如何获得方法的执行时间? 是否有Timer实用程序类来计时任务所需的时间等?
在谷歌上的大多数搜索都返回调度线程和任务的计时器的结果,这不是我想要的。
如何获得方法的执行时间? 是否有Timer实用程序类来计时任务所需的时间等?
在谷歌上的大多数搜索都返回调度线程和任务的计时器的结果,这不是我想要的。
当前回答
如果你想要时间
long start_time = System.currentTimeMillis();
object.method();
long end_time = System.currentTimeMillis();
long execution_time = end_time - start_time;
其他回答
纯Java SE代码,不需要添加依赖项,使用TimeTracedExecuter:
public static void main(String[] args) {
Integer square = new TimeTracedExecutor<>(Main::calculateSquare)
.executeWithInput("calculate square of num",5,logger);
}
public static int calculateSquare(int num){
return num*num;
}
会产生这样的结果:
信息:计算num的平方需要3毫秒
自定义可重用类:TimeTracedExecutor
import java.text.NumberFormat;
import java.time.Duration;
import java.time.Instant;
import java.util.function.Function;
import java.util.logging.Logger;
public class TimeTracedExecutor<T,R> {
Function<T,R> methodToExecute;
public TimeTracedExecutor(Function<T, R> methodToExecute) {
this.methodToExecute = methodToExecute;
}
public R executeWithInput(String taskDescription, T t, Logger logger){
Instant start = Instant.now();
R r= methodToExecute.apply(t);
Instant finish = Instant.now();
String format = "It took %s milliseconds to "+taskDescription;
String elapsedTime = NumberFormat.getNumberInstance().format(Duration.between(start, finish).toMillis());
logger.info(String.format(format, elapsedTime));
return r;
}
}
总有一些过时的方法:
long startTime = System.nanoTime();
methodToTime();
long endTime = System.nanoTime();
long duration = (endTime - startTime); //divide by 1000000 to get milliseconds.
在Java 8中引入了一个名为Instant的新类。根据文件:
Instant represents the start of a nanosecond on the time line. This class is useful for generating a time stamp to represent machine time. The range of an instant requires the storage of a number larger than a long. To achieve this, the class stores a long representing epoch-seconds and an int representing nanosecond-of-second, which will always be between 0 and 999,999,999. The epoch-seconds are measured from the standard Java epoch of 1970-01-01T00:00:00Z where instants after the epoch have positive values, and earlier instants have negative values. For both the epoch-second and nanosecond parts, a larger value is always later on the time-line than a smaller value.
这可以用于:
Instant start = Instant.now();
try {
Thread.sleep(7000);
} catch (InterruptedException e) {
e.printStackTrace();
}
Instant end = Instant.now();
System.out.println(Duration.between(start, end));
打印pt7.001。
在java ee中对我有效的策略是:
Create a class with a method annotated with @AroundInvoke; @Singleton public class TimedInterceptor implements Serializable { @AroundInvoke public Object logMethod(InvocationContext ic) throws Exception { Date start = new Date(); Object result = ic.proceed(); Date end = new Date(); System.out.println("time: " + (end.getTime - start.getTime())); return result; } } Annotate the method that you want to monitoring: @Interceptors(TimedInterceptor.class) public void onMessage(final Message message) { ...
我希望这能有所帮助。
我的答案很简单。对我有用。
long startTime = System.currentTimeMillis();
doReallyLongThing();
long endTime = System.currentTimeMillis();
System.out.println("That took " + (endTime - startTime) + " milliseconds");
它运行得很好。分辨率显然只有毫秒级,使用System.nanoTime()可以做得更好。这两种方法都有一些限制(操作系统调度切片等),但效果很好。
平均几次运行(越多越好),你就会得到一个不错的想法。