我似乎找不到如何更新查询参数与反应路由器不使用<Link/>。hashHistory.push(url)似乎没有注册查询参数,而且似乎不能将查询对象或任何东西作为第二个参数传递。
如何将url从/shop/Clothes/dresses更改为/shop/Clothes/dresses?color=blue在反应路由器没有使用<链接>?
onChange函数真的是侦听查询更改的唯一方法吗?为什么不自动检测和响应查询更改-以参数更改的方式?
我似乎找不到如何更新查询参数与反应路由器不使用<Link/>。hashHistory.push(url)似乎没有注册查询参数,而且似乎不能将查询对象或任何东西作为第二个参数传递。
如何将url从/shop/Clothes/dresses更改为/shop/Clothes/dresses?color=blue在反应路由器没有使用<链接>?
onChange函数真的是侦听查询更改的唯一方法吗?为什么不自动检测和响应查询更改-以参数更改的方式?
当前回答
我目前在一个正在运行的项目中使用react-router v5,不容易迁移到v6。 我写了一个钩子,允许读取和修改一个URL参数,同时保持其他URL参数不变。 数组被视为逗号分隔值的列表: magnifying_glass ?产品=管,猎鹿帽
import { useCallback } from 'react';
import { useHistory } from 'react-router';
const getDecodedUrlParam = (name: string, locationSearch: string, _default?: any) => {
const params = deserialize(locationSearch);
const param = params[name];
if (_default && Array.isArray(_default)) {
return param
? param.split(',').map((v: string) => decodeURIComponent(v))
: _default;
}
return param ? decodeURIComponent(param) : _default;
};
const deserialize = (locationSearch: string): any => {
if (locationSearch.startsWith('?')) {
locationSearch = locationSearch.substring(1);
}
const parts = locationSearch.split('&');
return Object.fromEntries(parts.map((part) => part.split('=')));
};
const serialize = (params: any) =>
Object.entries(params)
.map(([key, value]) => `${key}=${value}`)
.join('&');
export const useURLSearchParam = (name: string, _default?: any) => {
const history = useHistory();
const value: any = getDecodedUrlParam(name, location.search, _default);
const _update = useCallback(
(value: any) => {
const params = deserialize(location.search);
if (Array.isArray(value)) {
params[name] = value.map((v) => encodeURIComponent(v)).join(',');
} else {
params[name] = encodeURIComponent(value);
}
history.replace({ pathname: location.pathname, search: serialize(params) });
},
[history, name]
);
const _delete = useCallback(() => {
const params = deserialize(location.search);
delete params[name];
history.replace({ pathname: location.pathname, search: serialize(params) });
}, [history, name]);
return [value, _update, _delete];
};
其他回答
约翰的答案是正确的。当我处理参数时,我还需要URLSearchParams接口:
this.props.history.push({
pathname: '/client',
search: "?" + new URLSearchParams({clientId: clientId}).toString()
})
你可能还需要用一个withRouter HOC来包装你的组件。export default with throuter (YourComponent);
我目前在一个正在运行的项目中使用react-router v5,不容易迁移到v6。 我写了一个钩子,允许读取和修改一个URL参数,同时保持其他URL参数不变。 数组被视为逗号分隔值的列表: magnifying_glass ?产品=管,猎鹿帽
import { useCallback } from 'react';
import { useHistory } from 'react-router';
const getDecodedUrlParam = (name: string, locationSearch: string, _default?: any) => {
const params = deserialize(locationSearch);
const param = params[name];
if (_default && Array.isArray(_default)) {
return param
? param.split(',').map((v: string) => decodeURIComponent(v))
: _default;
}
return param ? decodeURIComponent(param) : _default;
};
const deserialize = (locationSearch: string): any => {
if (locationSearch.startsWith('?')) {
locationSearch = locationSearch.substring(1);
}
const parts = locationSearch.split('&');
return Object.fromEntries(parts.map((part) => part.split('=')));
};
const serialize = (params: any) =>
Object.entries(params)
.map(([key, value]) => `${key}=${value}`)
.join('&');
export const useURLSearchParam = (name: string, _default?: any) => {
const history = useHistory();
const value: any = getDecodedUrlParam(name, location.search, _default);
const _update = useCallback(
(value: any) => {
const params = deserialize(location.search);
if (Array.isArray(value)) {
params[name] = value.map((v) => encodeURIComponent(v)).join(',');
} else {
params[name] = encodeURIComponent(value);
}
history.replace({ pathname: location.pathname, search: serialize(params) });
},
[history, name]
);
const _delete = useCallback(() => {
const params = deserialize(location.search);
delete params[name];
history.replace({ pathname: location.pathname, search: serialize(params) });
}, [history, name]);
return [value, _update, _delete];
};
在hashHistory的push方法中,可以指定查询参数。例如,
history.push({
pathname: '/dresses',
search: '?color=blue'
})
or
history.push('/dresses?color=blue')
您可以查看这个存储库以获得有关使用历史记录的其他示例
我更喜欢你使用下面的ES6风格的函数:
getQueryStringParams = query => {
return query
? (/^[?#]/.test(query) ? query.slice(1) : query)
.split('&')
.reduce((params, param) => {
let [key, value] = param.split('=');
params[key] = value ? decodeURIComponent(value.replace(/\+/g, ' ')) : '';
return params;
}, {}
)
: {}
};
对于React Router v6+,只需使用新的useSearchParams钩子(特别是setSearchParams):
const [searchParams, setSearchParams] = useSearchParams()
setSearchParams(`?${new URLSearchParams({ paramName: 'whatever' })}`)
对于React Router v5使用useHistory:
const history = useHistory()
history.push({
pathname: '/the-path',
search: `?${new URLSearchParams({ paramName: 'whatever' })}`
})
URLSearchParams只是一个可选的方便助手。