我没有看到任何使用“c字符串”的基于范围的for循环的例子。

char cs[] = "This is a c string\u0031 \x32 3";

// range based for loop does not print '\n'
for (char& c : cs) {
    printf("%c", c);
}

不是相关的，而是int数组的例子

int ia[] = {1,2,3,4,5,6};

for (int& i : ia) {
    printf("%d", i);
}

这是另一种方法，使用标准算法。

#include <iostream>
#include <string>
#include <algorithm>

int main()
{
   std::string name = "some string";
   std::for_each(name.begin(), name.end(), [] (char c) {
      std::cout << c;
   });
}

对于C-string (char[])，你应该这样做:

char mystring[] = "My String";
int size = strlen(mystring);
int i;
for(i = 0; i < size; i++) {
    char c = mystring[i];
}

对于std::string，你可以使用str.size()来获取它的大小并像示例一样迭代，或者可以使用迭代器:

std::string mystring = "My String";
std::string::iterator it;
for(it = mystring.begin(); it != mystring.end(); it++) {
    char c = *it;
}

const char* str = "abcde";
int len = strlen(str);
for (int i = 0; i < len; i++)
{
    char chr = str[i];
    //do something....
}

Looping through the characters of a std::string, using a range-based for loop (it's from C++11, already supported in recent releases of GCC, clang, and the VC11 beta): std::string str = ???; for(char& c : str) { do_things_with(c); } Looping through the characters of a std::string with iterators: std::string str = ???; for(std::string::iterator it = str.begin(); it != str.end(); ++it) { do_things_with(*it); } Looping through the characters of a std::string with an old-fashioned for-loop: std::string str = ???; for(std::string::size_type i = 0; i < str.size(); ++i) { do_things_with(str[i]); } Looping through the characters of a null-terminated character array: char* str = ???; for(char* it = str; *it; ++it) { do_things_with(*it); }

我没有看到任何使用“c字符串”的基于范围的for循环的例子。

char cs[] = "This is a c string\u0031 \x32 3";

// range based for loop does not print '\n'
for (char& c : cs) {
    printf("%c", c);
}

不是相关的，而是int数组的例子

int ia[] = {1,2,3,4,5,6};

for (int& i : ia) {
    printf("%d", i);
}