约翰的答案是正确的。当我处理参数时，我还需要URLSearchParams接口:

this.props.history.push({
    pathname: '/client',
    search: "?" + new URLSearchParams({clientId: clientId}).toString()
})

你可能还需要用一个withRouter HOC来包装你的组件。export default with throuter (YourComponent);

我做了一个简单的钩子来减轻工作。

让我们想象一下你的url是这样的: /搜索吗?起源=主页= 1

function useUrl(param: string) {

    const history = useHistory()
    const { search, pathname } = useLocation()
    const url = new URLSearchParams(search)

    const urlParam = url.get(param)
    const [value, setValue] = useState(urlParam !== null ? urlParam : '')

    function _setValue(val: string){
        url.set(param, val)
        history.replace({ pathname, search: url.toString() }); 
        setValue(val)
    }

    return [value, _setValue]
}

那么实际使用情况:

function SearchPage() {

    const [origin] = useUrl("origin")
    const [page, setPage] = useUrl("page")

    return (
        <div>
            <p>Return to: {origin}</p>
            <p>Current Page: {page}</p>
        </div>
    )
}

当你需要一个模块来轻松地解析你的查询字符串时，推荐使用query-string模块。

http://localhost:3000?token=xxx-xxx-xxx

componentWillMount() {
    var query = queryString.parse(this.props.location.search);
    if (query.token) {
        window.localStorage.setItem("jwt", query.token);
        store.dispatch(push("/"));
    }
}

在这里，我从Node.js服务器重定向回我的客户端后，成功的Google-Passport身份验证，这是重定向回令牌作为查询参数。

我用query-string模块解析它，保存它并更新url中的查询参数，从react-router-redux推送。

我目前在一个正在运行的项目中使用react-router v5，不容易迁移到v6。 我写了一个钩子，允许读取和修改一个URL参数，同时保持其他URL参数不变。 数组被视为逗号分隔值的列表: magnifying_glass ?产品=管,猎鹿帽

import { useCallback } from 'react';
import { useHistory } from 'react-router';

const getDecodedUrlParam = (name: string, locationSearch: string, _default?: any) => {
  const params = deserialize(locationSearch);
  const param = params[name];

  if (_default && Array.isArray(_default)) {
    return param
      ? param.split(',').map((v: string) => decodeURIComponent(v))
      : _default;
  }

  return param ? decodeURIComponent(param) : _default;
};

const deserialize = (locationSearch: string): any => {
  if (locationSearch.startsWith('?')) {
    locationSearch = locationSearch.substring(1);
  }
  const parts = locationSearch.split('&');
  return Object.fromEntries(parts.map((part) => part.split('=')));
};

const serialize = (params: any) =>
  Object.entries(params)
    .map(([key, value]) => `${key}=${value}`)
    .join('&');

export const useURLSearchParam = (name: string, _default?: any) => {
  const history = useHistory();
  const value: any = getDecodedUrlParam(name, location.search, _default);
  const _update = useCallback(
    (value: any) => {
      const params = deserialize(location.search);
      if (Array.isArray(value)) {
        params[name] = value.map((v) => encodeURIComponent(v)).join(',');
      } else {
        params[name] = encodeURIComponent(value);
      }
      history.replace({ pathname: location.pathname, search: serialize(params) });
    },
    [history, name]
  );
  const _delete = useCallback(() => {
    const params = deserialize(location.search);
    delete params[name];
    history.replace({ pathname: location.pathname, search: serialize(params) });
  }, [history, name]);
  return [value, _update, _delete];
};

// react-router-dom v6

// import
import { useNavigate, createSearchParams } from 'react-router-dom';

// useSearchParams hook
const [searchParams, setSearchParams] = useSearchParams();

// usage
const params: URLSearchParams = new URLSearchParams();
params.id = '123';
params.color = 'white';

// set new parameters
setSearchParams(params);

! !当心!!这将只更新当前页面上的查询参数，但您将无法导航回(浏览器返回btn)到以前的路由，因为此选项不会更改历史记录。要使此行为到位，请检查之前的答案:https://stackoverflow.com/users/6160270/rakesh-sharma的答案

使用react-router v4、redux-thunk和react-router-redux(5.0.0-alpha.6)包的示例。

当用户使用搜索功能时，我希望他能够为相同的查询发送url链接给同事。

import { push } from 'react-router-redux';
import qs from 'query-string';

export const search = () => (dispatch) => {
    const query = { firstName: 'John', lastName: 'Doe' };

    //API call to retrieve records
    //...

    const searchString = qs.stringify(query);

    dispatch(push({
        search: searchString
    }))
}