如何获得方法的执行时间? 是否有Timer实用程序类来计时任务所需的时间等?

在谷歌上的大多数搜索都返回调度线程和任务的计时器的结果,这不是我想要的。


当前回答

我实现了一个简单的定时器,我认为它真的很有用:

public class Timer{
    private static long start_time;

    public static double tic(){
        return start_time = System.nanoTime();
    }

    public static double toc(){
        return (System.nanoTime()-start_time)/1000000000.0;
    }

}

这样你就可以计算一个或多个动作的时间:

Timer.tic();
// Code 1
System.out.println("Code 1 runtime: "+Timer.toc()+" seconds.");
// Code 2
System.out.println("(Code 1 + Code 2) runtime: "+Timer.toc()+"seconds");
Timer.tic();
// Code 3
System.out.println("Code 3 runtime: "+Timer.toc()+" seconds.");

其他回答

我实现了一个简单的定时器,我认为它真的很有用:

public class Timer{
    private static long start_time;

    public static double tic(){
        return start_time = System.nanoTime();
    }

    public static double toc(){
        return (System.nanoTime()-start_time)/1000000000.0;
    }

}

这样你就可以计算一个或多个动作的时间:

Timer.tic();
// Code 1
System.out.println("Code 1 runtime: "+Timer.toc()+" seconds.");
// Code 2
System.out.println("(Code 1 + Code 2) runtime: "+Timer.toc()+"seconds");
Timer.tic();
// Code 3
System.out.println("Code 3 runtime: "+Timer.toc()+" seconds.");

非常好的代码。

http://www.rgagnon.com/javadetails/java-0585.html

import java.util.concurrent.TimeUnit;

long startTime = System.currentTimeMillis();
........
........
........
long finishTime = System.currentTimeMillis();

String diff = millisToShortDHMS(finishTime - startTime);


  /**
   * converts time (in milliseconds) to human-readable format
   *  "<dd:>hh:mm:ss"
   */
  public static String millisToShortDHMS(long duration) {
    String res = "";
    long days  = TimeUnit.MILLISECONDS.toDays(duration);
    long hours = TimeUnit.MILLISECONDS.toHours(duration)
                   - TimeUnit.DAYS.toHours(TimeUnit.MILLISECONDS.toDays(duration));
    long minutes = TimeUnit.MILLISECONDS.toMinutes(duration)
                     - TimeUnit.HOURS.toMinutes(TimeUnit.MILLISECONDS.toHours(duration));
    long seconds = TimeUnit.MILLISECONDS.toSeconds(duration)
                   - TimeUnit.MINUTES.toSeconds(TimeUnit.MILLISECONDS.toMinutes(duration));
    if (days == 0) {
      res = String.format("%02d:%02d:%02d", hours, minutes, seconds);
    }
    else {
      res = String.format("%dd%02d:%02d:%02d", days, hours, minutes, seconds);
    }
    return res;
  }

下面是打印好的字符串,格式化后的秒数,类似于谷歌搜索所需的时间:

        long startTime = System.nanoTime();
        //  ... methodToTime();
        long endTime = System.nanoTime();
        long duration = (endTime - startTime);
        long seconds = (duration / 1000) % 60;
        // formatedSeconds = (0.xy seconds)
        String formatedSeconds = String.format("(0.%d seconds)", seconds);
        System.out.println("formatedSeconds = "+ formatedSeconds);
        // i.e actual formatedSeconds = (0.52 seconds)

您可以使用Perf4j。非常酷的实用工具。用法简单

String watchTag = "target.SomeMethod";
StopWatch stopWatch = new LoggingStopWatch(watchTag);
Result result = null; // Result is a type of a return value of a method
try {
    result = target.SomeMethod();
    stopWatch.stop(watchTag + ".success");
} catch (Exception e) {
    stopWatch.stop(watchTag + ".fail", "Exception was " + e);
    throw e; 
}

更多信息可以在开发者指南中找到

编辑:项目似乎已死

也可以实现定时器接口,并在类的任何方法上执行

import java.util.function.*;

public interface Timer {

    default void timeIt(Runnable r) {
        timeIt(() -> { r.run(); return 0;});
    }

    default <S,T> T timeIt(Function<S,T> fun, S arg) {
        long start = System.nanoTime();
        T result = fun.apply(arg);
        long stop = System.nanoTime();
        System.out.println("Time: " + (stop-start)/1000000.0 + " msec");
        return result;
    }

    default <T> T timeIt(Supplier<T> s) {
        return timeIt(obj -> s.get(), null);
    }
}

用法:

class MyClass implements Timer ..

timeIt(this::myFunction);