我更喜欢你使用下面的ES6风格的函数:

getQueryStringParams = query => {
    return query
        ? (/^[?#]/.test(query) ? query.slice(1) : query)
            .split('&')
            .reduce((params, param) => {
                    let [key, value] = param.split('=');
                    params[key] = value ? decodeURIComponent(value.replace(/\+/g, ' ')) : '';
                    return params;
                }, {}
            )
        : {}
};

约翰的答案是正确的。当我处理参数时，我还需要URLSearchParams接口:

this.props.history.push({
    pathname: '/client',
    search: "?" + new URLSearchParams({clientId: clientId}).toString()
})

你可能还需要用一个withRouter HOC来包装你的组件。export default with throuter (YourComponent);

您可以使用replace功能，而不是在每次更改时推送一个新路由

import React from 'react';
import { useHistory, useLocation } from 'react-router';

const MyComponent = ()=>{
   const history = useHistory();
   const location = useLocation();

   const onChange=(event)=>{
     const {name, value} = event?.target;
     const params = new URLSearchParams({[name]: value });
     history.replace({ pathname: location.pathname, search: params.toString() });       
   }

   return <input name="search" onChange={onChange} />
}

这保留了历史，而不是在每一个变化上都推一条新的道路

更新- 2022年2月(V6)

正如Matrix Spielt指出的那样，useHistory被usenavate取代来进行更改。还有一个方便的方法叫做useSearchParams，我只需要阅读文档，没有运行这个，但这应该可以工作

import React from 'react';
import { useSearchParams } from 'react-router-dom';
// import from react-router should also work but following docs
// import { useSearchParams } from 'react-router';

const MyComponent = ()=>{
   const [searchParams, setSearchParams] = useSearchParams();

   const onChange=(event)=>{
     const {name, value} = event?.target;
     setSearchParams({[name]: value})       
   }

   return <input name="search" onChange={onChange} />
}

我目前在一个正在运行的项目中使用react-router v5，不容易迁移到v6。 我写了一个钩子，允许读取和修改一个URL参数，同时保持其他URL参数不变。 数组被视为逗号分隔值的列表: magnifying_glass ?产品=管,猎鹿帽

import { useCallback } from 'react';
import { useHistory } from 'react-router';

const getDecodedUrlParam = (name: string, locationSearch: string, _default?: any) => {
  const params = deserialize(locationSearch);
  const param = params[name];

  if (_default && Array.isArray(_default)) {
    return param
      ? param.split(',').map((v: string) => decodeURIComponent(v))
      : _default;
  }

  return param ? decodeURIComponent(param) : _default;
};

const deserialize = (locationSearch: string): any => {
  if (locationSearch.startsWith('?')) {
    locationSearch = locationSearch.substring(1);
  }
  const parts = locationSearch.split('&');
  return Object.fromEntries(parts.map((part) => part.split('=')));
};

const serialize = (params: any) =>
  Object.entries(params)
    .map(([key, value]) => `${key}=${value}`)
    .join('&');

export const useURLSearchParam = (name: string, _default?: any) => {
  const history = useHistory();
  const value: any = getDecodedUrlParam(name, location.search, _default);
  const _update = useCallback(
    (value: any) => {
      const params = deserialize(location.search);
      if (Array.isArray(value)) {
        params[name] = value.map((v) => encodeURIComponent(v)).join(',');
      } else {
        params[name] = encodeURIComponent(value);
      }
      history.replace({ pathname: location.pathname, search: serialize(params) });
    },
    [history, name]
  );
  const _delete = useCallback(() => {
    const params = deserialize(location.search);
    delete params[name];
    history.replace({ pathname: location.pathname, search: serialize(params) });
  }, [history, name]);
  return [value, _update, _delete];
};

就像@Craques解释的那样，我们可以使用替换功能，而不是每次更改都推送一个新路由。然而，在react-router的第6版中，useHistory()被useNavigate()取代，它只返回一个函数。你可以将选项传递给函数，以达到与旧的location.replace()相同的效果:

import { useLocation, useNavigate } from 'react-router-dom';
const to = { pathname: location.pathname, search: newParams.toString() };
navigate(to, { replace: true });

在我的例子中，输入输入字段输出到浏览器的url作为查询字符串，使用React JS功能组件如下所示

import React, { useEffect, useState } from 'react'
import { useHistory } from 'react-router-dom'

const Search = () => {
  const [query, setQuery] = useState('')
  const history = useHistory()

  const onChange = (e) => {
    setQuery(e.target.value)
  }

  useEffect(() => {
    const params = new URLSearchParams()
    if (query) {
      params.append('name', query)
    } else {
      params.delete('name')
    }
    history.push({ search: params.toString() })
  }, [query, history])

  return <input type="text" value={query} onChange={onChange} />
}

export default Search

浏览器URL查询

/搜索吗?name = query_here