我有两门课。第一个是活动,第二个是片段,其中有一些EditText。在活动中,我有一个带有async-task的子类,在方法doInBackground中,我得到了一些结果,我保存到变量中。我怎么能把这个变量从子类“我的活动”到这个片段?


当前回答

如果一个活动需要一个片段在初始化后执行一个动作,最简单的方法是让这个活动调用片段实例上的一个方法。在这个片段中,添加一个方法:

public class DemoFragment extends Fragment {
  public void doSomething(String param) {
      // do something in fragment
  }
}

然后在活动中,使用片段管理器访问片段并调用方法:

public class MainActivity extends FragmentActivity {
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        DemoFragment fragmentDemo = (DemoFragment) 
            getSupportFragmentManager().findFragmentById(R.id.fragmentDemo);
        fragmentDemo.doSomething("some param");
    }
}

然后活动可以通过调用此方法直接与片段通信。

其他回答

在片段和活动之间传递数据的最聪明的方法是创建一个变量,例如:

class StorageUtil {
  public static ArrayList<Employee> employees;
}

然后通过onActivityCreated方法将数据从fragment传递给activity:

//a field created in the sending fragment
ArrayList<Employee> employees;

@Override
    public void onActivityCreated(@Nullable Bundle savedInstanceState) {
        super.onActivityCreated(savedInstanceState);
         employees=new ArrayList();

       //java 7 and above syntax for arraylist else use employees=new ArrayList<Employee>() for java 6 and below

     //Adding first employee
        Employee employee=new Employee("1","Andrew","Sam","1984-04-10","Male","Ghanaian");
        employees.add(employee);

      //Adding second employee
       Employee employee=new Employee("1","Akuah","Morrison","1984-02-04","Female","Ghanaian");
         employees.add(employee);

        StorageUtil.employees=employees;
    }

现在您可以获得StorageUtil的值。来自各地的员工。 古德勒克!

你也可以从片段访问活动数据:

活动:

public class MyActivity extends Activity {

    private String myString = "hello";

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_my);
        ...
    }

    public String getMyData() {
        return myString;
    }
}

片段:

public class MyFragment extends Fragment {

    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {

        MyActivity activity = (MyActivity) getActivity();
        String myDataFromActivity = activity.getMyData();
        return view;
    }
}

从Activity中,你用Bundle发送数据为:

Bundle bundle = new Bundle();
bundle.putString("data", "Data you want to send");

// Your fragment
MyFragment obj = new MyFragment();
obj.setArguments(bundle);

并在Fragment的onCreateView方法中获取数据:

@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) 
{
    String data = getArguments().getString("data");// data which sent from activity  
    return inflater.inflate(R.layout.myfragment, container, false);
}

如果你将片段(具体子类)的引用传递给异步任务,你就可以直接访问片段。

将片段引用传递给异步任务的一些方法:

如果你的异步任务是一个完全成熟的类(类FooTask扩展AsyncTask),那么将你的片段传递到构造函数中。 如果您的异步任务是一个内部类,只需在异步任务定义的范围内声明一个最终的Fragment变量,或者作为外部类的字段。您将能够从内部类访问它。

Very old post, still I dare to add a little explanation that would had been helpful for me. Technically you can directly set members of any type in a fragment from activity. So why Bundle? The reason is very simple - Bundle provides uniform way to handle:-- creating/opening fragment -- reconfiguration (screen rotation) - just add initial/updated bundle to outState in onSaveInstanceState() -- app restoration after being garbage collected in background (as with reconfiguration). You can (if you like experiments) create a workaround in simple situations but Bundle-approach just doesn't see difference between one fragment and one thousand on a backstack - it stays simple and straightforward. That's why the answer by @Elenasys is the most elegant and universal solution. And that's why the answer given by @Martin has pitfalls