我需要随机洗牌以下数组:

int[] solutionArray = {1, 2, 3, 4, 5, 6, 6, 5, 4, 3, 2, 1};

有什么函数可以做到吗?


当前回答

public class ShuffleArray {
public static void shuffleArray(int[] a) {
    int n = a.length;
    Random random = new Random();
    random.nextInt();
    for (int i = 0; i < n; i++) {
        int change = i + random.nextInt(n - i);
        swap(a, i, change);
    }
}

private static void swap(int[] a, int i, int change) {
    int helper = a[i];
    a[i] = a[change];
    a[change] = helper;
}

public static void main(String[] args) {
    int[] a = new int[] { 1, 2, 3, 4, 5, 6, 6, 5, 4, 3, 2, 1 };
    shuffleArray(a);
    for (int i : a) {
        System.out.println(i);
    }
}
}

其他回答

下面是一个有效的Fisher-Yates shuffle数组函数:

private static void shuffleArray(int[] array)
{
    int index;
    Random random = new Random();
    for (int i = array.length - 1; i > 0; i--)
    {
        index = random.nextInt(i + 1);
        if (index != i)
        {
            array[index] ^= array[i];
            array[i] ^= array[index];
            array[index] ^= array[i];
        }
    }
}

or

private static void shuffleArray(int[] array)
{
    int index, temp;
    Random random = new Random();
    for (int i = array.length - 1; i > 0; i--)
    {
        index = random.nextInt(i + 1);
        temp = array[index];
        array[index] = array[i];
        array[i] = temp;
    }
}

在Java中,我们可以使用集合。Shuffle方法随机重新排列列表中的项目。

Groovy 3.0.0直接将shuffle和shuffle方法添加到List或数组中。

下面是一个使用数组列表的简单方法:

List<Integer> solution = new ArrayList<>();
for (int i = 1; i <= 6; i++) {
    solution.add(i);
}
Collections.shuffle(solution);

这是另一种洗牌的方法

public List<Integer> shuffleArray(List<Integer> a) {
    List<Integer> b = new ArrayList<Integer>();
    while (a.size() != 0) {
        int arrayIndex = (int) (Math.random() * (a.size()));
        b.add(a.get(arrayIndex));
        a.remove(a.get(arrayIndex));
    }
    return b;
}

从原始列表中选择一个随机数,并将其保存在另一个列表中。然后从原始列表中删除该数字。原始列表的大小将继续减小1,直到所有元素都移动到新列表中。

使用随机类

  public static void randomizeArray(int[] arr) {

      Random rGenerator = new Random(); // Create an instance of the random class 
      for (int i =0; i< arr.length;i++ ) {
          //Swap the positions...

          int rPosition = rGenerator.nextInt(arr.length); // Generates an integer within the range (Any number from 0 - arr.length)
          int temp = arr[i]; // variable temp saves the value of the current array index;
          arr[i] = arr[rPosition];  // array at the current position (i) get the value of the random generated 
          arr[rPosition] = temp; // the array at the position of random generated gets the value of temp

      }

      for(int i = 0; i<arr.length; i++) {
          System.out.print(arr[i]); //Prints out the array
      } 

  }