var range = getDates(new Date(), new Date().addDays(7));
我想“范围”是一个日期对象的数组,一个为两个日期之间的每一天。
诀窍在于它还应该处理月份和年份的边界。
var range = getDates(new Date(), new Date().addDays(7));
我想“范围”是一个日期对象的数组,一个为两个日期之间的每一天。
诀窍在于它还应该处理月份和年份的边界。
当前回答
功能:
var dates = [],
currentDate = startDate,
addDays = function(days) {
var date = new Date(this.valueOf());
date.setDate(date.getDate() + days);
return date;
};
while (currentDate <= endDate) {
dates.push(currentDate);
currentDate = addDays.call(currentDate, 1);
}
return dates;
};
用法:
var dates = getDatesRange(new Date(2019,01,01), new Date(2019,01,25));
dates.forEach(function(date) {
console.log(date);
});
希望对你有所帮助
其他回答
我使用moment.js和Twix.js,它们为日期和时间操作提供了非常好的支持
var itr = moment.twix(new Date('2012-01-15'),new Date('2012-01-20')).iterate("days");
var range=[];
while(itr.hasNext()){
range.push(itr.next().toDate())
}
console.log(range);
我在http://jsfiddle.net/Lkzg1bxb/上运行这个程序
我喜欢这样做
// hours * minutes * seconds * milliseconds
const DAY_IN_MS = 24 * 60 * 60 * 1000
/**
* Get range of dates
* @param {Date} startDate
* @param {Number} numOfDays
* @returns {array}
*/
const dateRange = (startDate, numOfDays) => {
const startDateMs = startDate.getTime()
// get array of days and map it to Date object
return [...Array(numOfDays).keys()].map(i => new Date(startDateMs + i * DAY_IN_MS))
}
不是最短的,而是简单的,不可变的,没有依赖关系
function datesArray(start, end) {
let result = [], current = new Date(start);
while (current <= end)
result.push(current) && (current = new Date(current)) && current.setDate(current.getDate() + 1);
return result;
}
使用
函数datesArray(start, end) { let result = [], current = new Date(start); While (current <= end) result.push(current) && (current = new Date(current)) && current. setdate (current. getdate () + 1); 返回结果; } / /使用 const test = datesArray( 新的日期(“2020-02-26”), 新日期(“2020-03-05”) ); 对于(设I = 0;I < test.length;I ++) { console.log ( 测试[我].toISOString () .slice (0, 10) ); }
这可能会帮助到一些人,
您可以从中获得行输出,并根据需要格式化row_date对象。
var from_date = '2016-01-01';
var to_date = '2016-02-20';
var dates = getDates(from_date, to_date);
console.log(dates);
function getDates(from_date, to_date) {
var current_date = new Date(from_date);
var end_date = new Date(to_date);
var getTimeDiff = Math.abs(current_date.getTime() - end_date.getTime());
var date_range = Math.ceil(getTimeDiff / (1000 * 3600 * 24)) + 1 ;
var weekday = ["SUN", "MON", "TUE", "WED", "THU", "FRI", "SAT"];
var months = ["JAN", "FEB", "MAR", "APR", "MAY", "JUN", "JUL", "AUG", "SEP", "OCT", "NOV", "DEC"];
var dates = new Array();
for (var i = 0; i <= date_range; i++) {
var getDate, getMonth = '';
if(current_date.getDate() < 10) { getDate = ('0'+ current_date.getDate());}
else{getDate = current_date.getDate();}
if(current_date.getMonth() < 9) { getMonth = ('0'+ (current_date.getMonth()+1));}
else{getMonth = current_date.getMonth();}
var row_date = {day: getDate, month: getMonth, year: current_date.getFullYear()};
var fmt_date = {weekDay: weekday[current_date.getDay()], date: getDate, month: months[current_date.getMonth()]};
var is_weekend = false;
if (current_date.getDay() == 0 || current_date.getDay() == 6) {
is_weekend = true;
}
dates.push({row_date: row_date, fmt_date: fmt_date, is_weekend: is_weekend});
current_date.setDate(current_date.getDate() + 1);
}
return dates;
}
https://gist.github.com/pranid/3c78f36253cbbc6a41a859c5d718f362.js
你可以使用momentJS轻松做到这一点
给你的依赖增加时间
npm i moment
然后把它导入你的文件
var moment = require("moment");
然后使用下面的代码获取两个日期之间的所有日期的列表
let dates = [];
let currDate = moment.utc(new Date("06/30/2019")).startOf("day");
let lastDate = moment.utc(new Date("07/30/2019")).startOf("day");
do {
dates.push(currDate.clone().toDate());
} while (currDate.add(1, "days").diff(lastDate) < 0);
dates.push(currDate.clone().toDate());
console.log(dates);