要获取完整信息：列名、表名以及表的架构。。

SELECT COLUMN_NAME, TABLE_NAME, TABLE_SCHEMA
FROM INFORMATION_SCHEMA.COLUMNS 
WHERE COLUMN_NAME LIKE '%col_Name%'

这应该是有效的：

SELECT name 
FROM sysobjects 
WHERE id IN ( SELECT id 
              FROM syscolumns 
              WHERE name like '%column_name%' )

搜索表：

SELECT      c.name  AS 'ColumnName'
            ,t.name AS 'TableName'
FROM        sys.columns c
JOIN        sys.tables  t   ON c.object_id = t.object_id
WHERE       c.name LIKE '%MyName%'
ORDER BY    TableName
            ,ColumnName;

搜索表和视图：

SELECT      COLUMN_NAME AS 'ColumnName'
            ,TABLE_NAME AS  'TableName'
FROM        INFORMATION_SCHEMA.COLUMNS
WHERE       COLUMN_NAME LIKE '%MyName%'
ORDER BY    TableName
            ,ColumnName;

SELECT table_schema + '.' + table_name,
       column_name
FROM   [yourdatabase].information_schema.columns
WHERE  column_name LIKE '%myName%' 

这将为您提供需要查找的列的表名。

希望这不是一个重复的答案，但我想做的是在sql语句中生成一个sql语句，这将允许我搜索我要查找的值（而不仅仅是具有这些字段名称的表（因为通常我需要删除与我要查找列名称的id相关的任何信息）：

  SELECT  'Select * from ' + t.name + ' where ' + c.name + ' = 148' AS SQLToRun
  FROM sys.columns c, c.name as ColName, t.name as TableName
  JOIN sys.tables t 
     ON c.object_id = t.object_id
  WHERE c.name LIKE '%ProjectID%'

然后我可以复制并粘贴运行我的第一列“SQLToRun”。。。然后我将“Select*from”替换为“Delete from”，它允许我删除对该给定ID的任何引用！将这些结果写入文件，以备不时之需。

注意***在运行delete语句之前，请确保消除所有bakup表。。。

  SELECT  'Delete from ' + t.name + ' where ' + c.name + ' = 148' AS SQLToRun
  FROM sys.columns c, c.name as ColName, t.name as TableName
  JOIN sys.tables t 
     ON c.object_id = t.object_id
  WHERE c.name LIKE '%ProjectID%'

您可以通过column_name过滤器从INFORMATION_SCHEMA.COLUMNS中找到它

Select DISTINCT TABLE_NAME as TableName,COLUMN_NAME as ColumnName
     From INFORMATION_SCHEMA.COLUMNS Where column_name like '%myname%'