我们有一个很大的原始数据文件,我们想把它修剪成指定的大小。
如何在python中获取文本文件的前N行?所使用的操作系统对实现有任何影响吗?
我们有一个很大的原始数据文件,我们想把它修剪成指定的大小。
如何在python中获取文本文件的前N行?所使用的操作系统对实现有任何影响吗?
当前回答
fname = input("Enter file name: ")
num_lines = 0
with open(fname, 'r') as f: #lines count
for line in f:
num_lines += 1
num_lines_input = int (input("Enter line numbers: "))
if num_lines_input <= num_lines:
f = open(fname, "r")
for x in range(num_lines_input):
a = f.readline()
print(a)
else:
f = open(fname, "r")
for x in range(num_lines_input):
a = f.readline()
print(a)
print("Don't have", num_lines_input, " lines print as much as you can")
print("Total lines in the text",num_lines)
其他回答
Python 3:
with open("datafile") as myfile:
head = [next(myfile) for x in range(N)]
print(head)
Python 2:
with open("datafile") as myfile:
head = [next(myfile) for x in xrange(N)]
print head
下面是另一种方法(Python 2和3都是):
from itertools import islice
with open("datafile") as myfile:
head = list(islice(myfile, N))
print(head)
#!/usr/bin/python
import subprocess
p = subprocess.Popen(["tail", "-n 3", "passlist"], stdout=subprocess.PIPE)
output, err = p.communicate()
print output
这个方法对我很有效
fname = input("Enter file name: ")
num_lines = 0
with open(fname, 'r') as f: #lines count
for line in f:
num_lines += 1
num_lines_input = int (input("Enter line numbers: "))
if num_lines_input <= num_lines:
f = open(fname, "r")
for x in range(num_lines_input):
a = f.readline()
print(a)
else:
f = open(fname, "r")
for x in range(num_lines_input):
a = f.readline()
print(a)
print("Don't have", num_lines_input, " lines print as much as you can")
print("Total lines in the text",num_lines)
没有特定的方法来读取文件对象暴露的行数。
我想最简单的方法是:
lines =[]
with open(file_name) as f:
lines.extend(f.readline() for i in xrange(N))
如果你想要一些明显(不需要在手册中查找深奥的东西)不需要导入就可以工作的东西,请尝试/except,并且可以在相当大范围的Python 2上工作。X版本(2.2至2.6):
def headn(file_name, n):
"""Like *x head -N command"""
result = []
nlines = 0
assert n >= 1
for line in open(file_name):
result.append(line)
nlines += 1
if nlines >= n:
break
return result
if __name__ == "__main__":
import sys
rval = headn(sys.argv[1], int(sys.argv[2]))
print rval
print len(rval)