在C语言中什么时候应该使用双重间接?谁能举个例子解释一下吗?

我所知道的是双间接是指向指针的指针。为什么我需要指向指针的指针?


当前回答

如果你想要一个字符列表(一个单词),你可以使用char *word

如果你想要一个单词列表(一个句子),你可以使用char **句子

如果你想要一个句子列表(独白),你可以使用char ***monologue

如果你想要一个独白列表(传记),你可以使用char ****传记

如果你想要一个传记列表(一个生物图书馆),你可以使用char *****biolibrary

如果你想要一个生物库列表(a ??lol),你可以使用char ******lol

……

是的,我知道这些可能不是最好的数据结构


一个非常非常非常无聊的lol的用法例子

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int wordsinsentence(char **x) {
    int w = 0;
    while (*x) {
        w += 1;
        x++;
    }
    return w;
}

int wordsinmono(char ***x) {
    int w = 0;
    while (*x) {
        w += wordsinsentence(*x);
        x++;
    }
    return w;
}

int wordsinbio(char ****x) {
    int w = 0;
    while (*x) {
        w += wordsinmono(*x);
        x++;
    }
    return w;
}

int wordsinlib(char *****x) {
    int w = 0;
    while (*x) {
        w += wordsinbio(*x);
        x++;
    }
    return w;
}

int wordsinlol(char ******x) {
    int w = 0;
    while (*x) {
        w += wordsinlib(*x);
        x++;
    }
    return w;
}

int main(void) {
    char *word;
    char **sentence;
    char ***monologue;
    char ****biography;
    char *****biolibrary;
    char ******lol;

    //fill data structure
    word = malloc(4 * sizeof *word); // assume it worked
    strcpy(word, "foo");

    sentence = malloc(4 * sizeof *sentence); // assume it worked
    sentence[0] = word;
    sentence[1] = word;
    sentence[2] = word;
    sentence[3] = NULL;

    monologue = malloc(4 * sizeof *monologue); // assume it worked
    monologue[0] = sentence;
    monologue[1] = sentence;
    monologue[2] = sentence;
    monologue[3] = NULL;

    biography = malloc(4 * sizeof *biography); // assume it worked
    biography[0] = monologue;
    biography[1] = monologue;
    biography[2] = monologue;
    biography[3] = NULL;

    biolibrary = malloc(4 * sizeof *biolibrary); // assume it worked
    biolibrary[0] = biography;
    biolibrary[1] = biography;
    biolibrary[2] = biography;
    biolibrary[3] = NULL;

    lol = malloc(4 * sizeof *lol); // assume it worked
    lol[0] = biolibrary;
    lol[1] = biolibrary;
    lol[2] = biolibrary;
    lol[3] = NULL;

    printf("total words in my lol: %d\n", wordsinlol(lol));

    free(lol);
    free(biolibrary);
    free(biography);
    free(monologue);
    free(sentence);
    free(word);
}

输出:

total words in my lol: 243

其他回答

比较变量的修改值和指针的修改值:

#include <stdio.h>
#include <stdlib.h>

void changeA(int (*a))
{
  (*a) = 10;
}

void changeP(int *(*P))
{
  (*P) = malloc(sizeof((*P)));
}

int main(void)
{
  int A = 0;

  printf("orig. A = %d\n", A);
  changeA(&A);
  printf("modi. A = %d\n", A);

  /*************************/

  int *P = NULL;

  printf("orig. P = %p\n", P);
  changeP(&P);
  printf("modi. P = %p\n", P);

  free(P);

  return EXIT_SUCCESS;
}

这帮助我避免指针被调用函数修改时返回指针的值(用于单链表)。

古老的(坏的):

int *func(int *P)
{
  ...
  return P;
}

int main(void)
{
  int *pointer;
  pointer = func(pointer);
  ...
}    

新(更好的):

void func(int **pointer)
{
  ...
}

int main(void)
{
  int *pointer;
  func(&pointer);
  ...
}    

I have used double pointers today while I was programming something for work, so I can answer why we had to use them (it's the first time I actually had to use double pointers). We had to deal with real time encoding of frames contained in buffers which are members of some structures. In the encoder we had to use a pointer to one of those structures. The problem was that our pointer was being changed to point to other structures from another thread. In order to use the current structure in the encoder, I had to use a double pointer, in order to point to the pointer that was being modified in another thread. It wasn't obvious at first, at least for us, that we had to take this approach. A lot of address were printed in the process :)).

当你处理在应用程序其他地方被更改的指针时,你应该使用双指针。在处理返回和寻址给您的硬件时,您可能还会发现双指针是必须的。

字符串是使用双指针的一个很好的例子。字符串本身是一个指针,所以任何时候你需要指向一个字符串,你就需要一个双指针。

这里的大多数答案或多或少都与应用程序编程有关。下面是一个嵌入式系统编程的例子。例如,以下是NXP Kinetis KL13系列微控制器参考手册的摘录,此代码片段用于从固件中运行驻留在ROM中的引导加载程序:

" 为了获得入口点的地址,用户应用程序读取包含引导加载程序API树指针的单词,该指针位于引导加载程序向量表的0x1C偏移量处。向量表被放置在引导加载器地址范围的底部,ROM的地址范围是0x1C00_0000。因此,API树指针位于地址0x1C00_001C。

引导加载程序API树是一个包含指向其他结构的指针的结构,这些结构具有引导加载程序的函数和数据地址。引导加载程序入口点总是API树的第一个单词。 "

uint32_t runBootloaderAddress;
void (*runBootloader)(void * arg);
// Read the function address from the ROM API tree.
runBootloaderAddress = **(uint32_t **)(0x1c00001c);
runBootloader = (void (*)(void * arg))runBootloaderAddress;
// Start the bootloader.
runBootloader(NULL);

一个原因是你想要改变传递给函数的作为函数参数的指针的值,要做到这一点,你需要指针指向指针。

简单地说,当你想在函数调用之外保留(或保留)内存分配或分配的变化时,使用**。(因此,传递带有双指针arg的函数。)

这可能不是一个很好的例子,但会告诉你基本的用法:

#include <stdio.h>
#include <stdlib.h>

void allocate(int **p)
{
    *p = (int *)malloc(sizeof(int));
}

int main()
{
    int *p = NULL;
    allocate(&p);
    *p = 42;
    printf("%d\n", *p);
    free(p);
}