DECLARE @columnName as varchar(100)
SET @columnName = 'ColumnName'

SELECT t.name AS Table, c.name AS Column,
ty.name AS Type, c.max_length AS Length
FROM sys.tables AS t
INNER JOIN sys.columns c ON t.OBJECT_ID = c.OBJECT_ID
INNER JOIN sys.types ty ON c.system_type_id = ty.system_type_id
WHERE c.name LIKE @columnName
ORDER BY t.name, c.name

这应该是有效的：

SELECT name 
FROM sysobjects 
WHERE id IN ( SELECT id 
              FROM syscolumns 
              WHERE name like '%column_name%' )

在MS SQL Server数据库中，使用此查询获取包含输入文本的表和相应的列名：

SELECT t.name AS tableName, c.name AS columnName 
FROM sys.tables as t 
INNER JOIN sys.columns AS c ON t.object_id=c.object_id 
WHERE c.name LIKE '%<your_search_string>%'

Create table #yourcolumndetails(
DBaseName varchar(100), 
TableSchema varchar(50), 
TableName varchar(100),
ColumnName varchar(100), 
DataType varchar(100), 
CharMaxLength varchar(100))

EXEC sp_MSForEachDB @command1='USE [?];
    INSERT INTO #yourcolumndetails SELECT
    Table_Catalog
    ,Table_Schema
    ,Table_Name
    ,Column_Name
    ,Data_Type
    ,Character_Maximum_Length
    FROM INFORMATION_SCHEMA.COLUMNS
    WHERE COLUMN_NAME like ''origin'''

select * from #yourcolumndetails
Drop table #yourcolumndetails

我们还可以使用以下语法：-

select * from INFORMATION_SCHEMA.COLUMNS 
where COLUMN_NAME like '%clientid%' 
order by TABLE_NAME

USE AdventureWorks

GO

SELECT t.name AS table_name, SCHEMA_NAME(schema_id) AS schema_name,
 c.name AS column_name
FROM sys.tables AS t
INNER JOIN sys.columns c ON t.OBJECT_ID = c.OBJECT_ID
WHERE c.name LIKE '%EmployeeID%'
ORDER BY schema_name, table_name; 

来自Pinal Sir博客