这适用于Python 2和3:

from itertools import islice

with open('/tmp/filename.txt') as inf:
    for line in islice(inf, N, N+M):
        print(line)

有一个简单的方法来获取前10行:

with open('fileName.txt', mode = 'r') as file:
    list = [line.rstrip('\n') for line in file][:10]
    print(list)

最直观的两种方法是:

逐行迭代文件，并在N行之后进行换行。 使用next()方法逐行迭代文件N次。(这本质上只是顶部答案的不同语法。)

代码如下:

# Method 1:
with open("fileName", "r") as f:
    counter = 0
    for line in f:
        print line
        counter += 1
        if counter == N: break

# Method 2:
with open("fileName", "r") as f:
    for i in xrange(N):
        line = f.next()
        print line

底线是，只要不使用readlines()或将整个文件枚举到内存中，您就有很多选择。

我想通过读取整个文件来处理小于n行的文件

def head(filename: str, n: int):
    try:
        with open(filename) as f:
            head_lines = [next(f).rstrip() for x in range(n)]
    except StopIteration:
        with open(filename) as f:
            head_lines = f.read().splitlines()
    return head_lines

这要归功于约翰·拉·鲁伊和伊莲·伊利耶夫。使用异常句柄函数以获得最佳性能

修改1:感谢FrankM的反馈，处理文件存在和读取权限我们可以进一步增加

import errno
import os

def head(filename: str, n: int):
    if not os.path.isfile(filename):
        raise FileNotFoundError(errno.ENOENT, os.strerror(errno.ENOENT), filename)  
    if not os.access(filename, os.R_OK):
        raise PermissionError(errno.EACCES, os.strerror(errno.EACCES), filename)     
   
    try:
        with open(filename) as f:
            head_lines = [next(f).rstrip() for x in range(n)]
    except StopIteration:
        with open(filename) as f:
            head_lines = f.read().splitlines()
    return head_lines

您可以使用第二个版本，也可以使用第一个版本，稍后再处理文件异常。从性能的角度来看，检查是快速的，而且大部分是免费的

Python 3:

with open("datafile") as myfile:
    head = [next(myfile) for x in range(N)]
print(head)

Python 2:

with open("datafile") as myfile:
    head = [next(myfile) for x in xrange(N)]
print head

下面是另一种方法(Python 2和3都是):

from itertools import islice

with open("datafile") as myfile:
    head = list(islice(myfile, N))
print(head)

这对我很有效

f = open("history_export.csv", "r")
line= 5
for x in range(line):
    a = f.readline()
    print(a)