是否可以查询包含以下列的表名
LIKE '%myName%'
?
是否可以查询包含以下列的表名
LIKE '%myName%'
?
当前回答
SELECT t.name AS table_name,
SCHEMA_NAME(schema_id) AS schema_name,
c.name AS column_name
FROM sys.tables AS t INNER JOIN sys.columns c ON t.OBJECT_ID = c.OBJECT_ID
WHERE c.name LIKE '%Label%'
ORDER BY schema_name, table_name;
其他回答
在MS SQL中,可以编写以下行来检查特定表的列名:
sp_help your_tablename
或者,您可以先在查询窗口中选择表名(突出显示模式和表名),然后按下下面的组合键:
Alt + F1
您可以通过column_name过滤器从INFORMATION_SCHEMA.COLUMNS中找到它
Select DISTINCT TABLE_NAME as TableName,COLUMN_NAME as ColumnName
From INFORMATION_SCHEMA.COLUMNS Where column_name like '%myname%'
这是你问题的答案
SELECT c.name AS ColumnName, t.name AS TableName
FROM sys.columns c
JOIN sys.tables t ON c.object_id = t.object_id
WHERE c.name LIKE '%myName%';
以下查询将为您提供字段名为“%myName”的数据库的确切表名。
SELECT distinct(TABLE_NAME)
FROM INFORMATION_SCHEMA.COLUMNS
WHERE COLUMN_NAME LIKE '%myName%'
为了改进上面的答案,我还包括了视图,并将模式和表/视图连接在一起,使结果更加明显。
DECLARE @COLUMNNAME AS VARCHAR(100);
SET @COLUMNNAME = '%Absence%';
SELECT CASE
WHEN [T].[NAME] IS NULL
THEN 'View'
WHEN [T].[NAME] = ''
THEN 'View'
ELSE 'Table'
END AS [TYPE], '[' + [S].[NAME] + '].' + '[' + CASE
WHEN [T].[NAME] IS NULL
THEN [V].[NAME]
WHEN [T].[NAME] = ''
THEN [V].[NAME]
ELSE [T].[NAME]
END + ']' AS [TABLE], [C].[NAME] AS [COLUMN]
FROM [SYS].[SCHEMAS] AS [S] LEFT JOIN [SYS].[TABLES] AS [T] ON [S].SCHEMA_ID = [T].SCHEMA_ID
LEFT JOIN [SYS].[VIEWS] AS [V] ON [S].SCHEMA_ID = [V].SCHEMA_ID
INNER JOIN [SYS].[COLUMNS] AS [C] ON [T].OBJECT_ID = [C].OBJECT_ID
OR
[V].OBJECT_ID = [C].OBJECT_ID
INNER JOIN [SYS].[TYPES] AS [TY] ON [C].[SYSTEM_TYPE_ID] = [TY].[SYSTEM_TYPE_ID]
WHERE [C].[NAME] LIKE @COLUMNNAME
GROUP BY '[' + [S].[NAME] + '].' + '[' + CASE
WHEN [T].[NAME] IS NULL
THEN [V].[NAME]
WHEN [T].[NAME] = ''
THEN [V].[NAME]
ELSE [T].[NAME]
END + ']', [T].[NAME], [C].[NAME], [S].[NAME]
ORDER BY '[' + [S].[NAME] + '].' + '[' + CASE
WHEN [T].[NAME] IS NULL
THEN [V].[NAME]
WHEN [T].[NAME] = ''
THEN [V].[NAME]
ELSE [T].[NAME]
END + ']', CASE
WHEN [T].[NAME] IS NULL
THEN 'View'
WHEN [T].[NAME] = ''
THEN 'View'
ELSE 'Table'
END, [T].[NAME], [C].[NAME];