是否可以查询包含以下列的表名
LIKE '%myName%'
?
是否可以查询包含以下列的表名
LIKE '%myName%'
?
当前回答
select
s.[name] 'Schema',
t.[name] 'Table',
c.[name] 'Column',
d.[name] 'Data Type',
c.[max_length] 'Length',
d.[max_length] 'Max Length',
d.[precision] 'Precision',
c.[is_identity] 'Is Id',
c.[is_nullable] 'Is Nullable',
c.[is_computed] 'Is Computed',
d.[is_user_defined] 'Is UserDefined',
t.[modify_date] 'Date Modified',
t.[create_date] 'Date created'
from sys.schemas s
inner join sys.tables t
on s.schema_id = t.schema_id
inner join sys.columns c
on t.object_id = c.object_id
inner join sys.types d
on c.user_type_id = d.user_type_id
where c.name like '%ColumnName%'
这里将为您提供一些有关架构、表和列的额外信息,您可以选择或不选择在where子句中使用额外条件进行筛选
and c.is_nullable = 0
您可以添加其他条件,我也以这种垂直方式添加了select子句中的列,以便根据您的需要轻松地重新排序、删除、重命名或添加其他列。或者,您可以使用T.Name搜索表格。它非常可定制。
享受
其他回答
Create table #yourcolumndetails(
DBaseName varchar(100),
TableSchema varchar(50),
TableName varchar(100),
ColumnName varchar(100),
DataType varchar(100),
CharMaxLength varchar(100))
EXEC sp_MSForEachDB @command1='USE [?];
INSERT INTO #yourcolumndetails SELECT
Table_Catalog
,Table_Schema
,Table_Name
,Column_Name
,Data_Type
,Character_Maximum_Length
FROM INFORMATION_SCHEMA.COLUMNS
WHERE COLUMN_NAME like ''origin'''
select * from #yourcolumndetails
Drop table #yourcolumndetails
我想要一些不会让我眼睛流血的桌子和视图。
查询
SELECT
t.TABLE_TYPE AS [Type],
c.TABLE_NAME AS [Object],
c.COLUMN_NAME AS [Column]
FROM
INFORMATION_SCHEMA.COLUMNS AS c
LEFT JOIN INFORMATION_SCHEMA.TABLES AS t ON
t.TABLE_CATALOG = c.TABLE_CATALOG AND
t.TABLE_SCHEMA = c.TABLE_SCHEMA AND
t.TABLE_NAME = c.TABLE_NAME
WHERE
c.COLUMN_NAME LIKE '%myName%'
ORDER BY
[Type],
[Object],
[Column]
后果
Type Object Column
----------------------------
BASE TABLE Table1 myName1
BASE TABLE Table2 myName2
VIEW View1 myName1
VIEW View2 myName2
SELECT t.name AS table_name,
SCHEMA_NAME(schema_id) AS schema_name,
c.name AS column_name
FROM sys.tables AS t INNER JOIN sys.columns c ON t.OBJECT_ID = c.OBJECT_ID
WHERE c.name LIKE '%Label%'
ORDER BY schema_name, table_name;
它将返回table_name、schema_name、column_name
SELECT t.name AS table_name,
SCHEMA_NAME(schema_id) AS schema_name,
c.name AS column_name
FROM sys.tables AS t
INNER JOIN sys.columns c
ON t.object_id = c.object_id
WHERE c.name LIKE '%colName%'
ORDER BY schema_name,
table_name;
您可以通过column_name过滤器从INFORMATION_SCHEMA.COLUMNS中找到它
Select DISTINCT TABLE_NAME as TableName,COLUMN_NAME as ColumnName
From INFORMATION_SCHEMA.COLUMNS Where column_name like '%myname%'