SELECT  [TABLE_NAME] ,
        [INFORMATION_SCHEMA].COLUMNS.COLUMN_NAME
FROM    INFORMATION_SCHEMA.COLUMNS
WHERE   INFORMATION_SCHEMA.COLUMNS.COLUMN_NAME LIKE '%NAME%' ;

Create table #yourcolumndetails(
DBaseName varchar(100), 
TableSchema varchar(50), 
TableName varchar(100),
ColumnName varchar(100), 
DataType varchar(100), 
CharMaxLength varchar(100))

EXEC sp_MSForEachDB @command1='USE [?];
    INSERT INTO #yourcolumndetails SELECT
    Table_Catalog
    ,Table_Schema
    ,Table_Name
    ,Column_Name
    ,Data_Type
    ,Character_Maximum_Length
    FROM INFORMATION_SCHEMA.COLUMNS
    WHERE COLUMN_NAME like ''origin'''

select * from #yourcolumndetails
Drop table #yourcolumndetails

这应该是有效的：

SELECT name 
FROM sysobjects 
WHERE id IN ( SELECT id 
              FROM syscolumns 
              WHERE name like '%column_name%' )

我想要一些不会让我眼睛流血的桌子和视图。

查询

SELECT
    t.TABLE_TYPE AS [Type],
    c.TABLE_NAME AS [Object],
    c.COLUMN_NAME AS [Column]
FROM
    INFORMATION_SCHEMA.COLUMNS AS c
    LEFT JOIN INFORMATION_SCHEMA.TABLES AS t ON
        t.TABLE_CATALOG = c.TABLE_CATALOG AND 
        t.TABLE_SCHEMA = c.TABLE_SCHEMA AND
        t.TABLE_NAME = c.TABLE_NAME
WHERE
    c.COLUMN_NAME LIKE '%myName%'
ORDER BY
    [Type],
    [Object],
    [Column]

后果

Type        Object   Column
----------------------------
BASE TABLE  Table1   myName1
BASE TABLE  Table2   myName2
VIEW        View1    myName1
VIEW        View2    myName2

它将返回table_name、schema_name、column_name

SELECT t.name AS table_name,
SCHEMA_NAME(schema_id) AS schema_name,
c.name AS column_name
FROM sys.tables AS t
INNER JOIN sys.columns c
ON t.object_id = c.object_id
WHERE c.name LIKE '%colName%'
ORDER BY schema_name,
table_name;

为此，我们可以使用sp_columns。

sp_columns 'table name', null, null, '%column name%'