我似乎找不到如何更新查询参数与反应路由器不使用<Link/>。hashHistory.push(url)似乎没有注册查询参数,而且似乎不能将查询对象或任何东西作为第二个参数传递。
如何将url从/shop/Clothes/dresses更改为/shop/Clothes/dresses?color=blue在反应路由器没有使用<链接>?
onChange函数真的是侦听查询更改的唯一方法吗?为什么不自动检测和响应查询更改-以参数更改的方式?
我似乎找不到如何更新查询参数与反应路由器不使用<Link/>。hashHistory.push(url)似乎没有注册查询参数,而且似乎不能将查询对象或任何东西作为第二个参数传递。
如何将url从/shop/Clothes/dresses更改为/shop/Clothes/dresses?color=blue在反应路由器没有使用<链接>?
onChange函数真的是侦听查询更改的唯一方法吗?为什么不自动检测和响应查询更改-以参数更改的方式?
当前回答
我目前在一个正在运行的项目中使用react-router v5,不容易迁移到v6。 我写了一个钩子,允许读取和修改一个URL参数,同时保持其他URL参数不变。 数组被视为逗号分隔值的列表: magnifying_glass ?产品=管,猎鹿帽
import { useCallback } from 'react';
import { useHistory } from 'react-router';
const getDecodedUrlParam = (name: string, locationSearch: string, _default?: any) => {
const params = deserialize(locationSearch);
const param = params[name];
if (_default && Array.isArray(_default)) {
return param
? param.split(',').map((v: string) => decodeURIComponent(v))
: _default;
}
return param ? decodeURIComponent(param) : _default;
};
const deserialize = (locationSearch: string): any => {
if (locationSearch.startsWith('?')) {
locationSearch = locationSearch.substring(1);
}
const parts = locationSearch.split('&');
return Object.fromEntries(parts.map((part) => part.split('=')));
};
const serialize = (params: any) =>
Object.entries(params)
.map(([key, value]) => `${key}=${value}`)
.join('&');
export const useURLSearchParam = (name: string, _default?: any) => {
const history = useHistory();
const value: any = getDecodedUrlParam(name, location.search, _default);
const _update = useCallback(
(value: any) => {
const params = deserialize(location.search);
if (Array.isArray(value)) {
params[name] = value.map((v) => encodeURIComponent(v)).join(',');
} else {
params[name] = encodeURIComponent(value);
}
history.replace({ pathname: location.pathname, search: serialize(params) });
},
[history, name]
);
const _delete = useCallback(() => {
const params = deserialize(location.search);
delete params[name];
history.replace({ pathname: location.pathname, search: serialize(params) });
}, [history, name]);
return [value, _update, _delete];
};
其他回答
DimitriDushkin在GitHub上写道:
import { browserHistory } from 'react-router';
/**
* @param {Object} query
*/
export const addQuery = (query) => {
const location = Object.assign({}, browserHistory.getCurrentLocation());
Object.assign(location.query, query);
// or simple replace location.query if you want to completely change params
browserHistory.push(location);
};
/**
* @param {...String} queryNames
*/
export const removeQuery = (...queryNames) => {
const location = Object.assign({}, browserHistory.getCurrentLocation());
queryNames.forEach(q => delete location.query[q]);
browserHistory.push(location);
};
or
import { withRouter } from 'react-router';
import { addQuery, removeQuery } from '../../utils/utils-router';
function SomeComponent({ location }) {
return <div style={{ backgroundColor: location.query.paintRed ? '#f00' : '#fff' }}>
<button onClick={ () => addQuery({ paintRed: 1 })}>Paint red</button>
<button onClick={ () => removeQuery('paintRed')}>Paint white</button>
</div>;
}
export default withRouter(SomeComponent);
// react-router-dom v6
// import
import { useNavigate, createSearchParams } from 'react-router-dom';
// useSearchParams hook
const [searchParams, setSearchParams] = useSearchParams();
// usage
const params: URLSearchParams = new URLSearchParams();
params.id = '123';
params.color = 'white';
// set new parameters
setSearchParams(params);
! !当心!!这将只更新当前页面上的查询参数,但您将无法导航回(浏览器返回btn)到以前的路由,因为此选项不会更改历史记录。要使此行为到位,请检查之前的答案:https://stackoverflow.com/users/6160270/rakesh-sharma的答案
您可以使用replace功能,而不是在每次更改时推送一个新路由
import React from 'react';
import { useHistory, useLocation } from 'react-router';
const MyComponent = ()=>{
const history = useHistory();
const location = useLocation();
const onChange=(event)=>{
const {name, value} = event?.target;
const params = new URLSearchParams({[name]: value });
history.replace({ pathname: location.pathname, search: params.toString() });
}
return <input name="search" onChange={onChange} />
}
这保留了历史,而不是在每一个变化上都推一条新的道路
更新- 2022年2月(V6)
正如Matrix Spielt指出的那样,useHistory被usenavate取代来进行更改。还有一个方便的方法叫做useSearchParams,我只需要阅读文档,没有运行这个,但这应该可以工作
import React from 'react';
import { useSearchParams } from 'react-router-dom';
// import from react-router should also work but following docs
// import { useSearchParams } from 'react-router';
const MyComponent = ()=>{
const [searchParams, setSearchParams] = useSearchParams();
const onChange=(event)=>{
const {name, value} = event?.target;
setSearchParams({[name]: value})
}
return <input name="search" onChange={onChange} />
}
使用React Router V6,我们可以像这样实现它
import { useNavigate, createSearchParams } from 'react-router-dom';
/* In React Component */
const navigate = useNavigate();
const params = {
color: 'blue',
};
const options = {
pathname: '/shop/Clothes/dresses',
search: `?${createSearchParams(params)}`,
};
navigate(options, { replace: true });
你可以使用钩子useHistory 确保你使用的是基于函数的组件 在顶部导入这个
import {useHistory} from "react-router-dom"
在你的组件中,
const history = useHistory()
history.push({
pathname: window.location.pathname,
search: '?color=blue'
})