我有两门课。第一个是活动,第二个是片段,其中有一些EditText。在活动中,我有一个带有async-task的子类,在方法doInBackground中,我得到了一些结果,我保存到变量中。我怎么能把这个变量从子类“我的活动”到这个片段?


当前回答

从Activity中,你用Bundle发送数据为:

Bundle bundle = new Bundle();
bundle.putString("data", "Data you want to send");

// Your fragment
MyFragment obj = new MyFragment();
obj.setArguments(bundle);

并在Fragment的onCreateView方法中获取数据:

@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) 
{
    String data = getArguments().getString("data");// data which sent from activity  
    return inflater.inflate(R.layout.myfragment, container, false);
}

其他回答

如果你将片段(具体子类)的引用传递给异步任务,你就可以直接访问片段。

将片段引用传递给异步任务的一些方法:

如果你的异步任务是一个完全成熟的类(类FooTask扩展AsyncTask),那么将你的片段传递到构造函数中。 如果您的异步任务是一个内部类,只需在异步任务定义的范围内声明一个最终的Fragment变量,或者作为外部类的字段。您将能够从内部类访问它。

最好和最方便的方法是调用片段实例并发送数据。 每个片段默认都有实例方法

例如: 如果你的片段名称是MyFragment

所以你会像这样调用你的fragment from activity:

getSupportFragmentManager().beginTransaction().add(R.id.container, MyFragment.newInstance("data1","data2"),"MyFragment").commit();

* R.id。container是我的框架布局的id

所以在MyFragment.newInstance("data1","data2")你可以发送数据到fragment,在你的fragment你得到这个数据在MyFragment newInstance(String param1, String param2)

public static MyFragment newInstance(String param1, String param2) {
        MyFragment fragment = new MyFragment();
        Bundle args = new Bundle();
        args.putString(ARG_PARAM1, param1);
        args.putString(ARG_PARAM2, param2);
        fragment.setArguments(args);
        return fragment;
    }

然后在fragment的onCreate方法中,你会得到数据:

@Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        if (getArguments() != null) {
            mParam1 = getArguments().getString(ARG_PARAM1);
            mParam2 = getArguments().getString(ARG_PARAM2);
        }
    }

现在mParam1有data1 mParam2有data2 现在你可以在你的片段中使用这个mParam1和mParam2。

只是偶然发现了这个问题,而上面的大多数方法都是有效的。 我只是想补充一点,你可以使用事件总线库,特别是在组件(活动或片段)还没有创建的情况下,它适用于所有规模的android项目和许多用例。我个人在我在playstore上的几个项目中使用过它。

Very old post, still I dare to add a little explanation that would had been helpful for me. Technically you can directly set members of any type in a fragment from activity. So why Bundle? The reason is very simple - Bundle provides uniform way to handle:-- creating/opening fragment -- reconfiguration (screen rotation) - just add initial/updated bundle to outState in onSaveInstanceState() -- app restoration after being garbage collected in background (as with reconfiguration). You can (if you like experiments) create a workaround in simple situations but Bundle-approach just doesn't see difference between one fragment and one thousand on a backstack - it stays simple and straightforward. That's why the answer by @Elenasys is the most elegant and universal solution. And that's why the answer given by @Martin has pitfalls

你也可以从片段访问活动数据:

活动:

public class MyActivity extends Activity {

    private String myString = "hello";

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_my);
        ...
    }

    public String getMyData() {
        return myString;
    }
}

片段:

public class MyFragment extends Fragment {

    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {

        MyActivity activity = (MyActivity) getActivity();
        String myDataFromActivity = activity.getMyData();
        return view;
    }
}