您可以通过column_name过滤器从INFORMATION_SCHEMA.COLUMNS中找到它

Select DISTINCT TABLE_NAME as TableName,COLUMN_NAME as ColumnName
     From INFORMATION_SCHEMA.COLUMNS Where column_name like '%myname%'

DECLARE @columnName as varchar(100)
SET @columnName = 'ColumnName'

SELECT t.name AS Table, c.name AS Column,
ty.name AS Type, c.max_length AS Length
FROM sys.tables AS t
INNER JOIN sys.columns c ON t.OBJECT_ID = c.OBJECT_ID
INNER JOIN sys.types ty ON c.system_type_id = ty.system_type_id
WHERE c.name LIKE @columnName
ORDER BY t.name, c.name

我出于同样的目的使用了这个，它起到了作用：

  select * from INFORMATION_SCHEMA.COLUMNS
  where TABLE_CATALOG= 'theDatabase'
  and COLUMN_NAME like 'theCol%'

您可以尝试以下查询：

USE AdventureWorks
GO
SELECT t.name AS table_name,
SCHEMA_NAME(schema_id) AS schema_name,
c.name AS column_name
FROM sys.tables AS t
INNER JOIN sys.columns c ON t.OBJECT_ID = c.OBJECT_ID
WHERE c.name LIKE '%myName%'

为此，我们可以使用sp_columns。

sp_columns 'table name', null, null, '%column name%'

这应该是有效的：

SELECT name 
FROM sysobjects 
WHERE id IN ( SELECT id 
              FROM syscolumns 
              WHERE name like '%column_name%' )