我有一个这样的字符串:
abc=foo&def=%5Basf%5D&xyz=5
如何将其转换为这样的JavaScript对象?
{
abc: 'foo',
def: '[asf]',
xyz: 5
}
当前回答
下面是硅制品方法的一个更简化的版本。
下面的函数可以从USVString或Location解析查询字符串。
/** * Returns a plain object representation of a URLSearchParams object. * @param {USVString} search - A URL querystring * @return {Object} a key-value pair object from a URL querystring */ const parseSearch = (search) => [...new URLSearchParams(search).entries()] .reduce((acc, [key, val]) => ({ ...acc, // eslint-disable-next-line no-nested-ternary [key]: Object.prototype.hasOwnProperty.call(acc, key) ? Array.isArray(acc[key]) ? [...acc[key], val] : [acc[key], val] : val }), {}); /** * Returns a plain object representation of a URLSearchParams object. * @param {Location} location - Either a document or window location, or React useLocation() * @return {Object} a key-value pair object from a URL querystring */ const parseLocationSearch = (location) => parseSearch(location.search); console.log(parseSearch('?foo=bar&x=y&ids=%5B1%2C2%2C3%5D&ids=%5B4%2C5%2C6%5D')); .as-console-wrapper { top: 0; max-height: 100% !important; }
下面是上面代码的一行代码(125字节):
f是parsearchch
f=s=>[...new URLSearchParams(s).entries()].reduce((a,[k,v])=>({...a,[k]:a[k]?Array.isArray(a[k])?[...a[k],v]:[a[k],v]:v}),{})
Edit
下面是一个序列化和更新的方法:
const parseSearch = (search) => [...new URLSearchParams(search).entries()] .reduce((acc, [key, val]) => ({ ...acc, // eslint-disable-next-line no-nested-ternary [key]: Object.prototype.hasOwnProperty.call(acc, key) ? Array.isArray(acc[key]) ? [...acc[key], val] : [acc[key], val] : val }), {}); const toQueryString = (params) => `?${Object.entries(params) .flatMap(([key, values]) => Array.isArray(values) ? values.map(value => [key, value]) : [[key, values]]) .map(pair => pair.map(val => encodeURIComponent(val)).join('=')) .join('&')}`; const updateQueryString = (search, update) => (parsed => toQueryString(update instanceof Function ? update(parsed) : { ...parsed, ...update })) (parseSearch(search)); const queryString = '?foo=bar&x=y&ids=%5B1%2C2%2C3%5D&ids=%5B4%2C5%2C6%5D'; const parsedQuery = parseSearch(queryString); console.log(parsedQuery); console.log(toQueryString(parsedQuery) === queryString); const updatedQuerySimple = updateQueryString(queryString, { foo: 'baz', x: 'z', }); console.log(updatedQuerySimple); console.log(parseSearch(updatedQuerySimple)); const updatedQuery = updateQueryString(updatedQuerySimple, parsed => ({ ...parsed, ids: [ ...parsed.ids, JSON.stringify([7,8,9]) ] })); console.log(updatedQuery); console.log(parseSearch(updatedQuery)); .as-console-wrapper { top: 0; max-height: 100% !important; }
其他回答
另一种基于URLSearchParams最新标准的解决方案(https://developer.mozilla.org/en-US/docs/Web/API/URLSearchParams)
function getQueryParamsObject() {
const searchParams = new URLSearchParams(location.search.slice(1));
return searchParams
? _.fromPairs(Array.from(searchParams.entries()))
: {};
}
请注意，这个解决方案是利用
Array.from (https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/from)
和lodash的_. fropairs (https://lodash.com/docs#fromPairs)，以便简单。
因为您可以访问searchParams.entries()迭代器，所以创建一个更兼容的解决方案应该很容易。
下面是硅制品方法的一个更简化的版本。
下面的函数可以从USVString或Location解析查询字符串。
/** * Returns a plain object representation of a URLSearchParams object. * @param {USVString} search - A URL querystring * @return {Object} a key-value pair object from a URL querystring */ const parseSearch = (search) => [...new URLSearchParams(search).entries()] .reduce((acc, [key, val]) => ({ ...acc, // eslint-disable-next-line no-nested-ternary [key]: Object.prototype.hasOwnProperty.call(acc, key) ? Array.isArray(acc[key]) ? [...acc[key], val] : [acc[key], val] : val }), {}); /** * Returns a plain object representation of a URLSearchParams object. * @param {Location} location - Either a document or window location, or React useLocation() * @return {Object} a key-value pair object from a URL querystring */ const parseLocationSearch = (location) => parseSearch(location.search); console.log(parseSearch('?foo=bar&x=y&ids=%5B1%2C2%2C3%5D&ids=%5B4%2C5%2C6%5D')); .as-console-wrapper { top: 0; max-height: 100% !important; }
下面是上面代码的一行代码(125字节):
f是parsearchch
f=s=>[...new URLSearchParams(s).entries()].reduce((a,[k,v])=>({...a,[k]:a[k]?Array.isArray(a[k])?[...a[k],v]:[a[k],v]:v}),{})
Edit
下面是一个序列化和更新的方法:
const parseSearch = (search) => [...new URLSearchParams(search).entries()] .reduce((acc, [key, val]) => ({ ...acc, // eslint-disable-next-line no-nested-ternary [key]: Object.prototype.hasOwnProperty.call(acc, key) ? Array.isArray(acc[key]) ? [...acc[key], val] : [acc[key], val] : val }), {}); const toQueryString = (params) => `?${Object.entries(params) .flatMap(([key, values]) => Array.isArray(values) ? values.map(value => [key, value]) : [[key, values]]) .map(pair => pair.map(val => encodeURIComponent(val)).join('=')) .join('&')}`; const updateQueryString = (search, update) => (parsed => toQueryString(update instanceof Function ? update(parsed) : { ...parsed, ...update })) (parseSearch(search)); const queryString = '?foo=bar&x=y&ids=%5B1%2C2%2C3%5D&ids=%5B4%2C5%2C6%5D'; const parsedQuery = parseSearch(queryString); console.log(parsedQuery); console.log(toQueryString(parsedQuery) === queryString); const updatedQuerySimple = updateQueryString(queryString, { foo: 'baz', x: 'z', }); console.log(updatedQuerySimple); console.log(parseSearch(updatedQuerySimple)); const updatedQuery = updateQueryString(updatedQuerySimple, parsed => ({ ...parsed, ids: [ ...parsed.ids, JSON.stringify([7,8,9]) ] })); console.log(updatedQuery); console.log(parseSearch(updatedQuery)); .as-console-wrapper { top: 0; max-height: 100% !important; }
如果您需要递归，您可以使用小巧的js-extension-ling库。
npm i js-extension-ling
const jsx = require("js-extension-ling");
console.log(jsx.queryStringToObject("a=1"));
console.log(jsx.queryStringToObject("a=1&a=3"));
console.log(jsx.queryStringToObject("a[]=1"));
console.log(jsx.queryStringToObject("a[]=1&a[]=pomme"));
console.log(jsx.queryStringToObject("a[0]=one&a[1]=five"));
console.log(jsx.queryStringToObject("http://blabla?foo=bar&number=1234"));
console.log(jsx.queryStringToObject("a[fruits][red][]=strawberry"));
console.log(jsx.queryStringToObject("a[fruits][red][]=strawberry&a[1]=five&a[fruits][red][]=cherry&a[fruits][yellow][]=lemon&a[fruits][yellow][688]=banana"));
这将输出如下内容:
{ a: '1' }
{ a: '3' }
{ a: { '0': '1' } }
{ a: { '0': '1', '1': 'pomme' } }
{ a: { '0': 'one', '1': 'five' } }
{ foo: 'bar', number: '1234' }
{
a: { fruits: { red: { '0': 'strawberry' } } }
}
{
a: {
'1': 'five',
fruits: {
red: { '0': 'strawberry', '1': 'cherry' },
yellow: { '0': 'lemon', '688': 'banana' }
}
}
}
注意:它基于loctus parse_str函数(https://locutus.io/php/strings/parse_str/)。
//under ES6
const getUrlParamAsObject = (url = window.location.href) => {
let searchParams = url.split('?')[1];
const result = {};
//in case the queryString is empty
if (searchParams!==undefined) {
const paramParts = searchParams.split('&');
for(let part of paramParts) {
let paramValuePair = part.split('=');
//exclude the case when the param has no value
if(paramValuePair.length===2) {
result[paramValuePair[0]] = decodeURIComponent(paramValuePair[1]);
}
}
}
return result;
}
对于Node JS，你可以使用Node JS API querystring:
const querystring = require('querystring');
querystring.parse('abc=foo&def=%5Basf%5D&xyz=5&foo=b%3Dar');
// returns the object
文档:https://nodejs.org/api/querystring.html
