我有一个这样的字符串:
abc=foo&def=%5Basf%5D&xyz=5
如何将其转换为这样的JavaScript对象?
{
abc: 'foo',
def: '[asf]',
xyz: 5
}
我有一个这样的字符串:
abc=foo&def=%5Basf%5D&xyz=5
如何将其转换为这样的JavaScript对象?
{
abc: 'foo',
def: '[asf]',
xyz: 5
}
当前回答
到目前为止,我发现的建议解决方案并没有涵盖更复杂的场景。
我需要像这样转换查询字符串
https://random.url.com?Target=Offer&Method=findAll&filters%5Bhas_goals_enabled%5D%5BTRUE%5D=1&filters%5Bstatus%5D=active&fields%5B%5D=id&fields%5B%5D=name&fields%5B%5D=default_goal_name
变成一个像这样的物体:
{
"Target": "Offer",
"Method": "findAll",
"fields": [
"id",
"name",
"default_goal_name"
],
"filters": {
"has_goals_enabled": {
"TRUE": "1"
},
"status": "active"
}
}
OR:
https://random.url.com?Target=Report&Method=getStats&fields%5B%5D=Offer.name&fields%5B%5D=Advertiser.company&fields%5B%5D=Stat.clicks&fields%5B%5D=Stat.conversions&fields%5B%5D=Stat.cpa&fields%5B%5D=Stat.payout&fields%5B%5D=Stat.date&fields%5B%5D=Stat.offer_id&fields%5B%5D=Affiliate.company&groups%5B%5D=Stat.offer_id&groups%5B%5D=Stat.date&filters%5BStat.affiliate_id%5D%5Bconditional%5D=EQUAL_TO&filters%5BStat.affiliate_id%5D%5Bvalues%5D=1831&limit=9999
成:
{
"Target": "Report",
"Method": "getStats",
"fields": [
"Offer.name",
"Advertiser.company",
"Stat.clicks",
"Stat.conversions",
"Stat.cpa",
"Stat.payout",
"Stat.date",
"Stat.offer_id",
"Affiliate.company"
],
"groups": [
"Stat.offer_id",
"Stat.date"
],
"limit": "9999",
"filters": {
"Stat.affiliate_id": {
"conditional": "EQUAL_TO",
"values": "1831"
}
}
}
我将多个解决方案编译并调整为一个实际有效的解决方案:
代码:
var getParamsAsObject = function (query) {
query = query.substring(query.indexOf('?') + 1);
var re = /([^&=]+)=?([^&]*)/g;
var decodeRE = /\+/g;
var decode = function (str) {
return decodeURIComponent(str.replace(decodeRE, " "));
};
var params = {}, e;
while (e = re.exec(query)) {
var k = decode(e[1]), v = decode(e[2]);
if (k.substring(k.length - 2) === '[]') {
k = k.substring(0, k.length - 2);
(params[k] || (params[k] = [])).push(v);
}
else params[k] = v;
}
var assign = function (obj, keyPath, value) {
var lastKeyIndex = keyPath.length - 1;
for (var i = 0; i < lastKeyIndex; ++i) {
var key = keyPath[i];
if (!(key in obj))
obj[key] = {}
obj = obj[key];
}
obj[keyPath[lastKeyIndex]] = value;
}
for (var prop in params) {
var structure = prop.split('[');
if (structure.length > 1) {
var levels = [];
structure.forEach(function (item, i) {
var key = item.replace(/[?[\]\\ ]/g, '');
levels.push(key);
});
assign(params, levels, params[prop]);
delete(params[prop]);
}
}
return params;
};
其他回答
使用phpjs
function parse_str(str, array) {
// discuss at: http://phpjs.org/functions/parse_str/
// original by: Cagri Ekin
// improved by: Michael White (http://getsprink.com)
// improved by: Jack
// improved by: Brett Zamir (http://brett-zamir.me)
// bugfixed by: Onno Marsman
// bugfixed by: Brett Zamir (http://brett-zamir.me)
// bugfixed by: stag019
// bugfixed by: Brett Zamir (http://brett-zamir.me)
// bugfixed by: MIO_KODUKI (http://mio-koduki.blogspot.com/)
// reimplemented by: stag019
// input by: Dreamer
// input by: Zaide (http://zaidesthings.com/)
// input by: David Pesta (http://davidpesta.com/)
// input by: jeicquest
// note: When no argument is specified, will put variables in global scope.
// note: When a particular argument has been passed, and the returned value is different parse_str of PHP. For example, a=b=c&d====c
// test: skip
// example 1: var arr = {};
// example 1: parse_str('first=foo&second=bar', arr);
// example 1: $result = arr
// returns 1: { first: 'foo', second: 'bar' }
// example 2: var arr = {};
// example 2: parse_str('str_a=Jack+and+Jill+didn%27t+see+the+well.', arr);
// example 2: $result = arr
// returns 2: { str_a: "Jack and Jill didn't see the well." }
// example 3: var abc = {3:'a'};
// example 3: parse_str('abc[a][b]["c"]=def&abc[q]=t+5');
// returns 3: {"3":"a","a":{"b":{"c":"def"}},"q":"t 5"}
var strArr = String(str)
.replace(/^&/, '')
.replace(/&$/, '')
.split('&'),
sal = strArr.length,
i, j, ct, p, lastObj, obj, lastIter, undef, chr, tmp, key, value,
postLeftBracketPos, keys, keysLen,
fixStr = function(str) {
return decodeURIComponent(str.replace(/\+/g, '%20'));
};
if (!array) {
array = this.window;
}
for (i = 0; i < sal; i++) {
tmp = strArr[i].split('=');
key = fixStr(tmp[0]);
value = (tmp.length < 2) ? '' : fixStr(tmp[1]);
while (key.charAt(0) === ' ') {
key = key.slice(1);
}
if (key.indexOf('\x00') > -1) {
key = key.slice(0, key.indexOf('\x00'));
}
if (key && key.charAt(0) !== '[') {
keys = [];
postLeftBracketPos = 0;
for (j = 0; j < key.length; j++) {
if (key.charAt(j) === '[' && !postLeftBracketPos) {
postLeftBracketPos = j + 1;
} else if (key.charAt(j) === ']') {
if (postLeftBracketPos) {
if (!keys.length) {
keys.push(key.slice(0, postLeftBracketPos - 1));
}
keys.push(key.substr(postLeftBracketPos, j - postLeftBracketPos));
postLeftBracketPos = 0;
if (key.charAt(j + 1) !== '[') {
break;
}
}
}
}
if (!keys.length) {
keys = [key];
}
for (j = 0; j < keys[0].length; j++) {
chr = keys[0].charAt(j);
if (chr === ' ' || chr === '.' || chr === '[') {
keys[0] = keys[0].substr(0, j) + '_' + keys[0].substr(j + 1);
}
if (chr === '[') {
break;
}
}
obj = array;
for (j = 0, keysLen = keys.length; j < keysLen; j++) {
key = keys[j].replace(/^['"]/, '')
.replace(/['"]$/, '');
lastIter = j !== keys.length - 1;
lastObj = obj;
if ((key !== '' && key !== ' ') || j === 0) {
if (obj[key] === undef) {
obj[key] = {};
}
obj = obj[key];
} else { // To insert new dimension
ct = -1;
for (p in obj) {
if (obj.hasOwnProperty(p)) {
if (+p > ct && p.match(/^\d+$/g)) {
ct = +p;
}
}
}
key = ct + 1;
}
}
lastObj[key] = value;
}
}
}
2022 ES6/7/8,进近
从ES6开始,Javascript提供了几个构造来为这个问题创建一个性能解决方案。
这包括使用URLSearchParams和迭代器
let params = new URLSearchParams('abc=foo&def=%5Basf%5D&xyz=5');
params.get("abc"); // "foo"
如果你的用例需要你实际将其转换为对象,你可以实现以下函数:
function paramsToObject(entries) {
const result = {}
for(const [key, value] of entries) { // each 'entry' is a [key, value] tupple
result[key] = value;
}
return result;
}
基本的演示
const urlParams = new URLSearchParams('abc=foo&def=%5Basf%5D&xyz=5');
const entries = urlParams.entries(); //returns an iterator of decoded [key,value] tuples
const params = paramsToObject(entries); //{abc:"foo",def:"[asf]",xyz:"5"}
使用Object.fromEntries和spread
我们可以使用Object.fromEntries,用Object.fromEntries(entries)替换paramsToObject。
对象的列表名称-值对是要遍历的值对 键是名称,值是值。
由于URLParams返回一个可迭代对象,使用展开操作符而不是调用.entries也将根据其规范生成条目:
const urlParams = new URLSearchParams('abc=foo&def=%5Basf%5D&xyz=5');
const params = Object.fromEntries(urlParams); // {abc: "foo", def: "[asf]", xyz: "5"}
注意:根据URLSearchParams规范,所有值都是自动字符串
多个相同的键
正如@siipe指出的,包含多个相同键值的字符串将被强制转换为最后一个可用值:foo=first_value&foo=second_value本质上将变成:{foo: "second_value"}。
根据这个答案:https://stackoverflow.com/a/1746566/1194694没有规范来决定用它做什么,每个框架可以有不同的行为。
一个常见的用例是将两个相同的值连接到一个数组中,使输出对象变成:
{foo: ["first_value", "second_value"]}
这可以通过以下代码实现:
const groupParamsByKey = (params) => [...params.entries()].reduce((acc, tuple) => {
// getting the key and value from each tuple
const [key, val] = tuple;
if(acc.hasOwnProperty(key)) {
// if the current key is already an array, we'll add the value to it
if(Array.isArray(acc[key])) {
acc[key] = [...acc[key], val]
} else {
// if it's not an array, but contains a value, we'll convert it into an array
// and add the current value to it
acc[key] = [acc[key], val];
}
} else {
// plain assignment if no special case is present
acc[key] = val;
}
return acc;
}, {});
const params = new URLSearchParams('abc=foo&def=%5Basf%5D&xyz=5&def=dude');
const output = groupParamsByKey(params) // {abc: "foo", def: ["[asf]", "dude"], xyz: 5}
如果你正在使用URI.js,你可以使用:
https://medialize.github.io/URI.js/docs.html#static-parseQuery
var result = URI.parseQuery("?foo=bar&hello=world&hello=mars&bam=&yup");
result === {
foo: "bar",
hello: ["world", "mars"],
bam: "",
yup: null
};
到目前为止,我发现的建议解决方案并没有涵盖更复杂的场景。
我需要像这样转换查询字符串
https://random.url.com?Target=Offer&Method=findAll&filters%5Bhas_goals_enabled%5D%5BTRUE%5D=1&filters%5Bstatus%5D=active&fields%5B%5D=id&fields%5B%5D=name&fields%5B%5D=default_goal_name
变成一个像这样的物体:
{
"Target": "Offer",
"Method": "findAll",
"fields": [
"id",
"name",
"default_goal_name"
],
"filters": {
"has_goals_enabled": {
"TRUE": "1"
},
"status": "active"
}
}
OR:
https://random.url.com?Target=Report&Method=getStats&fields%5B%5D=Offer.name&fields%5B%5D=Advertiser.company&fields%5B%5D=Stat.clicks&fields%5B%5D=Stat.conversions&fields%5B%5D=Stat.cpa&fields%5B%5D=Stat.payout&fields%5B%5D=Stat.date&fields%5B%5D=Stat.offer_id&fields%5B%5D=Affiliate.company&groups%5B%5D=Stat.offer_id&groups%5B%5D=Stat.date&filters%5BStat.affiliate_id%5D%5Bconditional%5D=EQUAL_TO&filters%5BStat.affiliate_id%5D%5Bvalues%5D=1831&limit=9999
成:
{
"Target": "Report",
"Method": "getStats",
"fields": [
"Offer.name",
"Advertiser.company",
"Stat.clicks",
"Stat.conversions",
"Stat.cpa",
"Stat.payout",
"Stat.date",
"Stat.offer_id",
"Affiliate.company"
],
"groups": [
"Stat.offer_id",
"Stat.date"
],
"limit": "9999",
"filters": {
"Stat.affiliate_id": {
"conditional": "EQUAL_TO",
"values": "1831"
}
}
}
我将多个解决方案编译并调整为一个实际有效的解决方案:
代码:
var getParamsAsObject = function (query) {
query = query.substring(query.indexOf('?') + 1);
var re = /([^&=]+)=?([^&]*)/g;
var decodeRE = /\+/g;
var decode = function (str) {
return decodeURIComponent(str.replace(decodeRE, " "));
};
var params = {}, e;
while (e = re.exec(query)) {
var k = decode(e[1]), v = decode(e[2]);
if (k.substring(k.length - 2) === '[]') {
k = k.substring(0, k.length - 2);
(params[k] || (params[k] = [])).push(v);
}
else params[k] = v;
}
var assign = function (obj, keyPath, value) {
var lastKeyIndex = keyPath.length - 1;
for (var i = 0; i < lastKeyIndex; ++i) {
var key = keyPath[i];
if (!(key in obj))
obj[key] = {}
obj = obj[key];
}
obj[keyPath[lastKeyIndex]] = value;
}
for (var prop in params) {
var structure = prop.split('[');
if (structure.length > 1) {
var levels = [];
structure.forEach(function (item, i) {
var key = item.replace(/[?[\]\\ ]/g, '');
levels.push(key);
});
assign(params, levels, params[prop]);
delete(params[prop]);
}
}
return params;
};
我也遇到了同样的问题,尝试了这里的解决方案,但没有一个真正有效,因为我在URL参数中有数组,像这样:
?param[]=5¶m[]=8&othr_param=abc¶m[]=string
所以我最终写了我自己的JS函数,它使一个数组的参数在URI:
/**
* Creates an object from URL encoded data
*/
var createObjFromURI = function() {
var uri = decodeURI(location.search.substr(1));
var chunks = uri.split('&');
var params = Object();
for (var i=0; i < chunks.length ; i++) {
var chunk = chunks[i].split('=');
if(chunk[0].search("\\[\\]") !== -1) {
if( typeof params[chunk[0]] === 'undefined' ) {
params[chunk[0]] = [chunk[1]];
} else {
params[chunk[0]].push(chunk[1]);
}
} else {
params[chunk[0]] = chunk[1];
}
}
return params;
}