是否可以查询包含以下列的表名

LIKE '%myName%'

?


当前回答

我不知道为什么很多人建议使用sys.columns加入sys.table。

您可以使用以下代码:

SELECT Object_name(object_id) AS TableName,
       *
FROM   sys.columns
WHERE  NAME LIKE '%MyName%' 

or

如果还需要架构名称:

SELECT *
FROM   information_schema.columns
WHERE  column_name LIKE '%MyName%' 

其他回答

USE AdventureWorks

GO

SELECT t.name AS table_name, SCHEMA_NAME(schema_id) AS schema_name,
 c.name AS column_name
FROM sys.tables AS t
INNER JOIN sys.columns c ON t.OBJECT_ID = c.OBJECT_ID
WHERE c.name LIKE '%EmployeeID%'
ORDER BY schema_name, table_name; 

来自Pinal Sir博客

我不知道为什么很多人建议使用sys.columns加入sys.table。

您可以使用以下代码:

SELECT Object_name(object_id) AS TableName,
       *
FROM   sys.columns
WHERE  NAME LIKE '%MyName%' 

or

如果还需要架构名称:

SELECT *
FROM   information_schema.columns
WHERE  column_name LIKE '%MyName%' 

这应该是有效的:

SELECT name 
FROM sysobjects 
WHERE id IN ( SELECT id 
              FROM syscolumns 
              WHERE name like '%column_name%' )

希望这不是一个重复的答案,但我想做的是在sql语句中生成一个sql语句,这将允许我搜索我要查找的值(而不仅仅是具有这些字段名称的表(因为通常我需要删除与我要查找列名称的id相关的任何信息):

  SELECT  'Select * from ' + t.name + ' where ' + c.name + ' = 148' AS SQLToRun
  FROM sys.columns c, c.name as ColName, t.name as TableName
  JOIN sys.tables t 
     ON c.object_id = t.object_id
  WHERE c.name LIKE '%ProjectID%'

然后我可以复制并粘贴运行我的第一列“SQLToRun”。。。然后我将“Select*from”替换为“Delete from”,它允许我删除对该给定ID的任何引用!将这些结果写入文件,以备不时之需。

注意***在运行delete语句之前,请确保消除所有bakup表。。。

  SELECT  'Delete from ' + t.name + ' where ' + c.name + ' = 148' AS SQLToRun
  FROM sys.columns c, c.name as ColName, t.name as TableName
  JOIN sys.tables t 
     ON c.object_id = t.object_id
  WHERE c.name LIKE '%ProjectID%'
DECLARE @columnName as varchar(100)
SET @columnName = 'ColumnName'

SELECT t.name AS Table, c.name AS Column,
ty.name AS Type, c.max_length AS Length
FROM sys.tables AS t
INNER JOIN sys.columns c ON t.OBJECT_ID = c.OBJECT_ID
INNER JOIN sys.types ty ON c.system_type_id = ty.system_type_id
WHERE c.name LIKE @columnName
ORDER BY t.name, c.name