我如何编写两个函数,如果它以指定的字符/字符串开头或以指定的字符串结尾,那么它们将接受字符串并返回?

例如:

$str = '|apples}';

echo startsWith($str, '|'); //Returns true
echo endsWith($str, '}'); //Returns true

当前回答

这里有两个函数不会引入临时字符串,这在针头很大时可能很有用:

function startsWith($haystack, $needle)
{
    return strncmp($haystack, $needle, strlen($needle)) === 0;
}

function endsWith($haystack, $needle)
{
    return $needle === '' || substr_compare($haystack, $needle, -strlen($needle)) === 0;
}

其他回答

上面的正则表达式函数,但上面还建议了其他调整:

 function startsWith($needle, $haystack) {
     return preg_match('/^' . preg_quote($needle, '/') . '/', $haystack);
 }

 function endsWith($needle, $haystack) {
     return preg_match('/' . preg_quote($needle, '/') . '$/', $haystack);
 }

简而言之:

function startsWith($str, $needle){
   return substr($str, 0, strlen($needle)) === $needle;
}

function endsWith($str, $needle){
   $length = strlen($needle);
   return !$length || substr($str, - $length) === $needle;
}

无副本,无实习循环:

function startsWith(string $string, string $start): bool
{
    return strrpos($string, $start, - strlen($string)) !== false;
}

function endsWith(string $string, string $end): bool
{
    return ($offset = strlen($string) - strlen($end)) >= 0 
    && strpos($string, $end, $offset) !== false;
}

2016年8月23日更新

功能

function substr_startswith($haystack, $needle) {
    return substr($haystack, 0, strlen($needle)) === $needle;
}

function preg_match_startswith($haystack, $needle) {
    return preg_match('~' . preg_quote($needle, '~') . '~A', $haystack) > 0;
}

function substr_compare_startswith($haystack, $needle) {
    return substr_compare($haystack, $needle, 0, strlen($needle)) === 0;
}

function strpos_startswith($haystack, $needle) {
    return strpos($haystack, $needle) === 0;
}

function strncmp_startswith($haystack, $needle) {
    return strncmp($haystack, $needle, strlen($needle)) === 0;
}

function strncmp_startswith2($haystack, $needle) {
    return $haystack[0] === $needle[0]
        ? strncmp($haystack, $needle, strlen($needle)) === 0
        : false;
}

测验

echo 'generating tests';
for($i = 0; $i < 100000; ++$i) {
    if($i % 2500 === 0) echo '.';
    $test_cases[] = [
        random_bytes(random_int(1, 7000)),
        random_bytes(random_int(1, 3000)),
    ];
}
echo "done!\n";


$functions = ['substr_startswith', 'preg_match_startswith', 'substr_compare_startswith', 'strpos_startswith', 'strncmp_startswith', 'strncmp_startswith2'];
$results = [];

foreach($functions as $func) {
    $start = microtime(true);
    foreach($test_cases as $tc) {
        $func(...$tc);
    }
    $results[$func] = (microtime(true) - $start) * 1000;
}

asort($results);

foreach($results as $func => $time) {
    echo "$func: " . number_format($time, 1) . " ms\n";
}

结果(PHP 7.0.9)

(从最快到最慢排序)

strncmp_startswith2: 40.2 ms
strncmp_startswith: 42.9 ms
substr_compare_startswith: 44.5 ms
substr_startswith: 48.4 ms
strpos_startswith: 138.7 ms
preg_match_startswith: 13,152.4 ms

结果(PHP 5.3.29)

(从最快到最慢排序)

strncmp_startswith2: 477.9 ms
strpos_startswith: 522.1 ms
strncmp_startswith: 617.1 ms
substr_compare_startswith: 706.7 ms
substr_startswith: 756.8 ms
preg_match_startswith: 10,200.0 ms

启动基准.php

专注于startswith,如果您确定字符串不为空,那么在比较之前,在第一个字符、strlen等上添加一个测试会加快速度:

function startswith5b($haystack, $needle) {
    return ($haystack{0}==$needle{0})?strncmp($haystack, $needle, strlen($needle)) === 0:FALSE;
}

不知怎么的,速度快了(20%-30%)。添加另一个字符测试,如$haystack{1}==$needle{1},似乎并不能加快速度,甚至可能会减慢速度。

==似乎比==条件运算符(a)?b: c似乎比如果(a)b更快;否则c;


对于那些问“为什么不使用strpos?”并称其他解决方案为“不必要的工作”的人


strpos速度很快,但它不是这项工作的正确工具。

为了理解,这里有一个小模拟作为示例:

Search a12345678c inside bcdefga12345678xbbbbb.....bbbbba12345678c

电脑在里面做什么?

    With strccmp, etc...

    is a===b? NO
    return false



    With strpos

    is a===b? NO -- iterating in haysack
    is a===c? NO
    is a===d? NO
    ....
    is a===g? NO
    is a===g? NO
    is a===a? YES
    is 1===1? YES -- iterating in needle
    is 2===3? YES
    is 4===4? YES
    ....
    is 8===8? YES
    is c===x? NO: oh God,
    is a===1? NO -- iterating in haysack again
    is a===2? NO
    is a===3? NO
    is a===4? NO
    ....
    is a===x? NO
    is a===b? NO
    is a===b? NO
    is a===b? NO
    is a===b? NO
    is a===b? NO
    is a===b? NO
    is a===b? NO
    ...
    ... may many times...
    ...
    is a===b? NO
    is a===a? YES -- iterating in needle again
    is 1===1? YES
    is 2===3? YES
    is 4===4? YES
    is 8===8? YES
    is c===c? YES YES YES I have found the same string! yay!
    was it at position 0? NOPE
    What you mean NO? So the string I found is useless? YEs.
    Damn.
    return false

假设strlen不迭代整个字符串(但即使在这种情况下),这一点都不方便。