我在silverlight应用程序中有一个比较2个字符串的条件，由于某种原因，当我使用==时，它返回false而. equals()返回true。
代码如下:
if (((ListBoxItem)lstBaseMenu.SelectedItem).Content.Equals("Energy Attack"))
{
// Execute code
}
if (((ListBoxItem)lstBaseMenu.SelectedItem).Content == "Energy Attack")
{
// Execute code
}
你知道为什么会这样吗?
当前回答
The == token in C# is used for two different equality-check operators. When the compiler encounters that token, it will check whether either of the types being compared has implemented an equality-operator overload for either the specific combination types being compared(*), or for a combination of types to which both types can be converted. If the compiler finds such an overload it will use it. Otherwise, if the two types are both reference types and they are not unrelated classes (either may be an interface, or they may be related classes), the compiler will regard == as a reference-comparison operator. If neither condition applies, compilation will fail.
请注意，其他一些语言为两个相等检查操作符使用单独的令牌。在VB。例如，=令牌在表达式中仅用于可重载的相等检查操作符，而is则用作引用测试或空测试操作符。在没有覆盖相等检查操作符的类型上使用=将会失败，在测试引用是否相等或为空之外的任何目的上尝试使用Is也会失败。
(*)Types generally only overload equality for comparison with themselves, but it may be useful for types to overload the equality operator for comparison with other particular types; for example, int could have (and IMHO should have but didn't) defined an equality operators for comparison with float, so that 16777217 would not report itself equal to 16777216f. As it is, since no such operator is defined, C# will promote the int to float, rounding it to 16777216f before the equality-check operator sees it; that operator then sees two equal floating-point numbers and reports them as equal, unaware of the rounding that took place.
其他回答
给答案再加一分。
. equalsto()方法提供了比较区域性和区分大小写的方法。
据我所知，答案很简单:
==比较对象引用。 . equals比较对象内容。 字符串数据类型的作用总是类似于内容比较。
我希望我是对的，这回答了你的问题。
= =操作符
如果操作数为值类型且值相等，则返回true否则为false。 如果操作数是引用类型(string除外)，并且都引用同一个实例(同一对象)，则返回true否则返回false。 如果操作数为字符串类型且值相等，则返回true否则返回false。
.Equals
如果操作数是引用类型，它执行引用相等，即如果两个操作数都引用同一个实例(同一个对象)，则返回true否则返回false。 如果操作数是值类型，那么与==运算符不同，它首先检查它们的类型，如果它们的类型相同，它执行==运算符，否则返回false。
Equal和==之间的唯一区别是对象类型比较。在其他情况下，例如引用类型和值类型，它们几乎是相同的(要么都是位相等，要么都是引用相等)。
对象: Equals:位的相等 ==:引用相等
String:(equals和==对于String是相同的，但如果字符串中的一个被更改为object，则比较结果将不同) Equals:位的相等 ==:位相等
更多的解释请看这里。
@BlueMonkMN早前的回答还有另一个层面。额外的维度是，@Drahcir的标题问题的答案也取决于我们如何得到字符串值。说明:
string s1 = "test";
string s2 = "test";
string s3 = "test1".Substring(0, 4);
object s4 = s3;
string s5 = "te" + "st";
object s6 = s5;
Console.WriteLine("{0} {1} {2}", object.ReferenceEquals(s1, s2), s1 == s2, s1.Equals(s2));
Console.WriteLine("\n Case1 - A method changes the value:");
Console.WriteLine("{0} {1} {2}", object.ReferenceEquals(s1, s3), s1 == s3, s1.Equals(s3));
Console.WriteLine("{0} {1} {2}", object.ReferenceEquals(s1, s4), s1 == s4, s1.Equals(s4));
Console.WriteLine("\n Case2 - Having only literals allows to arrive at a literal:");
Console.WriteLine("{0} {1} {2}", object.ReferenceEquals(s1, s5), s1 == s5, s1.Equals(s5));
Console.WriteLine("{0} {1} {2}", object.ReferenceEquals(s1, s6), s1 == s6, s1.Equals(s6));
输出结果为:
True True True
Case1 - A method changes the value:
False True True
False False True
Case2 - Having only literals allows to arrive at a literal:
True True True
True True True
