是否可以查询包含以下列的表名
LIKE '%myName%'
?
是否可以查询包含以下列的表名
LIKE '%myName%'
?
当前回答
我们还可以使用以下语法:-
select * from INFORMATION_SCHEMA.COLUMNS
where COLUMN_NAME like '%clientid%'
order by TABLE_NAME
其他回答
USE AdventureWorks
GO
SELECT t.name AS table_name, SCHEMA_NAME(schema_id) AS schema_name,
c.name AS column_name
FROM sys.tables AS t
INNER JOIN sys.columns c ON t.OBJECT_ID = c.OBJECT_ID
WHERE c.name LIKE '%EmployeeID%'
ORDER BY schema_name, table_name;
来自Pinal Sir博客
在MS SQL Server数据库中,使用此查询获取包含输入文本的表和相应的列名:
SELECT t.name AS tableName, c.name AS columnName
FROM sys.tables as t
INNER JOIN sys.columns AS c ON t.object_id=c.object_id
WHERE c.name LIKE '%<your_search_string>%'
要获取完整信息:列名、表名以及表的架构。。
SELECT COLUMN_NAME, TABLE_NAME, TABLE_SCHEMA
FROM INFORMATION_SCHEMA.COLUMNS
WHERE COLUMN_NAME LIKE '%col_Name%'
希望这不是一个重复的答案,但我想做的是在sql语句中生成一个sql语句,这将允许我搜索我要查找的值(而不仅仅是具有这些字段名称的表(因为通常我需要删除与我要查找列名称的id相关的任何信息):
SELECT 'Select * from ' + t.name + ' where ' + c.name + ' = 148' AS SQLToRun
FROM sys.columns c, c.name as ColName, t.name as TableName
JOIN sys.tables t
ON c.object_id = t.object_id
WHERE c.name LIKE '%ProjectID%'
然后我可以复制并粘贴运行我的第一列“SQLToRun”。。。然后我将“Select*from”替换为“Delete from”,它允许我删除对该给定ID的任何引用!将这些结果写入文件,以备不时之需。
注意***在运行delete语句之前,请确保消除所有bakup表。。。
SELECT 'Delete from ' + t.name + ' where ' + c.name + ' = 148' AS SQLToRun
FROM sys.columns c, c.name as ColName, t.name as TableName
JOIN sys.tables t
ON c.object_id = t.object_id
WHERE c.name LIKE '%ProjectID%'
您可以在SQL Server中使用以下查询。
SELECT column_name AS 'ColumnName',
table_name AS 'TableName'
FROM information_schema.columns
WHERE column_name LIKE '%columnname%'
AND table_schema = 'schema'
ORDER BY tablename,
columnname;