我有一个这样的字符串:
abc=foo&def=%5Basf%5D&xyz=5
如何将其转换为这样的JavaScript对象?
{
abc: 'foo',
def: '[asf]',
xyz: 5
}
我有一个这样的字符串:
abc=foo&def=%5Basf%5D&xyz=5
如何将其转换为这样的JavaScript对象?
{
abc: 'foo',
def: '[asf]',
xyz: 5
}
当前回答
一个班轮。干净简单。
const params = Object.fromEntries(new URLSearchParams(location.search));
对于您的具体情况,它将是:
const str = 'abc=foo&def=%5Basf%5D&xyz=5'; const params = Object.fromEntries(new URLSearchParams(str)); console.log (params);
其他回答
在Mike Causer回答的基础上,我创建了这个函数,它考虑了具有相同键的多个参数(foo=bar&foo=baz)和逗号分隔的参数(foo=bar,baz,bin)。它还允许您搜索某个查询键。
function getQueryParams(queryKey) {
var queryString = window.location.search;
var query = {};
var pairs = (queryString[0] === '?' ? queryString.substr(1) : queryString).split('&');
for (var i = 0; i < pairs.length; i++) {
var pair = pairs[i].split('=');
var key = decodeURIComponent(pair[0]);
var value = decodeURIComponent(pair[1] || '');
// Se possui uma vírgula no valor, converter em um array
value = (value.indexOf(',') === -1 ? value : value.split(','));
// Se a key já existe, tratar ela como um array
if (query[key]) {
if (query[key].constructor === Array) {
// Array.concat() faz merge se o valor inserido for um array
query[key] = query[key].concat(value);
} else {
// Se não for um array, criar um array contendo o valor anterior e o novo valor
query[key] = [query[key], value];
}
} else {
query[key] = value;
}
}
if (typeof queryKey === 'undefined') {
return query;
} else {
return query[queryKey];
}
}
示例输入: foo.html吗?博兹,foo = bar&foo = baz&foo =鹿角的第二叉,buz&bar = 1, 2, 3
示例输出
{
foo: ["bar","baz","bez","boz","buz"],
bar: ["1","2","3"]
}
这是一个简单的版本,显然你需要添加一些错误检查:
var obj = {};
var pairs = queryString.split('&');
for(i in pairs){
var split = pairs[i].split('=');
obj[decodeURIComponent(split[0])] = decodeURIComponent(split[1]);
}
最简单的方法之一是使用URLSearchParam接口。
下面是工作代码片段:
let paramObj={},
querystring=window.location.search,
searchParams = new URLSearchParams(querystring);
//*** :loop to add key and values to the param object.
searchParams.forEach(function(value, key) {
paramObj[key] = value;
});
使用URLSearchParams JavaScript Web API非常简单,
var paramsString = "abc=foo&def=%5Basf%5D&xyz=5"; //returns an iterator object var searchParams = new URLSearchParams(paramsString); //Usage for (let p of searchParams) { console.log(p); } //Get the query strings console.log(searchParams.toString()); //You can also pass in objects var paramsObject = {abc:"forum",def:"%5Basf%5D",xyz:"5"} //returns an iterator object var searchParams = new URLSearchParams(paramsObject); //Usage for (let p of searchParams) { console.log(p); } //Get the query strings console.log(searchParams.toString());
# #的有用链接
URLSearchParams - Web api | MDN 简单的URL操作与URLSearchParams | Web |谷歌开发者
注意:IE不支持
在2021年…请认为这是过时的。
Edit
这个编辑改进并解释了基于评论的答案。
var search = location.search.substring(1);
JSON.parse('{"' + decodeURI(search).replace(/"/g, '\\"').replace(/&/g, '","').replace(/=/g,'":"') + '"}')
例子
分五个步骤解析abc=foo&def=%5Basf%5D&xyz=5:
decodeURI: abc = foo&def = xyz (asf) = 5 转义引号:相同,因为没有引号 替换&:abc=foo","def=[asf]","xyz=5 " 5 . Replace =: abc":"foo","def":"[asf]","xyz": Suround卷曲和引用:{“abc”:“foo”、“def”:“(asf)”,“xyz”:“5”}
这是合法的JSON。
改进的解决方案允许搜索字符串中有更多字符。它使用了一个恢复函数来进行URI解码:
var search = location.search.substring(1);
JSON.parse('{"' + search.replace(/&/g, '","').replace(/=/g,'":"') + '"}', function(key, value) { return key===""?value:decodeURIComponent(value) })
例子
search = "abc=foo&def=%5Basf%5D&xyz=5&foo=b%3Dar";
给了
Object {abc: "foo", def: "[asf]", xyz: "5", foo: "b=ar"}
原来的答案
一行程序:
JSON.parse('{"' + decodeURI("abc=foo&def=%5Basf%5D&xyz=5".replace(/&/g, "\",\"").replace(/=/g,"\":\"")) + '"}')