可以使用size()方法获取字符串的长度，使用方括号操作符访问每个字符。

#include<bits/stdc++.h>
using namespace std;

int main()
{
   string s;
   cin >> s;
   int length = s.size();
   for(int i = 0; i < length; i++)
   {
      process(s[i]);
   }
}

这是另一种方法，使用标准算法。

#include <iostream>
#include <string>
#include <algorithm>

int main()
{
   std::string name = "some string";
   std::for_each(name.begin(), name.end(), [] (char c) {
      std::cout << c;
   });
}

Looping through the characters of a std::string, using a range-based for loop (it's from C++11, already supported in recent releases of GCC, clang, and the VC11 beta): std::string str = ???; for(char& c : str) { do_things_with(c); } Looping through the characters of a std::string with iterators: std::string str = ???; for(std::string::iterator it = str.begin(); it != str.end(); ++it) { do_things_with(*it); } Looping through the characters of a std::string with an old-fashioned for-loop: std::string str = ???; for(std::string::size_type i = 0; i < str.size(); ++i) { do_things_with(str[i]); } Looping through the characters of a null-terminated character array: char* str = ???; for(char* it = str; *it; ++it) { do_things_with(*it); }

const char* str = "abcde";
int len = strlen(str);
for (int i = 0; i < len; i++)
{
    char chr = str[i];
    //do something....
}

for循环可以这样实现:

string str("HELLO");
for (int i = 0; i < str.size(); i++){
    cout << str[i];
}

这将逐字符打印字符串。Str [i]返回索引i处的字符。

如果是字符数组:

char str[6] = "hello";
for (int i = 0; str[i] != '\0'; i++){
    cout << str[i];
}

基本上以上两个是c++支持的两种类型的字符串。 第二个称为c字符串，第一个称为std字符串或(c++字符串)。我建议使用c++字符串，很容易处理。

我没有看到任何使用“c字符串”的基于范围的for循环的例子。

char cs[] = "This is a c string\u0031 \x32 3";

// range based for loop does not print '\n'
for (char& c : cs) {
    printf("%c", c);
}

不是相关的，而是int数组的例子

int ia[] = {1,2,3,4,5,6};

for (int& i : ia) {
    printf("%d", i);
}