只是在这里添加我的版本如何在外部触摸时取消键盘。

viewDidLoad:

UITapGestureRecognizer *singleTap = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(handleSingleTap:)];
[self.view addGestureRecognizer:singleTap];

在任何地方:

-(void)handleSingleTap:(UITapGestureRecognizer *)sender{
    [textFieldName resignFirstResponder];
    puts("Dismissed the keyboard");
}

你需要添加一个UITapGestureRecogniser并将其分配给视图，然后在它的选择器上的UITextField上调用resign first responder。

代码:

在viewDidLoad

UITapGestureRecognizer *tap = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(dismissKeyboard)];

[self.view addGestureRecognizer:tap];

在dismissKeyboard:

-(void)dismissKeyboard 
{
    [aTextField resignFirstResponder];
}

(其中，aTextField是负责键盘的文本字段)

Swift 3版本是这样的

let tapGesture = UITapGestureRecognizer(target: self, action: #selector(self.dismissKeyboard (_:)))
self.view.addGestureRecognizer(tapGesture)

对于dismissKeyboard

@objc func dismissKeyboard (_ sender: UITapGestureRecognizer) {
    aTextField.resignFirstResponder()
}

最好是让你的UIView成为UIControl的一个实例(在界面构建器中)，然后连接他们的TouchUpInside事件来解散键盘方法。这个IBAction方法看起来像:

- (IBAction)dismissKeyboard:(id)sender {
    [aTextBox resignFirstResponder];
}

override func touchesBegan(touches: Set<NSObject>, withEvent event: UIEvent) {
    super.view.endEditing(true)
    super.touchesBegan(touches, withEvent: event)
}

在我的新发展中，我以巴里为例。它工作得很好!但我不得不包括一个轻微的变化，要求解散键盘，只有文本字段被编辑。

所以，我在Barry的例子中加入了以下内容:

- (void) textFieldDidBeginEditing:(UITextField *)textField
{
    _textBeingEdited = textField;
}
-(void) textFieldDidEndEditing:(UITextField *)textField
{
    _textBeingEdited = nil;
}

同时，我修改了hideKeyboard方法如下:

- (IBAction)hideKeyboard:(id)sender
{
    // Just call resignFirstResponder on all UITextFields and UITextViews in this VC
    // Why? Because it works and checking which one was last active gets messy.
    //UITextField * tf = (UITextField *) sender;
    [_textBeingEdited resignFirstResponder];
}

有一件事很重要……

添加手势识别到视图可以覆盖它的子视图。 所以只执行一个动作。 如果你想通过父视图和子视图执行多重识别操作… 你必须使用

 tap.cancelsTouchesInView = false

完整代码如下:

 let tap = UITapGestureRecognizer(target: self, action: #selector(self.superViewClicked))
        tap.numberOfTapsRequired = 1
        tap.delegate = self
        tap.cancelsTouchesInView = false
        self.view.addGestureRecognizer(tap)




  @objc func superViewClicked(){
        
        self.searchTF.resignFirstResponder()
    }

在外面点击关闭软键盘的最佳解决方案是什么?

我将解释一个条件:

想想看:你在顶部有UISearchBar， 然后添加头表视图!

解决方法很简单:

跟踪软键盘打开或关闭 添加手势识别头视图 实现表视图didSelectRowAt的委托

完整的代码:

   var isSoftKeyboardActive = false

    override func viewDidLoad() {
    
    
        var tap = UITapGestureRecognizer(target: self, action: #selector(self.tableHeaderClick))
            tap.numberOfTapsRequired = 1
            tap.delegate = self
            tap.cancelsTouchesInView = false
            self.headerOfTableView.addGestureRecognizer(tap)
    
    }
    
          override func viewWillAppear(_ animated: Bool) {
                  super.viewWillAppear(animated)
                 NotificationCenter.default.addObserver(self, selector: #selector(keyboardWillDisappear), name: UIResponder.keyboardWillHideNotification, object: nil)
                  NotificationCenter.default.addObserver(self, selector: #selector(keyboardWillAppear), name: UIResponder.keyboardWillShowNotification, object: nil)
              }
              
              override func viewWillDisappear(_ animated: Bool) {
                  super.viewWillDisappear(animated)
                  NotificationCenter.default.removeObserver(self)
              }
        


    func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {
          if isSoftKeyboardActive == true{
               
               self.searchTF.resignFirstResponder()
           }else{
           
               selectedRow = indexPath.row
               performSegue(withIdentifier: "segueWebview", sender: self)
               
           }
    }
    


 
    @objc func tableHeaderClick(){
         
        self.searchTF.resignFirstResponder()
    
     }
    
    
    
  @objc func keyboardWillAppear() {

        
        isSoftKeyboardActive = true
    }

    @objc func keyboardWillDisappear() {
        
        isSoftKeyboardActive = false
        
    }
 

它是如何工作的:

如果软键盘是打开的，用户点击头软键盘关闭 如果软键盘打开，用户点击单元格，键盘关闭，不执行单元格点击