我试图开发一个JavaScript游戏引擎,我遇到了这个问题:

当我按空格键时,角色会跳跃。 当我按下→角色向右移动。

问题是,当我按右键,然后按空格键时,角色会跳跃,然后停止移动。

我使用keydown函数来按下键。如何检查是否同时按下了多个键?


当前回答

如果有人需要简单的解决方案。

let keys = [];
document.addEventListener("keydown", (e) => {
  keys.push(e.key);
  if (keys.includes("Control") && keys.includes("o")) {
    console.log("open");
  }

  if (keys.includes("Control") && keys.includes("s")) {
    console.log("save");
  }
});

// clear the keys array
document.addEventListener("keyup", () => {
  keys = [];
});

其他回答

谁需要完整的示例代码。左+右补充道

var keyPressed = {};
document.addEventListener('keydown', function(e) {

   keyPressed[e.key + e.location] = true;

    if(keyPressed.Shift1 == true && keyPressed.Control1 == true){
        // Left shift+CONTROL pressed!
        keyPressed = {}; // reset key map
    }
    if(keyPressed.Shift2 == true && keyPressed.Control2 == true){
        // Right shift+CONTROL pressed!
        keyPressed = {};
    }

}, false);

document.addEventListener('keyup', function(e) {
   keyPressed[e.key + e.location] = false;

   keyPressed = {};
}, false);

如果你想找到任何按键事件与控制键,你可以这样做

onkeypress = (e) =>{
console.log(e);
if(e.ctrlKey && e.code == "KeyZ"){
    document.write("do somthing")
} }

我使用case, if和bool。我有一个项目,这对我很有效


window.addEventListener("keydown", onKeyDown, false);
window.addEventListener("keyup", onKeyUp, false);

function onKeyDown(event) {
  var keyCode = event.keyCode;
  switch (keyCode) {
    case 68: //D
      keyd = true;
      break;
    case 32: //spaaaaaaaaaaaaaaace
      keyspace = true;
      break;
    case 65: //A
      keya = true;
      break;
    case 37:
      keya = true;
      break;
    case 38:
      keyspace = true;
      break;
    case 39:
      keyd = true;
      break;
  }
}

function onKeyUp(event) {
  var keyCode = event.keyCode;

  switch (keyCode) {
    case 68: //dddddd
      keyd = false;
      break;
    case 32: //spaaaaaaaaaaaaaaaaaaaaaace
      keyspace = false;
      break;
    case 65: //aaaaa
      keya = false;
      break;
    case 37:
      keya = false;
      break;
    case 38:
      keyspace = false;
      break;
    case 39:
      keyd = false;
      break;
  }
}

如果有人需要简单的解决方案。

let keys = [];
document.addEventListener("keydown", (e) => {
  keys.push(e.key);
  if (keys.includes("Control") && keys.includes("o")) {
    console.log("open");
  }

  if (keys.includes("Control") && keys.includes("s")) {
    console.log("save");
  }
});

// clear the keys array
document.addEventListener("keyup", () => {
  keys = [];
});
document.onkeydown = keydown; 

function keydown (evt) { 

    if (!evt) evt = event; 

    if (evt.ctrlKey && evt.altKey && evt.keyCode === 115) {

        alert("CTRL+ALT+F4"); 

    } else if (evt.shiftKey && evt.keyCode === 9) { 

        alert("Shift+TAB");

    } 

}