我想知道是否有一种在Android中以编程方式阅读手机模型的方法。
我想要一个像HTC梦想,里程碑,蓝宝石或任何字符串…
我想知道是否有一种在Android中以编程方式阅读手机模型的方法。
我想要一个像HTC梦想,里程碑,蓝宝石或任何字符串…
当前回答
对于谁谁寻找完整的属性列表构建这里是一个索尼Z1 Compact的例子:
Build.BOARD = MSM8974
Build.BOOTLOADER = s1
Build.BRAND = Sony
Build.CPU_ABI = armeabi-v7a
Build.CPU_ABI2 = armeabi
Build.DEVICE = D5503
Build.DISPLAY = 14.6.A.1.236
Build.FINGERPRINT = Sony/D5503/D5503:5.1.1/14.6.A.1.236/2031203XXX:user/release-keys
Build.HARDWARE = qcom
Build.HOST = BuildHost
Build.ID = 14.6.A.1.236
Build.IS_DEBUGGABLE = false
Build.MANUFACTURER = Sony
Build.MODEL = D5503
Build.PRODUCT = D5503
Build.RADIO = unknown
Build.SERIAL = CB5A1YGVMT
Build.SUPPORTED_32_BIT_ABIS = [Ljava.lang.String;@3dd90541
Build.SUPPORTED_64_BIT_ABIS = [Ljava.lang.String;@1da4fc3
Build.SUPPORTED_ABIS = [Ljava.lang.String;@525f635
Build.TAGS = release-keys
Build.TIME = 144792559XXXX
Build.TYPE = user
Build.UNKNOWN = unknown
Build.USER = BuildUser
你可以在调试模式下使用kotlin的“evaluate expression”对话框轻松列出这些属性:
android.os.Build::class.java.fields.map { "Build.${it.name} = ${it.get(it.name)}"}.joinToString("\n")
其他回答
芬兰湾的科特林版本
val Name: String by lazy {
val manufacturer = Build.MANUFACTURER
val model = Build.MODEL
if (model.toLowerCase().startsWith(manufacturer.toLowerCase())) {
capitalize(model)
} else {
capitalize(manufacturer) + " " + model
}
}
private fun capitalize(s: String?): String {
if (s == null || s.isEmpty()) {
return ""
}
val first = s[0]
return if (Character.isUpperCase(first)) {
s
} else {
Character.toUpperCase(first) + s.substring(1)
}
}
Build.DEVICE // The name of the industrial design.
构建。DEVICE为某些设备提供人类可读的名称。模型
Build.DEVICE = OnePlus6
Build.MANUFACTURER = OnePlus
Build.MODEL = ONEPLUS A6003
我使用下面的代码来获取完整的设备名称。它获得模型和制造商字符串并连接它们,除非模型字符串已经包含制造商名称(在一些手机上):
public String getDeviceName() {
String manufacturer = Build.MANUFACTURER;
String model = Build.MODEL;
if (model.toLowerCase().startsWith(manufacturer.toLowerCase())) {
return capitalize(model);
} else {
return capitalize(manufacturer) + " " + model;
}
}
private String capitalize(String s) {
if (s == null || s.length() == 0) {
return "";
}
char first = s.charAt(0);
if (Character.isUpperCase(first)) {
return s;
} else {
return Character.toUpperCase(first) + s.substring(1);
}
}
以下是我从用户那里得到的一些设备名称示例:
三星GT-S5830L 摩托罗拉MB860 索尼爱立信LT18i LGE LG-P500 HTC Desire V HTC野火S A510e ...
这是我的代码,以获得制造商,品牌名称,Os版本和支持API级别
String manufacturer = Build.MANUFACTURER;
String model = Build.MODEL + " " + android.os.Build.BRAND +" ("
+ android.os.Build.VERSION.RELEASE+")"
+ " API-" + android.os.Build.VERSION.SDK_INT;
if (model.startsWith(manufacturer)) {
return capitalize(model);
} else {
return capitalize(manufacturer) + " " + model;
}
输出:
System.out: button press on device name = Lava Alfa L iris(5.0) API-21
在许多流行的设备上,该设备的市场名称是不可用的。例如,在三星Galaxy S6上,Build的值。MODEL可以是“SM-G920F”、“SM-G920I”或“SM-G920W8”。
我创建了一个小型库,用于获取设备的市场(消费者友好)名称。它为超过10,000个设备获得正确的名称,并不断更新。如果你想使用我的图书馆,请点击下面的链接:
Github上的AndroidDeviceNames库
如果你不想使用上面的库,那么这是获得一个消费者友好的设备名称的最佳解决方案:
/** Returns the consumer friendly device name */
public static String getDeviceName() {
String manufacturer = Build.MANUFACTURER;
String model = Build.MODEL;
if (model.startsWith(manufacturer)) {
return capitalize(model);
}
return capitalize(manufacturer) + " " + model;
}
private static String capitalize(String str) {
if (TextUtils.isEmpty(str)) {
return str;
}
char[] arr = str.toCharArray();
boolean capitalizeNext = true;
StringBuilder phrase = new StringBuilder();
for (char c : arr) {
if (capitalizeNext && Character.isLetter(c)) {
phrase.append(Character.toUpperCase(c));
capitalizeNext = false;
continue;
} else if (Character.isWhitespace(c)) {
capitalizeNext = true;
}
phrase.append(c);
}
return phrase.toString();
}
以我的Verizon HTC One M8为例:
// using method from above
System.out.println(getDeviceName());
// Using https://github.com/jaredrummler/AndroidDeviceNames
System.out.println(DeviceName.getDeviceName());
结果:
HTC6525LVW HTC One (M8)