我似乎找不到如何更新查询参数与反应路由器不使用<Link/>。hashHistory.push(url)似乎没有注册查询参数,而且似乎不能将查询对象或任何东西作为第二个参数传递。

如何将url从/shop/Clothes/dresses更改为/shop/Clothes/dresses?color=blue在反应路由器没有使用<链接>?

onChange函数真的是侦听查询更改的唯一方法吗?为什么不自动检测和响应查询更改-以参数更改的方式?


当前回答

对于react-router v4.3

const addQuery = (key, value) => {
  let pathname = props.location.pathname;
  // returns path: '/app/books'
  let searchParams = new URLSearchParams(props.location.search);
  // returns the existing query string: '?type=fiction&author=fahid'
  searchParams.set(key, value);
  this.props.history.push({
    pathname: pathname,
    search: searchParams.toString()
  });
};

const removeQuery = (key) => {
  let pathname = props.location.pathname;
  // returns path: '/app/books'
  let searchParams = new URLSearchParams(props.location.search);
  // returns the existing query string: '?type=fiction&author=fahid'
  searchParams.delete(key);
  this.props.history.push({
    pathname: pathname,
    search: searchParams.toString()
  });
};
function SomeComponent({ location }) {
  return <div>
    <button onClick={ () => addQuery('book', 'react')}>search react books</button>
    <button onClick={ () => removeQuery('book')}>remove search</button>
  </div>;
}

要了解更多关于URLSearchParams:

var paramsString = "q=URLUtils.searchParams&topic=api";
var searchParams = new URLSearchParams(paramsString);

//Iterate the search parameters.
for (let p of searchParams) {
  console.log(p);
}

searchParams.has("topic") === true; // true
searchParams.get("topic") === "api"; // true
searchParams.getAll("topic"); // ["api"]
searchParams.get("foo") === null; // true
searchParams.append("topic", "webdev");
searchParams.toString(); // "q=URLUtils.searchParams&topic=api&topic=webdev"
searchParams.set("topic", "More webdev");
searchParams.toString(); // "q=URLUtils.searchParams&topic=More+webdev"
searchParams.delete("topic");
searchParams.toString(); // "q=URLUtils.searchParams"

其他回答

// react-router-dom v6

// import
import { useNavigate, createSearchParams } from 'react-router-dom';

// useSearchParams hook
const [searchParams, setSearchParams] = useSearchParams();

// usage
const params: URLSearchParams = new URLSearchParams();
params.id = '123';
params.color = 'white';

// set new parameters
setSearchParams(params);

! !当心!!这将只更新当前页面上的查询参数,但您将无法导航回(浏览器返回btn)到以前的路由,因为此选项不会更改历史记录。要使此行为到位,请检查之前的答案:https://stackoverflow.com/users/6160270/rakesh-sharma的答案

我目前在一个正在运行的项目中使用react-router v5,不容易迁移到v6。 我写了一个钩子,允许读取和修改一个URL参数,同时保持其他URL参数不变。 数组被视为逗号分隔值的列表: magnifying_glass ?产品=管,猎鹿帽

import { useCallback } from 'react';
import { useHistory } from 'react-router';

const getDecodedUrlParam = (name: string, locationSearch: string, _default?: any) => {
  const params = deserialize(locationSearch);
  const param = params[name];

  if (_default && Array.isArray(_default)) {
    return param
      ? param.split(',').map((v: string) => decodeURIComponent(v))
      : _default;
  }

  return param ? decodeURIComponent(param) : _default;
};

const deserialize = (locationSearch: string): any => {
  if (locationSearch.startsWith('?')) {
    locationSearch = locationSearch.substring(1);
  }
  const parts = locationSearch.split('&');
  return Object.fromEntries(parts.map((part) => part.split('=')));
};

const serialize = (params: any) =>
  Object.entries(params)
    .map(([key, value]) => `${key}=${value}`)
    .join('&');

export const useURLSearchParam = (name: string, _default?: any) => {
  const history = useHistory();
  const value: any = getDecodedUrlParam(name, location.search, _default);
  const _update = useCallback(
    (value: any) => {
      const params = deserialize(location.search);
      if (Array.isArray(value)) {
        params[name] = value.map((v) => encodeURIComponent(v)).join(',');
      } else {
        params[name] = encodeURIComponent(value);
      }
      history.replace({ pathname: location.pathname, search: serialize(params) });
    },
    [history, name]
  );
  const _delete = useCallback(() => {
    const params = deserialize(location.search);
    delete params[name];
    history.replace({ pathname: location.pathname, search: serialize(params) });
  }, [history, name]);
  return [value, _update, _delete];
};

对于React Router v6+,只需使用新的useSearchParams钩子(特别是setSearchParams):

const [searchParams, setSearchParams] = useSearchParams()

setSearchParams(`?${new URLSearchParams({ paramName: 'whatever' })}`)

对于React Router v5使用useHistory:

const history = useHistory()

history.push({
    pathname: '/the-path',
    search: `?${new URLSearchParams({ paramName: 'whatever' })}`
})

URLSearchParams只是一个可选的方便助手。

您可以使用replace功能,而不是在每次更改时推送一个新路由

import React from 'react';
import { useHistory, useLocation } from 'react-router';

const MyComponent = ()=>{
   const history = useHistory();
   const location = useLocation();

   const onChange=(event)=>{
     const {name, value} = event?.target;
     const params = new URLSearchParams({[name]: value });
     history.replace({ pathname: location.pathname, search: params.toString() });       
   }

   return <input name="search" onChange={onChange} />
}

这保留了历史,而不是在每一个变化上都推一条新的道路

更新- 2022年2月(V6)

正如Matrix Spielt指出的那样,useHistory被usenavate取代来进行更改。还有一个方便的方法叫做useSearchParams,我只需要阅读文档,没有运行这个,但这应该可以工作

import React from 'react';
import { useSearchParams } from 'react-router-dom';
// import from react-router should also work but following docs
// import { useSearchParams } from 'react-router';

const MyComponent = ()=>{
   const [searchParams, setSearchParams] = useSearchParams();

   const onChange=(event)=>{
     const {name, value} = event?.target;
     setSearchParams({[name]: value})       
   }

   return <input name="search" onChange={onChange} />
}

DimitriDushkin在GitHub上写道:

import { browserHistory } from 'react-router';

/**
 * @param {Object} query
 */
export const addQuery = (query) => {
  const location = Object.assign({}, browserHistory.getCurrentLocation());

  Object.assign(location.query, query);
  // or simple replace location.query if you want to completely change params

  browserHistory.push(location);
};

/**
 * @param {...String} queryNames
 */
export const removeQuery = (...queryNames) => {
  const location = Object.assign({}, browserHistory.getCurrentLocation());
  queryNames.forEach(q => delete location.query[q]);
  browserHistory.push(location);
};

or

import { withRouter } from 'react-router';
import { addQuery, removeQuery } from '../../utils/utils-router';

function SomeComponent({ location }) {
  return <div style={{ backgroundColor: location.query.paintRed ? '#f00' : '#fff' }}>
    <button onClick={ () => addQuery({ paintRed: 1 })}>Paint red</button>
    <button onClick={ () => removeQuery('paintRed')}>Paint white</button>
  </div>;
}

export default withRouter(SomeComponent);