对于Objective-C解决方案也是如此

@implementation UIWindow (iOS13)

+ (UIWindow*) keyWindow {
   NSPredicate *isKeyWindow = [NSPredicate predicateWithFormat:@"isKeyWindow == YES"];
   return [[[UIApplication sharedApplication] windows] filteredArrayUsingPredicate:isKeyWindow].firstObject;
}

@end

如果你使用SwiftLint的'first_where'规则，并想静音交战:

UIApplication.shared.windows.first(where: { $0.isKeyWindow })

我在这里提出的建议在iOS 15中已弃用。现在怎么办?好吧，如果一个应用没有自己的多个窗口，我假设接受的现代方式将是获得应用的第一个connectedscene，强制到一个UIWindowScene，并获得它的第一个窗口。但这几乎正是公认的答案所做的!所以我的变通办法在这一点上感觉相当无力。但是，由于历史原因，我还是让它保持原样。

公认的答案虽然巧妙，但可能过于详尽。你可以更简单地得到完全相同的结果:

UIApplication.shared.windows.filter {$0.isKeyWindow}.first

我还要提醒大家，不要过于认真地对待keyWindow的弃用。完整的警告信息如下:

'keyWindow'在iOS 13.0中已弃用:不应该用于支持多个场景的应用程序，因为它在所有连接的场景中返回一个键窗口

所以如果你不支持iPad上的多窗口，继续使用keyWindow是没有异议的。

一个UIApplication扩展:

extension UIApplication {

    /// The app's key window taking into consideration apps that support multiple scenes.
    var keyWindowInConnectedScenes: UIWindow? {
        return windows.first(where: { $0.isKeyWindow })
    }

}

用法:

let myKeyWindow: UIWindow? = UIApplication.shared.keyWindowInConnectedScenes

当.foregroundActive场景为空时，我遇到了这个问题

这是我的变通办法

public extension UIWindow {
    @objc
    static var main: UIWindow {
        // Here we sort all the scenes in order to work around the case
        // when no .foregroundActive scenes available and we need to look through
        // all connectedScenes in order to find the most suitable one
        let connectedScenes = UIApplication.shared.connectedScenes
            .sorted { lhs, rhs in
                let lhs = lhs.activationState
                let rhs = rhs.activationState
                switch lhs {
                case .foregroundActive:
                    return true
                case .foregroundInactive:
                    return rhs == .background || rhs == .unattached
                case .background:
                    return rhs == .unattached
                case .unattached:
                    return false
                @unknown default:
                    return false
                }
            }
            .compactMap { $0 as? UIWindowScene }

        guard connectedScenes.isEmpty == false else {
            fatalError("Connected scenes is empty")
        }
        let mainWindow = connectedScenes
            .flatMap { $0.windows }
            .first(where: \.isKeyWindow)

        guard let window = mainWindow else {
            fatalError("Couldn't get main window")
        }
        return window
    }
}

Objective C解决方案:

UIWindow *foundWindow = nil;
NSSet *scenes=[[UIApplication sharedApplication] connectedScenes];
NSArray *windows;
for(id aScene in scenes){  // it's an NSSet so you can't use the first object
    windows=[aScene windows];
    if([aScene activationState]==UISceneActivationStateForegroundActive)
         break;
}
for (UIWindow  *window in windows) {
    if (window.isKeyWindow) {
        foundWindow = window;
        break;
    }
}
 // and to find the parent viewController:
UIViewController* parentController = foundWindow.rootViewController;
while( parentController.presentedViewController &&
      parentController != parentController.presentedViewController ){
    parentController = parentController.presentedViewController;
}