下面是平滑z-score算法的Python / numpy实现(见上面的答案)。你可以在这里找到要点。
#!/usr/bin/env python
# Implementation of algorithm from https://stackoverflow.com/a/22640362/6029703
import numpy as np
import pylab
def thresholding_algo(y, lag, threshold, influence):
signals = np.zeros(len(y))
filteredY = np.array(y)
avgFilter = [0]*len(y)
stdFilter = [0]*len(y)
avgFilter[lag - 1] = np.mean(y[0:lag])
stdFilter[lag - 1] = np.std(y[0:lag])
for i in range(lag, len(y)):
if abs(y[i] - avgFilter[i-1]) > threshold * stdFilter [i-1]:
if y[i] > avgFilter[i-1]:
signals[i] = 1
else:
signals[i] = -1
filteredY[i] = influence * y[i] + (1 - influence) * filteredY[i-1]
avgFilter[i] = np.mean(filteredY[(i-lag+1):i+1])
stdFilter[i] = np.std(filteredY[(i-lag+1):i+1])
else:
signals[i] = 0
filteredY[i] = y[i]
avgFilter[i] = np.mean(filteredY[(i-lag+1):i+1])
stdFilter[i] = np.std(filteredY[(i-lag+1):i+1])
return dict(signals = np.asarray(signals),
avgFilter = np.asarray(avgFilter),
stdFilter = np.asarray(stdFilter))
下面是在同一个数据集上的测试,它产生的图与R/Matlab的原始答案相同
# Data
y = np.array([1,1,1.1,1,0.9,1,1,1.1,1,0.9,1,1.1,1,1,0.9,1,1,1.1,1,1,1,1,1.1,0.9,1,1.1,1,1,0.9,
1,1.1,1,1,1.1,1,0.8,0.9,1,1.2,0.9,1,1,1.1,1.2,1,1.5,1,3,2,5,3,2,1,1,1,0.9,1,1,3,
2.6,4,3,3.2,2,1,1,0.8,4,4,2,2.5,1,1,1])
# Settings: lag = 30, threshold = 5, influence = 0
lag = 30
threshold = 5
influence = 0
# Run algo with settings from above
result = thresholding_algo(y, lag=lag, threshold=threshold, influence=influence)
# Plot result
pylab.subplot(211)
pylab.plot(np.arange(1, len(y)+1), y)
pylab.plot(np.arange(1, len(y)+1),
result["avgFilter"], color="cyan", lw=2)
pylab.plot(np.arange(1, len(y)+1),
result["avgFilter"] + threshold * result["stdFilter"], color="green", lw=2)
pylab.plot(np.arange(1, len(y)+1),
result["avgFilter"] - threshold * result["stdFilter"], color="green", lw=2)
pylab.subplot(212)
pylab.step(np.arange(1, len(y)+1), result["signals"], color="red", lw=2)
pylab.ylim(-1.5, 1.5)
pylab.show()