PHP -简短但精确

在这里，我将我的JS答案(数学细节在那里)重写为PHP -你可以在这里运行它

function hsl2rgb($h,$s,$l) 
{
  $a = $s * min($l, 1-$l);
  $k = function($n,$h) { return ($n+$h/30)%12;};
  $f = function($n) use ($h,$s,$l,$a,$k) { 
      return $l - $a * max( min($k($n,$h)-3, 9-$k($n,$h), 1),-1);
  };
  return [ $f(0), $f(8), $f(4) ];
}   

@Mohsen代码的PHP实现(包括Test!)

很抱歉重新发布这篇文章。但我真的没有看到任何其他实现可以提供我所需的质量。

/**
 * Converts an HSL color value to RGB. Conversion formula
 * adapted from http://en.wikipedia.org/wiki/HSL_color_space.
 * Assumes h, s, and l are contained in the set [0, 1] and
 * returns r, g, and b in the set [0, 255].
 *
 * @param   {number}  h       The hue
 * @param   {number}  s       The saturation
 * @param   {number}  l       The lightness
 * @return  {Array}           The RGB representation
 */
  
function hue2rgb($p, $q, $t){
            if($t < 0) $t += 1;
            if($t > 1) $t -= 1;
            if($t < 1/6) return $p + ($q - $p) * 6 * $t;
            if($t < 1/2) return $q;
            if($t < 2/3) return $p + ($q - $p) * (2/3 - $t) * 6;
            return $p;
        }
function hslToRgb($h, $s, $l){
    if($s == 0){
        $r = $l;
        $g = $l;
        $b = $l; // achromatic
    }else{
        $q = $l < 0.5 ? $l * (1 + $s) : $l + $s - $l * $s;
        $p = 2 * $l - $q;
        $r = hue2rgb($p, $q, $h + 1/3);
        $g = hue2rgb($p, $q, $h);
        $b = hue2rgb($p, $q, $h - 1/3);
    }

    return array(round($r * 255), round($g * 255), round($b * 255));
}

/* Uncomment to test * /
for ($i=0;$i<360;$i++) {
  $rgb=hslToRgb($i/360, 1, .9);
  echo '<div style="background-color:rgb(' .$rgb[0] . ', ' . $rgb[1] . ', ' . $rgb[2] . ');padding:2px;"></div>';
}
/* End Test */

如果你正在寻找一些完全符合HSL和RGB的CSS语义的东西，你可以使用css3规范中指定的算法，它如下:

HOW TO RETURN hsl.to.rgb(h, s, l): 
   SELECT: 
      l<=0.5: PUT l*(s+1) IN m2
      ELSE: PUT l+s-l*s IN m2
   PUT l*2-m2 IN m1
   PUT hue.to.rgb(m1, m2, h+1/3) IN r
   PUT hue.to.rgb(m1, m2, h    ) IN g
   PUT hue.to.rgb(m1, m2, h-1/3) IN b
   RETURN (r, g, b)

HOW TO RETURN hue.to.rgb(m1, m2, h): 
   IF h<0: PUT h+1 IN h
   IF h>1: PUT h-1 IN h
   IF h*6<1: RETURN m1+(m2-m1)*h*6
   IF h*2<1: RETURN m2
   IF h*3<2: RETURN m1+(m2-m1)*(2/3-h)*6
   RETURN m1

我相信这是这里其他一些答案的来源。

我是这样做的，这很容易记住，把RGB想象成一个轮子上的三条辐条，相隔120度。

H = hue (0-360)
S = saturation (0-1)
L = luminance (0-1)

R1 = SIN( H ) * L 
G1 = SIN( H + 120 ) * L 
B1 = SIN( H + 240 ) * L 

棘手的部分是饱和度，即缩小到这三者的平均值。

AVERAGE = (R1 + G1 + B1) / 3 

R2 = ((R1 - AVERAGE) * S) + AVERAGE 
G2 = ((G1 - AVERAGE) * S) + AVERAGE 
B2 = ((B1 - AVERAGE) * S) + AVERAGE 

RED = R2 * 255 
GREEN = G2 * 255 
BLUE = B2 * 255 

Mohsen代码的Java实现

注意，所有整数都声明为浮点数(即1f)，必须是浮点数，否则您将选择灰色。

HSL到RGB

 /**
 * Converts an HSL color value to RGB. Conversion formula
 * adapted from http://en.wikipedia.org/wiki/HSL_color_space.
 * Assumes h, s, and l are contained in the set [0, 1] and
 * returns r, g, and b in the set [0, 255].
 *
 * @param h       The hue
 * @param s       The saturation
 * @param l       The lightness
 * @return int array, the RGB representation
 */
public static int[] hslToRgb(float h, float s, float l){
    float r, g, b;

    if (s == 0f) {
        r = g = b = l; // achromatic
    } else {
        float q = l < 0.5f ? l * (1 + s) : l + s - l * s;
        float p = 2 * l - q;
        r = hueToRgb(p, q, h + 1f/3f);
        g = hueToRgb(p, q, h);
        b = hueToRgb(p, q, h - 1f/3f);
    }
    int[] rgb = {to255(r), to255(g), to255(b)};
    return rgb;
}
public static int to255(float v) { return (int)Math.min(255,256*v); }

/** Helper method that converts hue to rgb */
public static float hueToRgb(float p, float q, float t) {
    if (t < 0f)
        t += 1f;
    if (t > 1f)
        t -= 1f;
    if (t < 1f/6f)
        return p + (q - p) * 6f * t;
    if (t < 1f/2f)
        return q;
    if (t < 2f/3f)
        return p + (q - p) * (2f/3f - t) * 6f;
    return p;
}

RGB到HSL

/**
 * Converts an RGB color value to HSL. Conversion formula
 * adapted from http://en.wikipedia.org/wiki/HSL_color_space.
 * Assumes pR, pG, and bpBare contained in the set [0, 255] and
 * returns h, s, and l in the set [0, 1].
 *
 * @param pR       The red color value
 * @param pG       The green color value
 * @param pB       The blue color value
 * @return float array, the HSL representation
 */
public static float[] rgbToHsl(int pR, int pG, int pB) {
    float r = pR / 255f;
    float g = pG / 255f;
    float b = pB / 255f;

    float max = (r > g && r > b) ? r : (g > b) ? g : b;
    float min = (r < g && r < b) ? r : (g < b) ? g : b;

    float h, s, l;
    l = (max + min) / 2.0f;

    if (max == min) {
        h = s = 0.0f;
    } else {
        float d = max - min;
        s = (l > 0.5f) ? d / (2.0f - max - min) : d / (max + min);

        if (r > g && r > b)
            h = (g - b) / d + (g < b ? 6.0f : 0.0f);

        else if (g > b)
            h = (b - r) / d + 2.0f;

        else
            h = (r - g) / d + 4.0f;

        h /= 6.0f;
    }

    float[] hsl = {h, s, l};
    return hsl;
}

维基百科上关于HSL和HSV的文章包含了一些公式。计算有点棘手，所以看一下现有的实现可能会有用。