有没有办法告诉一个字符串是否代表一个整数(例如,'3','-17'但不是'3.14'或'asfasfas')而不使用try/except机制?

is_int('3.14') == False
is_int('-7')   == True

当前回答

先决条件:

我们谈论的是整数(不是小数/浮点数); 内置int()的行为是我们的标准(有时很奇怪:“-00”是它的正确输入)

简短的回答:

使用下面的代码。它简单,正确(虽然这个线程中的许多变体不是),并且几乎是try/except和regex变体的两倍。

def is_int_str(string):
    return (
        string.startswith(('-', '+')) and string[1:].isdigit()
    ) or string.isdigit()

TL;博士答:

我已经测试了3个主要变体(1)try/except, (2) re.match()和(3)字符串操作(见上文)。第三个变体比try/except和re.match()快两倍。顺便说一句:regex变体是最慢的!请参见下面的测试脚本。

import re
import time


def test(func, test_suite):
    for test_case in test_suite:
        actual_result = func(*test_case[0])
        expected_result = test_case[1]
        assert (
            actual_result == expected_result
        ), f'Expected: {expected_result} but actual: {actual_result}'


def perf(func, test_suite):
    start = time.time()

    for _ in range(0, 1_000_000):
        test(func, test_suite)

    return time.time() - start


def is_int_str_1(string):
    try:
        int(string)
        return True
    except ValueError:
        return False


def is_int_str_2(string):
    return re.match(r'^[\-+]?\d+$', string) is not None


def is_int_str_3(string):
    return (
        string.startswith(('-', '+')) and string[1:].isdigit()
    ) or string.isdigit()


# Behavior of built-in int() function is a standard for the following tests
test_suite = [
    [['1'], True],  # func('1') -> True
    [['-1'], True],
    [['+1'], True],
    [['--1'], False],
    [['++1'], False],
    [['001'], True],  # because int() can read it
    [['-00'], True],  # because of quite strange behavior of int()
    [['-'], False],
    [['abracadabra'], False],
    [['57938759283475928347592347598357098458405834957984755200000000'], True],
]

time_span_1 = perf(is_int_str_1, test_suite)
time_span_2 = perf(is_int_str_2, test_suite)
time_span_3 = perf(is_int_str_3, test_suite)

print(f'{is_int_str_1.__name__}: {time_span_1} seconds')
print(f'{is_int_str_2.__name__}: {time_span_2} seconds')
print(f'{is_int_str_3.__name__}: {time_span_3} seconds')

输出是:

is_int_str_1: 4.314162969589233 seconds
is_int_str_2: 5.7216269969940186 seconds
is_int_str_3: 2.5828163623809814 seconds

其他回答

如果你真的不喜欢到处使用try/except,请写一个helper函数:

def represents_int(s):
    try: 
        int(s)
    except ValueError:
        return False
    else:
        return True
>>> print(represents_int("+123"))
True
>>> print(represents_int("10.0"))
False

它将需要更多的代码来精确覆盖Python认为是整数的所有字符串。要我说,你就用蟒语吧。

我认为

s.startswith('-') and s[1:].isdigit()

最好重写为:

s.replace('-', '').isdigit()

因为s[1:]也创建了一个新的字符串

但更好的解决办法是

s.lstrip('+-').isdigit()

下面是一个解析时不会产生错误的函数。它处理明显的情况,失败时返回None(在CPython上默认处理最多2000个'-/+'符号!):

#!/usr/bin/env python

def get_int(number):
    splits = number.split('.')
    if len(splits) > 2:
        # too many splits
        return None
    if len(splits) == 2 and splits[1]:
        # handle decimal part recursively :-)
        if get_int(splits[1]) != 0:
            return None

    int_part = splits[0].lstrip("+")
    if int_part.startswith('-'):
        # handle minus sign recursively :-)
        return get_int(int_part[1:]) * -1
    # successful 'and' returns last truth-y value (cast is always valid)
    return int_part.isdigit() and int(int_part)

一些测试:

tests = ["0", "0.0", "0.1", "1", "1.1", "1.0", "-1", "-1.1", "-1.0", "-0", "--0", "---3", '.3', '--3.', "+13", "+-1.00", "--+123", "-0.000"]

for t in tests:
    print "get_int(%s) = %s" % (t, get_int(str(t)))

结果:

get_int(0) = 0
get_int(0.0) = 0
get_int(0.1) = None
get_int(1) = 1
get_int(1.1) = None
get_int(1.0) = 1
get_int(-1) = -1
get_int(-1.1) = None
get_int(-1.0) = -1
get_int(-0) = 0
get_int(--0) = 0
get_int(---3) = -3
get_int(.3) = None
get_int(--3.) = 3
get_int(+13) = 13
get_int(+-1.00) = -1
get_int(--+123) = 123
get_int(-0.000) = 0

如有需要,可使用:

def int_predicate(number):
     return get_int(number) is not None

呃. .试试这个:

def int_check(a):
    if int(a) == a:
        return True
    else:
        return False

如果你不输入非数字的字符串,这是可行的。

还有(我忘了写数字检查部分了。),有一个函数检查字符串是否是数字。它是str.isdigit()。这里有一个例子:

a = 2
a.isdigit()

如果调用a.s isdigit(),它将返回True。

You know, I've found (and I've tested this over and over) that try/except does not perform all that well, for whatever reason. I frequently try several ways of doing things, and I don't think I've ever found a method that uses try/except to perform the best of those tested, in fact it seems to me those methods have usually come out close to the worst, if not the worst. Not in every case, but in many cases. I know a lot of people say it's the "Pythonic" way, but that's one area where I part ways with them. To me, it's neither very performant nor very elegant, so, I tend to only use it for error trapping and reporting.

我本来想抱怨PHP, perl, ruby, C,甚至是该死的shell都有简单的函数来测试字符串是否为整数,但在验证这些假设时,我被绊倒了!显然,这种缺乏是一种常见的疾病。

以下是布鲁诺的帖子的快速编辑:

import sys, time, re

g_intRegex = re.compile(r"^([+-]?[1-9]\d*|0)$")

testvals = [
    # integers
    0, 1, -1, 1.0, -1.0,
    '0', '0.','0.0', '1', '-1', '+1', '1.0', '-1.0', '+1.0', '06',
    # non-integers
    'abc 123',
    1.1, -1.1, '1.1', '-1.1', '+1.1',
    '1.1.1', '1.1.0', '1.0.1', '1.0.0',
    '1.0.', '1..0', '1..',
    '0.0.', '0..0', '0..',
    'one', object(), (1,2,3), [1,2,3], {'one':'two'},
    # with spaces
    ' 0 ', ' 0.', ' .0','.01 '
]

def isInt_try(v):
    try:     i = int(v)
    except:  return False
    return True

def isInt_str(v):
    v = str(v).strip()
    return v=='0' or (v if v.find('..') > -1 else v.lstrip('-+').rstrip('0').rstrip('.')).isdigit()

def isInt_re(v):
    import re
    if not hasattr(isInt_re, 'intRegex'):
        isInt_re.intRegex = re.compile(r"^([+-]?[1-9]\d*|0)$")
    return isInt_re.intRegex.match(str(v).strip()) is not None

def isInt_re2(v):
    return g_intRegex.match(str(v).strip()) is not None

def check_int(s):
    s = str(s)
    if s[0] in ('-', '+'):
        return s[1:].isdigit()
    return s.isdigit()    


def timeFunc(func, times):
    t1 = time.time()
    for n in range(times):
        for v in testvals: 
            r = func(v)
    t2 = time.time()
    return t2 - t1

def testFuncs(funcs):
    for func in funcs:
        sys.stdout.write( "\t%s\t|" % func.__name__)
    print()
    for v in testvals:
        if type(v) == type(''):
            sys.stdout.write("'%s'" % v)
        else:
            sys.stdout.write("%s" % str(v))
        for func in funcs:
            sys.stdout.write( "\t\t%s\t|" % func(v))
        sys.stdout.write("\r\n") 

if __name__ == '__main__':
    print()
    print("tests..")
    testFuncs((isInt_try, isInt_str, isInt_re, isInt_re2, check_int))
    print()

    print("timings..")
    print("isInt_try:   %6.4f" % timeFunc(isInt_try, 10000))
    print("isInt_str:   %6.4f" % timeFunc(isInt_str, 10000)) 
    print("isInt_re:    %6.4f" % timeFunc(isInt_re, 10000))
    print("isInt_re2:   %6.4f" % timeFunc(isInt_re2, 10000))
    print("check_int:   %6.4f" % timeFunc(check_int, 10000))

以下是性能比较结果:

timings..
isInt_try:   0.6426
isInt_str:   0.7382
isInt_re:    1.1156
isInt_re2:   0.5344
check_int:   0.3452

C语言的方法可以对它进行一次扫描。我认为,用C语言来扫描字符串是正确的做法。

编辑:

我更新了上面的代码,使其能够在Python 3.5中工作,并包含了来自当前投票最多的答案的check_int函数,并使用了我能找到的当前最流行的正则表达式来测试整型。这个正则表达式拒绝'abc 123'这样的字符串。我添加了'abc 123'作为测试值。

我很有趣地注意到,在这一点上,测试的所有函数,包括try方法、流行的check_int函数和最流行的正则表达式,都没有返回所有测试值的正确答案(好吧,这取决于你认为的正确答案是什么;请参阅下面的测试结果)。

内置的int()函数无声地截断浮点数的小数部分并返回小数之前的整数部分,除非浮点数首先转换为字符串。

check_int()函数对于0.0和1.0(技术上是整数)这样的值返回false,对于'06'这样的值返回true。

以下是当前(Python 3.5)的测试结果:

              isInt_try |       isInt_str       |       isInt_re        |       isInt_re2       |   check_int   |
0               True    |               True    |               True    |               True    |       True    |
1               True    |               True    |               True    |               True    |       True    |
-1              True    |               True    |               True    |               True    |       True    |
1.0             True    |               True    |               False   |               False   |       False   |
-1.0            True    |               True    |               False   |               False   |       False   |
'0'             True    |               True    |               True    |               True    |       True    |
'0.'            False   |               True    |               False   |               False   |       False   |
'0.0'           False   |               True    |               False   |               False   |       False   |
'1'             True    |               True    |               True    |               True    |       True    |
'-1'            True    |               True    |               True    |               True    |       True    |
'+1'            True    |               True    |               True    |               True    |       True    |
'1.0'           False   |               True    |               False   |               False   |       False   |
'-1.0'          False   |               True    |               False   |               False   |       False   |
'+1.0'          False   |               True    |               False   |               False   |       False   |
'06'            True    |               True    |               False   |               False   |       True    |
'abc 123'       False   |               False   |               False   |               False   |       False   |
1.1             True    |               False   |               False   |               False   |       False   |
-1.1            True    |               False   |               False   |               False   |       False   |
'1.1'           False   |               False   |               False   |               False   |       False   |
'-1.1'          False   |               False   |               False   |               False   |       False   |
'+1.1'          False   |               False   |               False   |               False   |       False   |
'1.1.1'         False   |               False   |               False   |               False   |       False   |
'1.1.0'         False   |               False   |               False   |               False   |       False   |
'1.0.1'         False   |               False   |               False   |               False   |       False   |
'1.0.0'         False   |               False   |               False   |               False   |       False   |
'1.0.'          False   |               False   |               False   |               False   |       False   |
'1..0'          False   |               False   |               False   |               False   |       False   |
'1..'           False   |               False   |               False   |               False   |       False   |
'0.0.'          False   |               False   |               False   |               False   |       False   |
'0..0'          False   |               False   |               False   |               False   |       False   |
'0..'           False   |               False   |               False   |               False   |       False   |
'one'           False   |               False   |               False   |               False   |       False   |
<obj..>         False   |               False   |               False   |               False   |       False   |
(1, 2, 3)       False   |               False   |               False   |               False   |       False   |
[1, 2, 3]       False   |               False   |               False   |               False   |       False   |
{'one': 'two'}  False   |               False   |               False   |               False   |       False   |
' 0 '           True    |               True    |               True    |               True    |       False   |
' 0.'           False   |               True    |               False   |               False   |       False   |
' .0'           False   |               False   |               False   |               False   |       False   |
'.01 '          False   |               False   |               False   |               False   |       False   |

刚才我试着添加这个函数:

def isInt_float(s):
    try:
        return float(str(s)).is_integer()
    except:
        return False

它的性能几乎与check_int(0.3486)一样好,对于1.0和0.0以及+1.0和0这样的值,它返回true。0等等。但它也为'06'返回true,所以。我想,选择你的毒药吧。