SELECT t.name AS table_name, 
    SCHEMA_NAME(schema_id) AS schema_name,
    c.name AS column_name
FROM sys.tables AS t INNER JOIN sys.columns c ON t.OBJECT_ID = c.OBJECT_ID
WHERE c.name LIKE '%Label%'
ORDER BY schema_name, table_name;

这应该是有效的：

SELECT name 
FROM sysobjects 
WHERE id IN ( SELECT id 
              FROM syscolumns 
              WHERE name like '%column_name%' )

SELECT COLUMN_NAME, TABLE_NAME
  FROM INFORMATION_SCHEMA.COLUMNS    
 WHERE COLUMN_NAME LIKE '%myName%'

我想要一些不会让我眼睛流血的桌子和视图。

查询

SELECT
    t.TABLE_TYPE AS [Type],
    c.TABLE_NAME AS [Object],
    c.COLUMN_NAME AS [Column]
FROM
    INFORMATION_SCHEMA.COLUMNS AS c
    LEFT JOIN INFORMATION_SCHEMA.TABLES AS t ON
        t.TABLE_CATALOG = c.TABLE_CATALOG AND 
        t.TABLE_SCHEMA = c.TABLE_SCHEMA AND
        t.TABLE_NAME = c.TABLE_NAME
WHERE
    c.COLUMN_NAME LIKE '%myName%'
ORDER BY
    [Type],
    [Object],
    [Column]

后果

Type        Object   Column
----------------------------
BASE TABLE  Table1   myName1
BASE TABLE  Table2   myName2
VIEW        View1    myName1
VIEW        View2    myName2

以下查询将为您提供字段名为“%myName”的数据库的确切表名。

SELECT distinct(TABLE_NAME)
  FROM INFORMATION_SCHEMA.COLUMNS    
 WHERE COLUMN_NAME LIKE '%myName%'

USE AdventureWorks

GO

SELECT t.name AS table_name, SCHEMA_NAME(schema_id) AS schema_name,
 c.name AS column_name
FROM sys.tables AS t
INNER JOIN sys.columns c ON t.OBJECT_ID = c.OBJECT_ID
WHERE c.name LIKE '%EmployeeID%'
ORDER BY schema_name, table_name; 

来自Pinal Sir博客