我有两门课。第一个是活动,第二个是片段,其中有一些EditText。在活动中,我有一个带有async-task的子类,在方法doInBackground中,我得到了一些结果,我保存到变量中。我怎么能把这个变量从子类“我的活动”到这个片段?


当前回答

使用以下接口在活动和片段之间进行通信

public interface BundleListener {
    void update(Bundle bundle);
    Bundle getBundle();
}

或者使用下面这个通用监听器进行双向通信使用接口

 /**
 * Created by Qamar4P on 10/11/2017.
 */
public interface GenericConnector<T,E> {
    T getData();
    void updateData(E data);
    void connect(GenericConnector<T,E> connector);
}

片段显示法

public static void show(AppCompatActivity activity) {
        CustomValueDialogFragment dialog = new CustomValueDialogFragment();
        dialog.connector = (GenericConnector) activity;
        dialog.show(activity.getSupportFragmentManager(),"CustomValueDialogFragment");
    }

你也可以在onAttach(context)中将你的上下文转换为GenericConnector

在你的活动中

CustomValueDialogFragment.show(this);

在你的片段中

...
@Override
    public void onCreate(@Nullable Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        connector.connect(new GenericConnector() {
            @Override
            public Object getData() {
                return null;
            }

            @Override
            public void updateData(Object data) {

            }

            @Override
            public void connect(GenericConnector connector) {

            }
        });
    }
...
    public static void show(AppCompatActivity activity, GenericConnector connector) {
            CustomValueDialogFragment dialog = new CustomValueDialogFragment();
            dialog.connector = connector;
            dialog.show(activity.getSupportFragmentManager(),"CustomValueDialogFragment");
        }

注意:千万不要像"".toString().toString().toString();道路

其他回答

有时你可以在你的活动中接收Intent,你需要将信息传递给你的工作片段。 给出的答案是OK,如果你需要启动片段,但如果它仍在工作,setArguments()不是很有用。 如果传递的信息将导致与UI交互,则会出现另一个问题。在这种情况下,你不能调用像myfragment.passData()这样的东西,因为android会迅速告诉只有创建视图的线程可以与之交互。

所以我的建议是使用接收器。这样,您可以从任何地方发送数据,包括活动,但是工作将在片段的上下文中完成。

在你的片段的onCreate():

protected DataReceiver dataReceiver;
public static final String REC_DATA = "REC_DATA";

@Override
public void onCreate(Bundle savedInstanceState) {


    data Receiver = new DataReceiver();
    intentFilter = new IntentFilter(REC_DATA);

    getActivity().registerReceiver(dataReceiver, intentFilter);
}

private class DataReceiver extends BroadcastReceiver {

    @Override
    public void onReceive(Context context, Intent intent) {

        int data= intent.getIntExtra("data", -1);

        // Do anything including interact with your UI
    }
}

在你的活动:

// somewhere
Intent retIntent = new Intent(RE_DATA);
retIntent.putExtra("data", myData);
sendBroadcast(retIntent);

Very old post, still I dare to add a little explanation that would had been helpful for me. Technically you can directly set members of any type in a fragment from activity. So why Bundle? The reason is very simple - Bundle provides uniform way to handle:-- creating/opening fragment -- reconfiguration (screen rotation) - just add initial/updated bundle to outState in onSaveInstanceState() -- app restoration after being garbage collected in background (as with reconfiguration). You can (if you like experiments) create a workaround in simple situations but Bundle-approach just doesn't see difference between one fragment and one thousand on a backstack - it stays simple and straightforward. That's why the answer by @Elenasys is the most elegant and universal solution. And that's why the answer given by @Martin has pitfalls

你也可以从片段访问活动数据:

活动:

public class MyActivity extends Activity {

    private String myString = "hello";

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_my);
        ...
    }

    public String getMyData() {
        return myString;
    }
}

片段:

public class MyFragment extends Fragment {

    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {

        MyActivity activity = (MyActivity) getActivity();
        String myDataFromActivity = activity.getMyData();
        return view;
    }
}

从Activity中发送数据,意图如下:

Bundle bundle = new Bundle();
bundle.putString("edttext", "From Activity");
// set Fragmentclass Arguments
Fragmentclass fragobj = new Fragmentclass();
fragobj.setArguments(bundle);

在Fragment的onCreateView方法中:

@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
        Bundle savedInstanceState) {
    String strtext = getArguments().getString("edttext");    
    return inflater.inflate(R.layout.fragment, container, false);
}

我在这里@ stackoverflow.com找到了很多答案,但这绝对是正确的答案:

“发送数据从活动碎片在android”。

活动:

        Bundle bundle = new Bundle();
        String myMessage = "Stackoverflow is cool!";
        bundle.putString("message", myMessage );
        FragmentClass fragInfo = new FragmentClass();
        fragInfo.setArguments(bundle);
        transaction.replace(R.id.fragment_single, fragInfo);
        transaction.commit();

片段:

读取片段中的值

        @Override
        public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
        Bundle bundle = this.getArguments();
        String myValue = bundle.getString("message");
        ...
        ...
        ...
        }

或者只是

        @Override
        public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
        String myValue = this.getArguments().getString("message");
        ...
        ...
        ...
        }