我试图开发一个JavaScript游戏引擎,我遇到了这个问题:
当我按空格键时,角色会跳跃。 当我按下→角色向右移动。
问题是,当我按右键,然后按空格键时,角色会跳跃,然后停止移动。
我使用keydown函数来按下键。如何检查是否同时按下了多个键?
我试图开发一个JavaScript游戏引擎,我遇到了这个问题:
当我按空格键时,角色会跳跃。 当我按下→角色向右移动。
问题是,当我按右键,然后按空格键时,角色会跳跃,然后停止移动。
我使用keydown函数来按下键。如何检查是否同时按下了多个键?
当前回答
Easiest, and most Effective Method
//check key press
function loop(){
//>>key<< can be any string representing a letter eg: "a", "b", "ctrl",
if(map[*key*]==true){
//do something
}
//multiple keys
if(map["x"]==true&&map["ctrl"]==true){
console.log("x, and ctrl are being held down together")
}
}
//>>>variable which will hold all key information<<
var map={}
//Key Event Listeners
window.addEventListener("keydown", btnd, true);
window.addEventListener("keyup", btnu, true);
//Handle button down
function btnd(e) {
map[e.key] = true;
}
//Handle Button up
function btnu(e) {
map[e.key] = false;
}
//>>>If you want to see the state of every Key on the Keybaord<<<
setInterval(() => {
for (var x in map) {
log += "|" + x + "=" + map[x];
}
console.log(log);
log = "";
}, 300);
其他回答
我使用这种方式(必须检查按下Shift + Ctrl的地方):
// create some object to save all pressed keys
var keys = {
shift: false,
ctrl: false
};
$(document.body).keydown(function(event) {
// save status of the button 'pressed' == 'true'
if (event.keyCode == 16) {
keys["shift"] = true;
} else if (event.keyCode == 17) {
keys["ctrl"] = true;
}
if (keys["shift"] && keys["ctrl"]) {
$("#convert").trigger("click"); // or do anything else
}
});
$(document.body).keyup(function(event) {
// reset status of the button 'released' == 'false'
if (event.keyCode == 16) {
keys["shift"] = false;
} else if (event.keyCode == 17) {
keys["ctrl"] = false;
}
});
如果其中一个按键是Alt / Crtl / Shift,你可以使用这个方法:
document.body.addEventListener('keydown', keysDown(actions) );
function actions() {
// do stuff here
}
// simultaneous pressing Alt + R
function keysDown (cb) {
return function (zEvent) {
if (zEvent.altKey && zEvent.code === "KeyR" ) {
return cb()
}
}
}
谁需要完整的示例代码。左+右补充道
var keyPressed = {};
document.addEventListener('keydown', function(e) {
keyPressed[e.key + e.location] = true;
if(keyPressed.Shift1 == true && keyPressed.Control1 == true){
// Left shift+CONTROL pressed!
keyPressed = {}; // reset key map
}
if(keyPressed.Shift2 == true && keyPressed.Control2 == true){
// Right shift+CONTROL pressed!
keyPressed = {};
}
}, false);
document.addEventListener('keyup', function(e) {
keyPressed[e.key + e.location] = false;
keyPressed = {};
}, false);
只是让某些东西更稳定:
var keys = [];
$(document).keydown(function (e) {
if(e.which == 32 || e.which == 70){
keys.push(e.which);
if(keys.length == 2 && keys.indexOf(32) != -1 && keys.indexOf(70) != -1){
alert("it WORKS !!"); //MAKE SOMETHING HERE---------------->
keys.length = 0;
}else if((keys.indexOf(32) == -1 && keys.indexOf(70) != -1) || (keys.indexOf(32) != -1 && keys.indexOf(70) == -1) && (keys.indexOf(32) > 1 || keys.indexOf(70) > 1)){
}else{
keys.length = 0;
}
}else{
keys.length = 0;
}
});
$(document).ready(function () {
// using ascii 17 for ctrl, 18 for alt and 83 for "S"
// ctr+alt+S
var map = { 17: false, 18: false, 83: false };
$(document).keyup(function (e) {
if (e.keyCode in map) {
map[e.keyCode] = true;
if (map[17] && map[18] && map[83]) {
// Write your own code here, what you want to do
map[17] = false;
map[18] = false;
map[83] = false;
}
}
else {
// if u press any other key apart from that "map" will reset.
map[17] = false;
map[18] = false;
map[83] = false;
}
});
});