有没有办法告诉一个字符串是否代表一个整数(例如,'3','-17'但不是'3.14'或'asfasfas')而不使用try/except机制?
is_int('3.14') == False
is_int('-7') == True
有没有办法告诉一个字符串是否代表一个整数(例如,'3','-17'但不是'3.14'或'asfasfas')而不使用try/except机制?
is_int('3.14') == False
is_int('-7') == True
当前回答
下面是一个解析时不会产生错误的函数。它处理明显的情况,失败时返回None(在CPython上默认处理最多2000个'-/+'符号!):
#!/usr/bin/env python
def get_int(number):
splits = number.split('.')
if len(splits) > 2:
# too many splits
return None
if len(splits) == 2 and splits[1]:
# handle decimal part recursively :-)
if get_int(splits[1]) != 0:
return None
int_part = splits[0].lstrip("+")
if int_part.startswith('-'):
# handle minus sign recursively :-)
return get_int(int_part[1:]) * -1
# successful 'and' returns last truth-y value (cast is always valid)
return int_part.isdigit() and int(int_part)
一些测试:
tests = ["0", "0.0", "0.1", "1", "1.1", "1.0", "-1", "-1.1", "-1.0", "-0", "--0", "---3", '.3', '--3.', "+13", "+-1.00", "--+123", "-0.000"]
for t in tests:
print "get_int(%s) = %s" % (t, get_int(str(t)))
结果:
get_int(0) = 0
get_int(0.0) = 0
get_int(0.1) = None
get_int(1) = 1
get_int(1.1) = None
get_int(1.0) = 1
get_int(-1) = -1
get_int(-1.1) = None
get_int(-1.0) = -1
get_int(-0) = 0
get_int(--0) = 0
get_int(---3) = -3
get_int(.3) = None
get_int(--3.) = 3
get_int(+13) = 13
get_int(+-1.00) = -1
get_int(--+123) = 123
get_int(-0.000) = 0
如有需要,可使用:
def int_predicate(number):
return get_int(number) is not None
其他回答
我用的最简单的方法
def is_int(item: str) -> bool:
return item.lstrip('-+').isdigit()
可以用下面的方法进行检查。
def check_if_string_is_int(string1):
for character in string1:
if not character.isdigit():
return "Not a number"
else:
return "Is a number"
检查后将值转换为字符串为整数,然后检查字符串第一个字符值为-或+,其余字符串为数字。最后检查isdigit。 Test = ['1', '12015', '1..]2 ', ' a2kk78”、“1.5”,2,1.24,“-8.5”,“+”、“1”、“88751.71 + 7)
检查
for k,v in enumerate(test):
print(k, v, 'test: ', True if isinstance(v, int) is not False else True if str(v)[0] in ['-', '+'] and str(v)[1:].isdigit() else str(v).isdigit())
结果
0 1 test: True
1 12015 test: True
2 1..2 test: False
3 a2kk78 test: False
4 1.5 test: False
5 2 test: True
6 1.24 test: False
7 -8.5 test: False
8 +88751.71 test: False
9 -1 test: True
10 +7 test: True
呃. .试试这个:
def int_check(a):
if int(a) == a:
return True
else:
return False
如果你不输入非数字的字符串,这是可行的。
还有(我忘了写数字检查部分了。),有一个函数检查字符串是否是数字。它是str.isdigit()。这里有一个例子:
a = 2
a.isdigit()
如果调用a.s isdigit(),它将返回True。
正确的RegEx解决方案应该结合Greg Hewgill和Nowell的思想,但不使用全局变量。可以通过将属性附加到方法来实现这一点。另外,我知道在方法中导入是不受欢迎的,但我想要的是像http://peak.telecommunity.com/DevCenter/Importing#lazy-imports这样的“惰性模块”效果
edit:到目前为止,我最喜欢的技术是使用String对象的独占方法。
#!/usr/bin/env python
# Uses exclusively methods of the String object
def isInteger(i):
i = str(i)
return i=='0' or (i if i.find('..') > -1 else i.lstrip('-+').rstrip('0').rstrip('.')).isdigit()
# Uses re module for regex
def isIntegre(i):
import re
if not hasattr(isIntegre, '_re'):
print("I compile only once. Remove this line when you are confident in that.")
isIntegre._re = re.compile(r"[-+]?\d+(\.0*)?$")
return isIntegre._re.match(str(i)) is not None
# When executed directly run Unit Tests
if __name__ == '__main__':
for obj in [
# integers
0, 1, -1, 1.0, -1.0,
'0', '0.','0.0', '1', '-1', '+1', '1.0', '-1.0', '+1.0',
# non-integers
1.1, -1.1, '1.1', '-1.1', '+1.1',
'1.1.1', '1.1.0', '1.0.1', '1.0.0',
'1.0.', '1..0', '1..',
'0.0.', '0..0', '0..',
'one', object(), (1,2,3), [1,2,3], {'one':'two'}
]:
# Notice the integre uses 're' (intended to be humorous)
integer = ('an integer' if isInteger(obj) else 'NOT an integer')
integre = ('an integre' if isIntegre(obj) else 'NOT an integre')
# Make strings look like strings in the output
if isinstance(obj, str):
obj = ("'%s'" % (obj,))
print("%30s is %14s is %14s" % (obj, integer, integre))
对于那些不太喜欢冒险的同学,输出如下:
I compile only once. Remove this line when you are confident in that.
0 is an integer is an integre
1 is an integer is an integre
-1 is an integer is an integre
1.0 is an integer is an integre
-1.0 is an integer is an integre
'0' is an integer is an integre
'0.' is an integer is an integre
'0.0' is an integer is an integre
'1' is an integer is an integre
'-1' is an integer is an integre
'+1' is an integer is an integre
'1.0' is an integer is an integre
'-1.0' is an integer is an integre
'+1.0' is an integer is an integre
1.1 is NOT an integer is NOT an integre
-1.1 is NOT an integer is NOT an integre
'1.1' is NOT an integer is NOT an integre
'-1.1' is NOT an integer is NOT an integre
'+1.1' is NOT an integer is NOT an integre
'1.1.1' is NOT an integer is NOT an integre
'1.1.0' is NOT an integer is NOT an integre
'1.0.1' is NOT an integer is NOT an integre
'1.0.0' is NOT an integer is NOT an integre
'1.0.' is NOT an integer is NOT an integre
'1..0' is NOT an integer is NOT an integre
'1..' is NOT an integer is NOT an integre
'0.0.' is NOT an integer is NOT an integre
'0..0' is NOT an integer is NOT an integre
'0..' is NOT an integer is NOT an integre
'one' is NOT an integer is NOT an integre
<object object at 0x103b7d0a0> is NOT an integer is NOT an integre
(1, 2, 3) is NOT an integer is NOT an integre
[1, 2, 3] is NOT an integer is NOT an integre
{'one': 'two'} is NOT an integer is NOT an integre