我想知道是否有一种在Android中以编程方式阅读手机模型的方法。

我想要一个像HTC梦想,里程碑,蓝宝石或任何字符串…


当前回答

芬兰湾的科特林版本

val Name: String by lazy {
    val manufacturer = Build.MANUFACTURER
    val model = Build.MODEL
    if (model.toLowerCase().startsWith(manufacturer.toLowerCase())) {
        capitalize(model)
    } else {
        capitalize(manufacturer) + " " + model
    }
}

private fun capitalize(s: String?): String {
    if (s == null || s.isEmpty()) {
        return ""
    }
    val first = s[0]
    return if (Character.isUpperCase(first)) {
        s
    } else {
        Character.toUpperCase(first) + s.substring(1)
    }
}

其他回答

是的:Build.MODEL。

Kotlin简写版:

import android.os.Build.MANUFACTURER
import android.os.Build.MODEL

fun getDeviceName(): String =
    if (MODEL.startsWith(MANUFACTURER, ignoreCase = true)) {
        MODEL
    } else {
        "$MANUFACTURER $MODEL"
    }.capitalize(Locale.ROOT)

显然你需要使用https://support.google.com/googleplay/answer/1727131上谷歌的列表

api不会返回任何我期望的东西或设置中的任何东西。对于我的摩托罗拉X,这是我得到的

   Build.MODEL = "XT1053"
   Build.BRAND = "motorola"
   Build.PRODUCT = "ghost"

转到上面提到的Moto x的“幽灵”地图页面,似乎这可以简单一点…

当你想要检索制造商、设备名称和/或型号时,以下字符串都是有用的:

String manufacturer = Build.MANUFACTURER;
String brand        = Build.BRAND;
String product      = Build.PRODUCT;
String model        = Build.MODEL;

芬兰湾的科特林版本

val Name: String by lazy {
    val manufacturer = Build.MANUFACTURER
    val model = Build.MODEL
    if (model.toLowerCase().startsWith(manufacturer.toLowerCase())) {
        capitalize(model)
    } else {
        capitalize(manufacturer) + " " + model
    }
}

private fun capitalize(s: String?): String {
    if (s == null || s.isEmpty()) {
        return ""
    }
    val first = s[0]
    return if (Character.isUpperCase(first)) {
        s
    } else {
        Character.toUpperCase(first) + s.substring(1)
    }
}