如何获得方法的执行时间? 是否有Timer实用程序类来计时任务所需的时间等?
在谷歌上的大多数搜索都返回调度线程和任务的计时器的结果,这不是我想要的。
如何获得方法的执行时间? 是否有Timer实用程序类来计时任务所需的时间等?
在谷歌上的大多数搜索都返回调度线程和任务的计时器的结果,这不是我想要的。
当前回答
我修改了代码,从正确答案得到的结果在几秒钟内:
long startTime = System.nanoTime();
methodCode ...
long endTime = System.nanoTime();
double duration = (double)(endTime - startTime) / (Math.pow(10, 9));
Log.v(TAG, "MethodName time (s) = " + duration);
其他回答
纯Java SE代码,不需要添加依赖项,使用TimeTracedExecuter:
public static void main(String[] args) {
Integer square = new TimeTracedExecutor<>(Main::calculateSquare)
.executeWithInput("calculate square of num",5,logger);
}
public static int calculateSquare(int num){
return num*num;
}
会产生这样的结果:
信息:计算num的平方需要3毫秒
自定义可重用类:TimeTracedExecutor
import java.text.NumberFormat;
import java.time.Duration;
import java.time.Instant;
import java.util.function.Function;
import java.util.logging.Logger;
public class TimeTracedExecutor<T,R> {
Function<T,R> methodToExecute;
public TimeTracedExecutor(Function<T, R> methodToExecute) {
this.methodToExecute = methodToExecute;
}
public R executeWithInput(String taskDescription, T t, Logger logger){
Instant start = Instant.now();
R r= methodToExecute.apply(t);
Instant finish = Instant.now();
String format = "It took %s milliseconds to "+taskDescription;
String elapsedTime = NumberFormat.getNumberInstance().format(Duration.between(start, finish).toMillis());
logger.info(String.format(format, elapsedTime));
return r;
}
}
非常好的代码。
http://www.rgagnon.com/javadetails/java-0585.html
import java.util.concurrent.TimeUnit;
long startTime = System.currentTimeMillis();
........
........
........
long finishTime = System.currentTimeMillis();
String diff = millisToShortDHMS(finishTime - startTime);
/**
* converts time (in milliseconds) to human-readable format
* "<dd:>hh:mm:ss"
*/
public static String millisToShortDHMS(long duration) {
String res = "";
long days = TimeUnit.MILLISECONDS.toDays(duration);
long hours = TimeUnit.MILLISECONDS.toHours(duration)
- TimeUnit.DAYS.toHours(TimeUnit.MILLISECONDS.toDays(duration));
long minutes = TimeUnit.MILLISECONDS.toMinutes(duration)
- TimeUnit.HOURS.toMinutes(TimeUnit.MILLISECONDS.toHours(duration));
long seconds = TimeUnit.MILLISECONDS.toSeconds(duration)
- TimeUnit.MINUTES.toSeconds(TimeUnit.MILLISECONDS.toMinutes(duration));
if (days == 0) {
res = String.format("%02d:%02d:%02d", hours, minutes, seconds);
}
else {
res = String.format("%dd%02d:%02d:%02d", days, hours, minutes, seconds);
}
return res;
}
long startTime = System.currentTimeMillis();
// code goes here
long finishTime = System.currentTimeMillis();
long elapsedTime = finishTime - startTime; // elapsed time in milliseconds
我实现了一个简单的定时器,我认为它真的很有用:
public class Timer{
private static long start_time;
public static double tic(){
return start_time = System.nanoTime();
}
public static double toc(){
return (System.nanoTime()-start_time)/1000000000.0;
}
}
这样你就可以计算一个或多个动作的时间:
Timer.tic();
// Code 1
System.out.println("Code 1 runtime: "+Timer.toc()+" seconds.");
// Code 2
System.out.println("(Code 1 + Code 2) runtime: "+Timer.toc()+"seconds");
Timer.tic();
// Code 3
System.out.println("Code 3 runtime: "+Timer.toc()+" seconds.");
总有一些过时的方法:
long startTime = System.nanoTime();
methodToTime();
long endTime = System.nanoTime();
long duration = (endTime - startTime); //divide by 1000000 to get milliseconds.