在我的情况下，我试图使用意图，我直接移动到下一个活动，而不使用谷歌登录。

对我有用的是:

在OnCreate中为登录按钮设置onClickListener:

     btnSignIn.setOnClickListener {
        signIn()
        }

    private fun signIn() {
        val intent = client.signInIntent
        mainActivityResultLauncher.launch(intent)
    }

在上面的代码中，我写了去下一个活动的意图，但我必须写client.signInIntent

    var mainActivityResultLauncher = registerForActivityResult(ActivityResultContracts.StartActivityForResult()){ result ->

        if(result.resultCode == Activity.RESULT_OK){
            val data = result.data
            val task = GoogleSignIn.getSignedInAccountFromIntent(data)
            try {
                // Google Sign In was successful, authenticate with Firebase
                val account = task.getResult(ApiException::class.java)!!
                Log.d(TAG, "firebaseAuthWithGoogle:" + account.id)
                firebaseAuthWithGoogle(account.idToken!!)
            } catch (e: ApiException) {
                // Google Sign In failed, update UI appropriately
                Log.w(TAG, "Google sign in failed", e)
            }
        }
    }

我的目标是用最少的代码更改重用startActivityForResult方法的当前实现。为此，我使用onActivityResultFromLauncher方法创建了一个包装器类和接口。

interface ActivityResultLauncherWrapper {

    fun launchIntentForResult(activity: FragmentActivity, intent: Intent, requestCode: Int, callBack: OnActivityResultListener)

    fun unregister()

    interface OnActivityResultListener {
        fun onActivityResultFromLauncher(requestCode: Int, resultCode: Int, data: Intent?)
    }
}

class ActivityResultLauncherWrapperImpl : ActivityResultLauncherWrapper {
    private var weakLauncher: WeakReference<ActivityResultLauncher<Intent>>? = null

    override fun launchIntentForResult(
            activity: FragmentActivity,
            intent: Intent,
            requestCode: Int,
            callBack: ActivityResultLauncherWrapper.OnActivityResultListener
    ) {

        weakLauncher = WeakReference(
                activity.registerForActivityResult(ActivityResultContracts.StartActivityForResult()) { result ->
                    callBack.onActivityResultFromLauncher(requestCode, result.resultCode, result.data)
                }
        )

        weakLauncher?.get()?.launch(intent)
    }

    override fun unregister() {
        weakLauncher?.get()?.unregister()
    }
}

我在我的项目中使用匕首，我在需要的地方注入了包装器

@Inject
lateinit var activityResultLauncher: ActivityResultLauncherWrapper

但是包装器也可以直接实例化:

val activityResultLauncher = ActivityResultLauncherWrapper()

然后你必须用launchIntentForResult改变startActivityForResult方法。下面是一个从片段中调用它的例子:

activityResultLauncher.launchIntentForResult(
        requireActivity(),
        intent,
        REQUEST_CODE_CONSTANT,
        object: ActivityResultLauncherWrapper.OnActivityResultListener {
            override fun onActivityResultFromLauncher(requestCode: Int, resultCode: Int, data: Intent?) {
                /*do something*/
            }
        }
)

您将在匿名对象中收到结果。 你可以在Fragment或FragmentActivity中使用OnActivityResultListener，如果你实现了接口，并像这样重构当前的实现:

class MyFragment : Fragment(), OnActivityResultListener {
   
 ...
    
override fun onActivityResultFromLauncher(requestCode: Int, resultCode: Int, data: Intent?) {/*do somthing*/}

 ...

}

正如我们所知，Kotlin类ActivityResultLauncherWrapper也可以在java代码中使用。在我的项目中也有java类。这里有一个在Fragment中实现回调接口的例子:

public class MyFragment extends Fragment implements OnActivityResultListener {
    
...

    @Inject
    ActivityResultLauncherWrapper activityResultLauncher;
//ActivityResultLauncherWrapper activityResultLauncher = new ActivityResultLauncherWrapper()

...

public void launnchActivity(@NotNull Intent intent) {
        activityResultLauncher.launchIntentForResult(requireActivity(), intent, REQUEST_CODE_CONSTANT, this);
    }

...

 @Override
    public void onActivityResultFromLauncher(int requestCode, int resultCode, Intent data) {/*do somthing*/}
...
}

我希望这有助于为您的案例构建解决方案。

分享我找到的解决方法

首先，使用registerForActivityResult为结果注册这个活动 这将返回一个类型为ActivityResultLauncher<Intent!> 像这样,

private val getResult =
        registerForActivityResult(
            ActivityResultContracts.StartActivityForResult()
        ) {
            if (it.resultCode == Activity.RESULT_OK) {
                val value = it.data?.getStringExtra("input")
            }
        }

现在，无论我们想在哪里启动result活动我们都可以使用getresult。launch(intent)

在芬兰湾的科特林 我改变了我的代码

startActivityForResult(intent, Constants.MY_CODE_REQUEST)

and

override fun onActivityResult(requestCode: Int, resultCode: Int, data: Intent) {
    super.onActivityResult(requestCode, resultCode, data)
    if (resultCode == Activity.RESULT_OK) {
        when (requestCode) {
            Constants.MY_CODE_REQUEST -> {
            ...
}

to

registerForActivityResult(StartActivityForResult()) { result ->
    onActivityResult(Constants.MY_CODE_REQUEST, result)
}.launch(intent)

and

private fun onActivityResult(requestCode: Int, result: ActivityResult) {
    if(result.resultCode == Activity.RESULT_OK) {
        val intent = result.data
        when (requestCode) {
            Constants.MY_CODE_REQUEST -> {
            ...

我希望这对你有用。: D

在我的情况下，我试图使用意图，我直接移动到下一个活动，而不使用谷歌登录。

对我有用的是:

在OnCreate中为登录按钮设置onClickListener:

     btnSignIn.setOnClickListener {
        signIn()
        }

    private fun signIn() {
        val intent = client.signInIntent
        mainActivityResultLauncher.launch(intent)
    }

在上面的代码中，我写了去下一个活动的意图，但我必须写client.signInIntent

    var mainActivityResultLauncher = registerForActivityResult(ActivityResultContracts.StartActivityForResult()){ result ->

        if(result.resultCode == Activity.RESULT_OK){
            val data = result.data
            val task = GoogleSignIn.getSignedInAccountFromIntent(data)
            try {
                // Google Sign In was successful, authenticate with Firebase
                val account = task.getResult(ApiException::class.java)!!
                Log.d(TAG, "firebaseAuthWithGoogle:" + account.id)
                firebaseAuthWithGoogle(account.idToken!!)
            } catch (e: ApiException) {
                // Google Sign In failed, update UI appropriately
                Log.w(TAG, "Google sign in failed", e)
            }
        }
    }

一个简单的例子:registerForActivityResult和requestmultiplepermission from Activity和Fragment

请求活动以获得活动的结果

registerForActivityResult(
    ActivityResultContracts.StartActivityForResult()
) { activityResult ->
    if (activityResult.resultCode == Activity.RESULT_OK) {
        //...
    }
}

检查ActivityResult

向活动请求许可?

registerForActivityResult(
    ActivityResultContracts.RequestMultiplePermissions()
) {
    //it: Map<String, Boolean>
}

从片段?

使用相同的方法，但确保将这些实现放在初始化中，onAttach()或onCreate()