我需要随机洗牌以下数组:

int[] solutionArray = {1, 2, 3, 4, 5, 6, 6, 5, 4, 3, 2, 1};

有什么函数可以做到吗?


当前回答

public class ShuffleArray {
public static void shuffleArray(int[] a) {
    int n = a.length;
    Random random = new Random();
    random.nextInt();
    for (int i = 0; i < n; i++) {
        int change = i + random.nextInt(n - i);
        swap(a, i, change);
    }
}

private static void swap(int[] a, int i, int change) {
    int helper = a[i];
    a[i] = a[change];
    a[change] = helper;
}

public static void main(String[] args) {
    int[] a = new int[] { 1, 2, 3, 4, 5, 6, 6, 5, 4, 3, 2, 1 };
    shuffleArray(a);
    for (int i : a) {
        System.out.println(i);
    }
}
}

其他回答

你有几个选择。当涉及到洗牌时,列表与数组有点不同。

如下所示,数组比列表快,而基元数组比对象数组快。

样品时间

List<Integer> Shuffle: 43133ns
    Integer[] Shuffle: 31884ns
        int[] Shuffle: 25377ns

下面是shuffle的三种不同实现。您应该只使用集合。如果处理的是集合,则Shuffle。没有必要为了排序而将数组包装到一个集合中。下面的方法实现起来非常简单。

ShuffleUtil Class

import java.lang.reflect.Array;
import java.util.*;

public class ShuffleUtil<T> {
    private static final int[] EMPTY_INT_ARRAY = new int[0];
    private static final int SHUFFLE_THRESHOLD = 5;

    private static Random rand;

主要方法

    public static void main(String[] args) {
        List<Integer> list = null;
        Integer[] arr = null;
        int[] iarr = null;

        long start = 0;
        int cycles = 1000;
        int n = 1000;

        // Shuffle List<Integer>
        start = System.nanoTime();
        list = range(n);
        for (int i = 0; i < cycles; i++) {
            ShuffleUtil.shuffle(list);
        }
        System.out.printf("%22s: %dns%n", "List<Integer> Shuffle", (System.nanoTime() - start) / cycles);

        // Shuffle Integer[]
        start = System.nanoTime();
        arr = toArray(list);
        for (int i = 0; i < cycles; i++) {
            ShuffleUtil.shuffle(arr);
        }
        System.out.printf("%22s: %dns%n", "Integer[] Shuffle", (System.nanoTime() - start) / cycles);

        // Shuffle int[]
        start = System.nanoTime();
        iarr = toPrimitive(arr);
        for (int i = 0; i < cycles; i++) {
            ShuffleUtil.shuffle(iarr);
        }
        System.out.printf("%22s: %dns%n", "int[] Shuffle", (System.nanoTime() - start) / cycles);
    }

变换通用列表

    // ================================================================
    // Shuffle List<T> (java.lang.Collections)
    // ================================================================
    @SuppressWarnings("unchecked")
    public static <T> void shuffle(List<T> list) {
        if (rand == null) {
            rand = new Random();
        }
        int size = list.size();
        if (size < SHUFFLE_THRESHOLD || list instanceof RandomAccess) {
            for (int i = size; i > 1; i--) {
                swap(list, i - 1, rand.nextInt(i));
            }
        } else {
            Object arr[] = list.toArray();

            for (int i = size; i > 1; i--) {
                swap(arr, i - 1, rand.nextInt(i));
            }

            ListIterator<T> it = list.listIterator();
            int i = 0;

            while (it.hasNext()) {
                it.next();
                it.set((T) arr[i++]);
            }
        }
    }

    public static <T> void swap(List<T> list, int i, int j) {
        final List<T> l = list;
        l.set(i, l.set(j, l.get(i)));
    }

    public static <T> List<T> shuffled(List<T> list) {
        List<T> copy = copyList(list);
        shuffle(copy);
        return copy;
    }

变换泛型数组

    // ================================================================
    // Shuffle T[]
    // ================================================================
    public static <T> void shuffle(T[] arr) {
        if (rand == null) {
            rand = new Random();
        }

        for (int i = arr.length - 1; i > 0; i--) {
            swap(arr, i, rand.nextInt(i + 1));
        }
    }

    public static <T> void swap(T[] arr, int i, int j) {
        T tmp = arr[i];
        arr[i] = arr[j];
        arr[j] = tmp;
    }

    public static <T> T[] shuffled(T[] arr) {
        T[] copy = Arrays.copyOf(arr, arr.length);
        shuffle(copy);
        return copy;
    }

打乱原语数组

    // ================================================================
    // Shuffle int[]
    // ================================================================
    public static <T> void shuffle(int[] arr) {
        if (rand == null) {
            rand = new Random();
        }

        for (int i = arr.length - 1; i > 0; i--) {
            swap(arr, i, rand.nextInt(i + 1));
        }
    }

    public static <T> void swap(int[] arr, int i, int j) {
        int tmp = arr[i];
        arr[i] = arr[j];
        arr[j] = tmp;
    }

    public static int[] shuffled(int[] arr) {
        int[] copy = Arrays.copyOf(arr, arr.length);
        shuffle(copy);
        return copy;
    }

实用方法

简单的实用工具方法复制和转换数组到列表,反之亦然。

    // ================================================================
    // Utility methods
    // ================================================================
    protected static <T> List<T> copyList(List<T> list) {
        List<T> copy = new ArrayList<T>(list.size());
        for (T item : list) {
            copy.add(item);
        }
        return copy;
    }

    protected static int[] toPrimitive(Integer[] array) {
        if (array == null) {
            return null;
        } else if (array.length == 0) {
            return EMPTY_INT_ARRAY;
        }
        final int[] result = new int[array.length];
        for (int i = 0; i < array.length; i++) {
            result[i] = array[i].intValue();
        }
        return result;
    }

    protected static Integer[] toArray(List<Integer> list) {
        return toArray(list, Integer.class);
    }

    protected static <T> T[] toArray(List<T> list, Class<T> clazz) {
        @SuppressWarnings("unchecked")
        final T[] arr = list.toArray((T[]) Array.newInstance(clazz, list.size()));
        return arr;
    }

范围类

生成一个值范围,类似于Python的range函数。

    // ================================================================
    // Range class for generating a range of values.
    // ================================================================
    protected static List<Integer> range(int n) {
        return toList(new Range(n), new ArrayList<Integer>());
    }

    protected static <T> List<T> toList(Iterable<T> iterable) {
        return toList(iterable, new ArrayList<T>());
    }

    protected static <T> List<T> toList(Iterable<T> iterable, List<T> destination) {
        addAll(destination, iterable.iterator());

        return destination;
    }

    protected static <T> void addAll(Collection<T> collection, Iterator<T> iterator) {
        while (iterator.hasNext()) {
            collection.add(iterator.next());
        }
    }

    private static class Range implements Iterable<Integer> {
        private int start;
        private int stop;
        private int step;

        private Range(int n) {
            this(0, n, 1);
        }

        private Range(int start, int stop) {
            this(start, stop, 1);
        }

        private Range(int start, int stop, int step) {
            this.start = start;
            this.stop = stop;
            this.step = step;
        }

        @Override
        public Iterator<Integer> iterator() {
            final int min = start;
            final int max = stop / step;

            return new Iterator<Integer>() {
                private int current = min;

                @Override
                public boolean hasNext() {
                    return current < max;
                }

                @Override
                public Integer next() {
                    if (hasNext()) {
                        return current++ * step;
                    } else {
                        throw new NoSuchElementException("Range reached the end");
                    }
                }

                @Override
                public void remove() {
                    throw new UnsupportedOperationException("Can't remove values from a Range");
                }
            };
        }
    }
}
Random rnd = new Random();
for (int i = ar.length - 1; i > 0; i--)
{
  int index = rnd.nextInt(i + 1);
  // Simple swap
  int a = ar[index];
  ar[index] = ar[i];
  ar[i] = a;
}

顺便说一下,我注意到这段代码返回了一个ar.length - 1个数的元素,所以如果你的数组有5个元素,新的打乱的数组将有4个元素。这是因为for循环说i>0。如果你改变为i>=0,你得到所有的元素洗牌。

我在一些答案中看到了一些遗漏的信息,所以我决定添加一个新的。

Java集合数组。asList接受类型为T的var-arg (T…)。如果传递一个基元数组(int array), asList方法将推断并生成一个List<int[]>,这是一个单元素列表(其中一个元素是基元数组)。如果你洗牌这个元素列表,它不会改变任何东西。

首先,你需要将原始数组转换为Wrapper对象数组。为此,您可以使用ArrayUtils。apache.commons.lang中的一个对象方法。然后将生成的数组传递给一个List,最后洗牌。

  int[] intArr = {1,2,3};
  List<Integer> integerList = Arrays.asList(ArrayUtils.toObject(array));
  Collections.shuffle(integerList);
  //now! elements in integerList are shuffled!

最简单的解决方案,这种随机洗牌数组。

String location[] = {"delhi","banglore","mathura","lucknow","chandigarh","mumbai"};
int index;
String temp;
Random random = new Random();
for(int i=1;i<location.length;i++)
{
    index = random.nextInt(i+1);
    temp = location[index];
    location[index] = location[i];
    location[i] = temp;
    System.out.println("Location Based On Random Values :"+location[i]);
}

这是knuth shuffle算法。

public class Knuth { 

    // this class should not be instantiated
    private Knuth() { }

    /**
     * Rearranges an array of objects in uniformly random order
     * (under the assumption that <tt>Math.random()</tt> generates independent
     * and uniformly distributed numbers between 0 and 1).
     * @param a the array to be shuffled
     */
    public static void shuffle(Object[] a) {
        int n = a.length;
        for (int i = 0; i < n; i++) {
            // choose index uniformly in [i, n-1]
            int r = i + (int) (Math.random() * (n - i));
            Object swap = a[r];
            a[r] = a[i];
            a[i] = swap;
        }
    }

    /**
     * Reads in a sequence of strings from standard input, shuffles
     * them, and prints out the results.
     */
    public static void main(String[] args) {

        // read in the data
        String[] a = StdIn.readAllStrings();

        // shuffle the array
        Knuth.shuffle(a);

        // print results.
        for (int i = 0; i < a.length; i++)
            StdOut.println(a[i]);
    }
}