你可以尝试跟随函数，它会以字符串格式返回你的phoneModel名字。

public String phoneModel() {

    return Build.MODEL;
}

对于谁谁寻找完整的属性列表构建这里是一个索尼Z1 Compact的例子:

Build.BOARD = MSM8974
Build.BOOTLOADER = s1
Build.BRAND = Sony
Build.CPU_ABI = armeabi-v7a
Build.CPU_ABI2 = armeabi
Build.DEVICE = D5503
Build.DISPLAY = 14.6.A.1.236
Build.FINGERPRINT = Sony/D5503/D5503:5.1.1/14.6.A.1.236/2031203XXX:user/release-keys
Build.HARDWARE = qcom
Build.HOST = BuildHost
Build.ID = 14.6.A.1.236
Build.IS_DEBUGGABLE = false
Build.MANUFACTURER = Sony
Build.MODEL = D5503
Build.PRODUCT = D5503
Build.RADIO = unknown
Build.SERIAL = CB5A1YGVMT
Build.SUPPORTED_32_BIT_ABIS = [Ljava.lang.String;@3dd90541
Build.SUPPORTED_64_BIT_ABIS = [Ljava.lang.String;@1da4fc3
Build.SUPPORTED_ABIS = [Ljava.lang.String;@525f635
Build.TAGS = release-keys
Build.TIME = 144792559XXXX
Build.TYPE = user
Build.UNKNOWN = unknown
Build.USER = BuildUser

你可以在调试模式下使用kotlin的“evaluate expression”对话框轻松列出这些属性:

android.os.Build::class.java.fields.map { "Build.${it.name} = ${it.get(it.name)}"}.joinToString("\n")

事实上，这不是百分之百正确的。这可以为您提供模型(有时是数字)。 将为您提供手机制造商(HTC部分您的请求):

 Build.MANUFACTURER

产品名称:

 Build.PRODUCT

芬兰湾的科特林版本

val Name: String by lazy {
    val manufacturer = Build.MANUFACTURER
    val model = Build.MODEL
    if (model.toLowerCase().startsWith(manufacturer.toLowerCase())) {
        capitalize(model)
    } else {
        capitalize(manufacturer) + " " + model
    }
}

private fun capitalize(s: String?): String {
    if (s == null || s.isEmpty()) {
        return ""
    }
    val first = s[0]
    return if (Character.isUpperCase(first)) {
        s
    } else {
        Character.toUpperCase(first) + s.substring(1)
    }
}

你可以尝试跟随函数，它会以字符串格式返回你的phoneModel名字。

public String phoneModel() {

    return Build.MODEL;
}

是的:Build.MODEL。