我试图将一个列表拆分为一系列较小的列表。
我的问题:我的拆分列表功能没有将它们拆分为正确大小的列表。它应该把它们分成大小为30的列表，但它却把它们分成大小为114的列表?
如何让我的函数将一个列表分割成X个大小为30或更小的列表?
public static List<List<float[]>> splitList(List <float[]> locations, int nSize=30)
{
List<List<float[]>> list = new List<List<float[]>>();
for (int i=(int)(Math.Ceiling((decimal)(locations.Count/nSize))); i>=0; i--) {
List <float[]> subLocat = new List <float[]>(locations);
if (subLocat.Count >= ((i*nSize)+nSize))
subLocat.RemoveRange(i*nSize, nSize);
else subLocat.RemoveRange(i*nSize, subLocat.Count-(i*nSize));
Debug.Log ("Index: "+i.ToString()+", Size: "+subLocat.Count.ToString());
list.Add (subLocat);
}
return list;
}
如果我在144大小的列表上使用该函数，那么输出是:
指数:4，尺寸:120
指数:3，尺寸:114
指数:2，尺寸:114
指数:1，尺寸:114
索引:0，大小:114
public static List<List<float[]>> SplitList(List<float[]> locations, int nSize=30)
{
var list = new List<List<float[]>>();
for (int i = 0; i < locations.Count; i += nSize)
{
list.Add(locations.GetRange(i, Math.Min(nSize, locations.Count - i)));
}
return list;
}
通用版:
public static IEnumerable<List<T>> SplitList<T>(List<T> locations, int nSize=30)
{
for (int i = 0; i < locations.Count; i += nSize)
{
yield return locations.GetRange(i, Math.Min(nSize, locations.Count - i));
}
}
List<int> orginalList =new List<int>(){1,2,3,4,5,6,7,8,9,10,12};
Dictionary<int,List<int>> dic = new Dictionary <int,List<int>> ();
int batchcount = orginalList.Count/2; //To List into two 2 parts if you
want three give three
List<int> lst = new List<int>();
for (int i=0;i<orginalList.Count; i++)
{
lst.Add(orginalList[i]);
if (i % batchCount == 0 && i!=0)
{
Dic.Add(threadId, lst);
lst = new List<int>();**strong text**
threadId++;
}
}
if(lst.Count>0)
Dic.Add(threadId, lst); //in case if any dayleft
foreach(int BatchId in Dic.Keys)
{
Console.Writeline("BatchId:"+BatchId);
Console.Writeline('Batch Count:"+Dic[BatchId].Count);
}
库MoreLinq有一个方法叫做Batch
List<int> ids = new List<int>() { 1, 2, 3, 4, 5, 6, 7, 8, 9, 0 }; // 10 elements
int counter = 1;
foreach(var batch in ids.Batch(2))
{
foreach(var eachId in batch)
{
Console.WriteLine("Batch: {0}, Id: {1}", counter, eachId);
}
counter++;
}
结果是
Batch: 1, Id: 1
Batch: 1, Id: 2
Batch: 2, Id: 3
Batch: 2, Id: 4
Batch: 3, Id: 5
Batch: 3, Id: 6
Batch: 4, Id: 7
Batch: 4, Id: 8
Batch: 5, Id: 9
Batch: 5, Id: 0
id被分成5个包含2个元素的块。
public static List<List<float[]>> SplitList(List<float[]> locations, int nSize=30)
{
var list = new List<List<float[]>>();
for (int i = 0; i < locations.Count; i += nSize)
{
list.Add(locations.GetRange(i, Math.Min(nSize, locations.Count - i)));
}
return list;
}
通用版:
public static IEnumerable<List<T>> SplitList<T>(List<T> locations, int nSize=30)
{
for (int i = 0; i < locations.Count; i += nSize)
{
yield return locations.GetRange(i, Math.Min(nSize, locations.Count - i));
}
}
