityClass.onActivityResult(result.getData(), AppActivityClass.this.requestCode, result.getResultCode());
                AppActivityClass.this.requestCode = -1;
            }
        });
    }
}

public final void startActivityForResult(int requestCode, Intent intent) {
    this.requestCode = requestCode;
    if (resultHandler != null) {
        resultHandler.launch(intent);
    }
}

protected static void onActivityResult(Intent intent, int requestCode, int resultCode) {
}

protected Boolean shouldRegisterForActivityResult() {
    return false;
}

现在在任何活动中使用这样的代码:

 @Override
protected Boolean shouldRegisterForActivityResult() {
    return true;  // this will override the baseactivity method and we can use onactivityresult
}

  private void someMethod(){
    Intent i = new Intent(mContext,SomeOtherClassActivity.class);
    startActivityForResult(101,i);
}

  @Override
protected void onActivityResult(int requestCode, int resultCode, @Nullable Intent data) {
    super.onActivityResult(requestCode, resultCode, data);
    if (requestCode == 101) {
        if (resultCode == RESULT_OK) {
            //revert from called class
        }
    }
}

下面的代码在Kotlin片段中工作，用于检查蓝牙权限。年- 2022年

val intent = intent (BluetoothAdapter.ACTION_REQUEST_ENABLE)

        registerForActivityResult(ActivityResultContracts.StartActivityForResult()) { result ->
            if (result.resultCode == Activity.RESULT_OK) {
                // There are no request codes
                val data: Intent? = result.data
                bluetoothAdapter.enable()
                Toast.makeText(context, "Permission Granted: ", Toast.LENGTH_SHORT).show()
                dynamicButton()
            }
            else{Toast.makeText(context, "You have to enable bluetooth to use this app.", Toast.LENGTH_SHORT).show()}
            
        }.launch(intent)

从现在开始，startActivityForResult()已经被弃用，所以使用new方法代替。

芬兰湾的科特林的例子

    fun openActivityForResult() {
        startForResult.launch(Intent(this, AnotherActivity::class.java))
    }


    val startForResult = registerForActivityResult(ActivityResultContracts.StartActivityForResult()) { 
    result: ActivityResult ->
        if (result.resultCode == Activity.RESULT_OK) {
            val intent = result.data
            // Handle the Intent
            //do stuff here
        }
    }

在我的情况下，我试图使用意图，我直接移动到下一个活动，而不使用谷歌登录。

对我有用的是:

在OnCreate中为登录按钮设置onClickListener:

     btnSignIn.setOnClickListener {
        signIn()
        }

    private fun signIn() {
        val intent = client.signInIntent
        mainActivityResultLauncher.launch(intent)
    }

在上面的代码中，我写了去下一个活动的意图，但我必须写client.signInIntent

    var mainActivityResultLauncher = registerForActivityResult(ActivityResultContracts.StartActivityForResult()){ result ->

        if(result.resultCode == Activity.RESULT_OK){
            val data = result.data
            val task = GoogleSignIn.getSignedInAccountFromIntent(data)
            try {
                // Google Sign In was successful, authenticate with Firebase
                val account = task.getResult(ApiException::class.java)!!
                Log.d(TAG, "firebaseAuthWithGoogle:" + account.id)
                firebaseAuthWithGoogle(account.idToken!!)
            } catch (e: ApiException) {
                // Google Sign In failed, update UI appropriately
                Log.w(TAG, "Google sign in failed", e)
            }
        }
    }